Heat transfer equation (

64) solution for 3D case (crystal sizes 0.001 × 0.001 × 0.001 mm, initial and boundary temperatures equal to 100 K). (a) The source is proportional to the 4th order of temperature; const = 1.00 J/(cm

^{3}·s·K

^{4}); heat capacity and heat conductivity are constant and equal to 11.5 J/(K·mol) and 27.5 W/(m·K), respectively; (b) the source is proportional to the 4th order of temperature; const = 1.00 J/(cm

^{3}·s·K

^{4}); (c) the source is proportional to the 2nd order of temperature; const = 1.00 J/(cm

^{3}·s·K

^{2}); (d) the source is proportional to the 2nd order of temperature; const = 0.10 J/(cm

^{3}·s·K

^{2}). Note: in the cases (b)–(d) the heat capacity and heat conductivity were determined by (

80) and (

81), respectively.