Research Article | Open Access

Ezzat G. Bakhoum, "Gaussian Curvature in Propagation Problems in Physics and Engineering", *Mathematical Problems in Engineering*, vol. 2012, Article ID 371890, 10 pages, 2012. https://doi.org/10.1155/2012/371890

# Gaussian Curvature in Propagation Problems in Physics and Engineering

**Academic Editor:**Cristian Toma

#### Abstract

The computation of the Gaussian curvature of a surface is a requirement in many propagation problems in physics and engineering. A formula is developed for the calculation of the Gaussian curvature by knowledge of two close geodesics on the surface, or alternatively from the projection (i.e., image) of such geodesics. The formula will be very useful for problems in general relativity, civil engineering, and robotic navigation.

#### 1. Introduction

In many propagation problems in physics and engineering, it becomes necessary to compute the Gaussian curvature of a two-dimensional surface. In physics, this becomes necessary in the applications of general relativity, where it is sometimes desired to calculate the Gaussian curvature at a point in space from the observed geodesic paths of planets or light rays [1, 2]. In engineering, engineers who are involved in the design of structures such as geodesic domes frequently require a practical formula for computing the Gaussian curvature, where relations exist between the Gaussian curvature at any point on the surface of the structure and the stability of such a structure [3]. In certain other engineering applications, such as computer vision and robotic navigation, engineers sometimes find themselves facing the complicated problem of having to compute the Gaussian curvature of a surface in order to calculate 3-dimensional depth data (or range) [4–6].

From the basic principles of differential geometry, the Gaussian curvature at any point of a two-dimensional surface is given by where and are the maximum and the minimum normal curvatures [6]. Unfortunately, in many practical situations, and are simply unknown. In the following section, we will derive a formula for computing the Gaussian curvature at any point on a surface by knowledge of two close geodesics on the surface, or alternatively from the projection (i.e., image) of such geodesics (this is very important in applications such as general relativity and robotic navigation, where no direct knowledge of the geodesics exists, but only an image of the geodesics is available). A simple test of the formula is given in Section 3 (the test shows that , as computed from the formula, must vanish in an Euclidean 2-space). In Section 4, it is proven that the Gaussian curvature is a projective invariant and hence can be calculated from any projected image of two geodesics.

#### 2. Calculation of the Gaussian Curvature from Geodesic Deviation

It is well known that any general 2-dimensional surface is topologically equivalent at any given point to a surface of revolution [6]. Hence, two close geodesics on the surface, when considered only within a small surface patch, can be treated as embedded in a surface of revolution. Such curves, however, will not necessarily be geodesics in the surface of revolution. Consider now a surface of revolution, where the smooth curve is a general curve that is embedded in the surface (Figure 1). is a copy of that is obtained by rotating through a small angle .

is a position vector, defined over a circular ring passing by . Let us select two parameters and , such that varies as we travel along the curve , but is constant, and varies as we pass from one curve to another, but is constant. Obviously, where is the rotation angle of the axis from to . Given such parameters on any surface in space, it can be shown that [7] where is the unit tangent vector to the curve, is the mixed curvature tensor [7], and the symbol is the covariant derivative operator [6, 7]. If the curve was a geodesic in the surface, we must have had [6, 7] since the covariant derivative of the unit tangent vector to a geodesic vanishes along the curve [6, 7]. Since is a general curve, however, then will be the components of a vector of finite length, normal to the vector [6]. On the other hand, due to circular symmetry in a surface of revolution, the vector , clearly, is parallel transported [6, 7] along a circular ring in the surface. Hence, we must conclude that at any point on . Further, given the parameters and , it can be shown that [7] for any 2-dimensional surface. From (2.4) and (2.5), (2.2) is rewritten as where , , . Moreover, it has be shown that [7] for a smooth 2-dimensional manifold, where is the Gaussian curvature, is the Kronecker delta, and are the components of the metric tensor at any point on the surface. Substituting from (2.7) into (2.6) and carrying out the summation, we obtain where we have used the identity Equation (2.8) is analogous to the equation of geodesic deviation [6, 7]. Once again, if was a geodesic in the surface, we must have had an orthogonality condition and (2.8) would have reduced to the well-known equation of deviation of two geodesics in a Riemannian 2-manifold. Equation (2.8), in its given form, will not allow the computation of the Gaussian curvature , since the metric tensor components, as well as all the covariant derivatives on the surface, are unknown. However, (2.8) can be further reduced as follows: for an infinitesimal rotation , Thus, Now, where , are unit tangent vectors at and , respectively, separated by a rotation (Figure 2).

Given that, for any vector on the surface [7],
where is a Christoffel symbol of the second kind, we can always select coordinates such that Christoffel symbols vanish at the origin [6, 7] (e.g., we can select coordinates on the surface, at the location of the vector ). Then, the vector is generally very small in the vicinity of the origin, and can be neglected (i.e., a linear approximation of is assumed here. This approximation will be further justified in the following discussion and in Section 3). Therefore, let
Further, let us define the * deviation angle*, , as the angle between the two unit tangent vectors , , at any point along the curve . Generally, the angle between two curves is given by [7]
but since is the length of the curve, and having , we can write
Hence, from (2.15) and (2.17),
We also see that
Now, consider (2.8) and the summation
and let
denote the Euclidean norm of the vector ; thus,
Substitution from (2.18), (2.21), and (2.23) into (2.20) gives
To evaluate the last term in (2.24), we rewrite (2.8) as
Now, from (2.22) and (2.25), we have
Each of the components in the last term of (2.26) vanishes identically. To prove this, we evaluate each of the components for each of the curves, and , by substitution from (2.6). We have
A straightforward summation shows that the right-hand side of (2.27) vanishes. We therefore conclude that is in the direction normal to the curve. In plus is in the direction of the tangent to the curve.

Finally, substitution from (2.19) into the first term of (2.26) gives or and hence (2.24) is further reduced to where is the Gaussian curvature of the surface at the location of the vector . In the following section, we prove that the Gaussian curvature given by (2.30) must vanish in an Euclidean 2-space. In Section 4, it is further proven that is a projective invariant and hence can be calculated from any projected image of the curves and .

#### 3. Investigation of the Behavior of in an Euclidean Space

Here, we illustrate by a simple example that the Gaussian curvature , given by (2.30), must vanish in an Euclidean 2-space.

Consider a right circular cone, shown in Figure 3.

is the Euclidean norm of the position vector, and is the rotation angle (as discussed in the above text).

From the Figure 3, we see that where is the length of the generator. Hence, Thus For an infinitesimal rotation, is expressed by the first two terms of its power series, that is, and thus, (3.3) is written as Furthermore, we can see that where is the deviation angle, or From (3.5) and (3.7), we have By comparison of (2.30) and (3.8), we immediately see that must vanish in an Euclidean 2-space. This proves the correctness of (2.30).

#### 4. Proof That the Gaussian Curvature Is a Projective Invariant

Now, we will reach our final goal by demonstrating that , formulated by (2.30), can be measured directly in the image plane.

We rewrite (2.8) as From (2.27), we saw that is a vector in the direction normal to the curve. Now, by using (2.9) and taking the summation it is easy to see that the denominator in (4.1) is also a vector in the direction normal to the curve.

If we now let where , are scalars, and is a vector in the direction normal to the curve, then Now, consider the orthographic projection of the two vectors in (4.3), written as where is a transformation Jacobian between a coordinate system on the surface and a coordinate system in the image plane.

If measured in the image plane, the Gaussian curvature is now given by as we can easily see from (4.5).

Hence, The Gaussian curvature is therefore a projective invariant. It should be noted that, while orthographic projection is assumed, the image plane may be placed in any arbitrary position with respect to the curve , and for all such positions, the Gaussian curvature holds the same numerical value. Equation (2.30) should be used in the image plane to obtain a correct measurement of .

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#### Copyright

Copyright © 2012 Ezzat G. Bakhoum. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.