Research Article

A Numerical Algorithm for Solving a Four-Point Nonlinear Fractional Integro-Differential Equations

Table 1

Absolute errors for Example 5.1.

𝑥 True solution DM [8] VIM [9] RKM ( 𝑢 5 1 1 ) RKM ( 𝑢 5 1 0 1 )

0 0.05566 5 . 6 1 6 8 9 𝐸 5 1 . 4 8 3 6 6 𝐸 4 2 . 1 6 9 9 3 𝐸 5 2 . 1 1 5 5 2 𝐸 7
0.1 0.19798 5 . 4 7 4 2 1 𝐸 5 1 . 4 6 2 4 6 𝐸 4 1 . 9 2 4 6 3 𝐸 5 1 . 9 0 5 9 1 𝐸 7
0.2 0.39473 5 . 4 3 9 7 3 𝐸 5 1 . 4 9 2 4 4 𝐸 4 1 . 7 0 8 1 7 𝐸 5 1 . 5 9 7 8 8 𝐸 7
0.3 0.60560 5 . 4 7 5 7 9 𝐸 5 1 . 5 5 8 0 7 𝐸 4 1 . 4 9 0 4 6 𝐸 5 1 . 3 6 9 3 3 𝐸 7
0.4 0.77891 5 . 5 6 6 2 4 𝐸 5 1 . 6 5 4 4 9 𝐸 4 1 . 2 6 0 3 1 𝐸 5 1 . 1 4 1 2 8 𝐸 7
0.5 0.83516 5 . 6 8 9 7 6 𝐸 5 1 . 7 8 2 2 5 𝐸 4 1 . 0 2 4 7 7 𝐸 5 9 . 2 5 5 6 1 𝐸 8
0.6 0.70036 5 . 8 0 3 8 9 𝐸 5 1 . 9 4 5 5 4 𝐸 4 7 . 8 8 4 6 6 𝐸 6 6 . 8 4 8 2 1 𝐸 8
0.7 0.50144 5 . 8 2 4 4 1 𝐸 5 2 . 1 5 1 8 𝐸 4 5 . 6 5 5 1 5 𝐸 6 4 . 8 2 4 6 8 𝐸 8
0.8 0.29175 5 . 5 9 6 8 𝐸 5 2 . 4 1 1 8 3 𝐸 4 3 . 5 4 4 8 1 𝐸 6 2 . 9 5 3 6 𝐸 8
0.9 0.11797 4 . 8 5 7 6 4 𝐸 5 2 . 7 4 0 6 2 𝐸 4 1 . 5 0 5 7 2 𝐸 6 9 . 8 4 7 4 𝐸 9
1.0 0.01485 3 . 1 8 3 9 7 𝐸 5 3 . 1 5 8 8 1 𝐸 4 9 . 7 9 0 7 8 𝐸 7 1 . 3 8 9 6 𝐸 8