Diagonal Block Method for Solving Two-Point Boundary Value Problems with Robin Boundary Conditions

Table 4

Comparison of the numerical result for solving Problem 4.

	Error at			Error at
	2PDD4	2PDAM4	DAM4	2PDD4	2PDAM4	DAM4
0.00	0.00e+00	2.07e-06	1.18e-05	0.00e+00	0.00e+00	0.00e+00
0.10	5.30e-07	1.77e-06	1.25e-05	1.27e-11	2.41e-11	9.41e-11
0.20	9.48e-07	1.62e-06	1.36e-05	1.20e-11	8.26e-11	3.66e-10
0.30	1.66e-06	2.03e-06	1.46e-05	1.01e-11	1.71e-10	7.57e-10
0.40	1.33e-06	2.36e-06	1.47e-05	7.54e-12	2.79e-10	1.23e-09
0.50	1.53e-06	2.39e-06	1.44e-05	4.68e-12	4.00e-10	1.75e-09
0.60	1.34e-06	2.39e-06	1.37e-05	1.61e-12	5.33e-10	2.33e-09
0.70	1.38e-06	2.29e-06	1.29e-05	1.62e-12	6.74e-10	2.93e-09
0.80	1.25e-06	2.18e-06	1.20e-05	4.97e-12	8.23e-10	3.58e-09
0.90	1.23e-06	2.03e-06	1.10e-05	8.42e-12	9.80e-10	4.25e-09
1.00	1.14e-06	1.88e-06	1.01e-05	1.20e-11	1.14e-09	4.96e-09
AVE	1.23e-06	2.30e-06	1.41e-05	7.55e-12	4.59e-10	2.00e-09
TS	6	6	10	51	51	100
FCN	32	48	32	114	212	114
ITN	1	4	4	1	1	1
TIME	0.0030	0.0150	0.0150	0.0050	0.0310	0.0460