The Scientific World Journal

Volume 2014, Article ID 756298, 7 pages

http://dx.doi.org/10.1155/2014/756298

## Partial Rectangular Metric Spaces and Fixed Point Theorems

Department of Applied Mathematics, Shri Vaishnav Institute of Technology & Science Gram Baroli, Sanwer Road, Indore 453331, India

Received 2 August 2013; Accepted 11 November 2013; Published 29 January 2014

Academic Editors: Y. Cheng and Y. C. Shiah

Copyright © 2014 Satish Shukla. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

#### Abstract

The purpose of this paper is to introduce the concept of partial rectangular metric spaces as a generalization of rectangular metric and partial metric spaces. Some properties of partial rectangular metric spaces and some fixed point results for quasitype contraction in partial rectangular metric spaces are proved. Some examples are given to illustrate the observed results.

#### 1. Introduction

In 1906, the famous French mathematician Fréchet [1] introduced the concept of a metric space. After this, several mathematicians generalize the concept of metric space in different directions. Branciari [2] introduced a class of generalized (rectangular) metric spaces by replacing triangular inequality by similar one which involves four or more points instead of three and improved Banach contraction principle. On the other hand, Matthews [3] introduced the notion of partial metric space as a part of the study of denotational semantics of dataflow network. In this space, the usual metric is replaced by partial metric with an interesting property that the self-distance of any point of space may not be zero. Further, Matthews showed that the Banach contraction principle is valid in partial metric space and can be applied in program verification. Ćirić [4] introduced the quasicontractions in metric spaces and generalized the Banach contraction principle and several other fixed point theorems in metric spaces.

In this paper, we generalize the concept of rectangular metric space and extend the concept of partial metric space by introducing the partial rectangular metric space. A fixed point theorem for quasitype contraction is also proved in the partial rectangular metric space which generalizes several known results in metric, partial metric, and rectangular metric spaces. Results are illustrated by some examples.

First, we recall some definitions from partial metric and rectangular metric spaces (see [2, 3]).

*Definition 1. *A partial metric on a nonempty set is a mapping such that, for all ,(P1);(P2) if and only if ;(P3);(P4);(P5).A partial metric space is a pair such that is a nonempty set and is a partial metric on .

*Definition 2. *Let be a nonempty set and let be a mapping such that(R1), for all and , if and only if ;(R2), for all ;(R3), for all and for all distinct points (rectangular property).Then, is called a rectangular metric on , and is called a rectangular metric space. A sequence in is called convergent and converges to , if, for every , there exists such that for all . Sequence is called a Cauchy sequence if, for every , there exists such that , for all . A rectangular metric space is called complete, if every Cauchy sequence in converges in .

#### 2. Partial Rectangular Metric Spaces

In this section, we define partial rectangular metric spaces and prove some properties of partial rectangular metric spaces.

*Definition 3. *Let be a nonempty set and let be a mapping such that(1), for all ;(2) if and only if , for all ;(3), for all ;(4), for all ;(5), for all and for all distinct points .Then, is called a partial rectangular metric on and the pair is called a partial rectangular metric space.

*Remark 4. *In a partial rectangular metric space , if and , then but the converse may not be true.

*Remark 5. *It is clear that every rectangular metric space is a partial rectangular metric space with zero self-distance. However, the converse of this fact need not hold.

*Example 6. *Let , and define a mapping by
Then, is a partial rectangular metric space, but it is not a rectangular metric space, because , for all . Also, is not a partial metric space because it lacks the property (P5). Indeed,

Next proposition shows that every partial rectangular metric space induces a rectangular metric space.

Proposition 7. *For each partial rectangular metric space , the pair is a rectangular metric space, where
*

*Proof. *By definition of and , it is easy to verify that satisfies the properties (R1) and (R2). For (R3), let , where and are distinct and ; then we have
Thus, is a rectangular metric space.

*Here, is called the induced rectangular metric space, and is the induced rectangular metric. In further discussion until specified, will represent induced rectangular metric space.*

*Now, we show that a rectangular metric space with some restriction on it always induces a partial rectangular metric space.*

*Proposition 8. Let be a rectangular metric space and there exists such that , for all distinct . Then, the pair is a partial rectangular metric space, where
Also, the rectangular metric induced by is the rectangular metric .*

*Proof. *The properties () and () follow by the definition of . For (), note that , for all ; therefore, if and , we have , which implies that ; that is, .

By the choice of , the property () follows immediately. For (), let , , . Then, by definition of , we have
Thus, is a partial rectangular metric space. Now, by the definition, it is easy to verify that is the rectangular metric induced by .

*Example 9. *Let and define by
Then, is a rectangular metric space. Note that for all distinct and so defined by
is a partial rectangular metric on , is a partial rectangular metric space, and is the rectangular metric induced by .

*The proof of following proposition is straightforward and, by using it, one can obtain some more examples of partial rectangular metric space.*

*Proposition 10. For any rectangular metric space and constant , the pair is a partial rectangular metric space, where
*

*Now, we define the convergence of a sequence and Cauchy sequence in partial rectangular metric spaces.*

*Definition 11. *Let be a partial rectangular metric space, a sequence in , and . Then,(i)the sequence is said to be convergent and converges to , if ;(ii)the sequence is said to be Cauchy in , if exists and is finite;(iii) is said to be a complete partial rectangular metric space, if, for every Cauchy sequence in , there exists such that

*Note that in a partial rectangular metric space the limit of convergent sequence may not be unique.*

*Example 12. *Let , be a constant and define by
Then, is a partial rectangular metric space. Consider the sequence in , where . Then, and . Therefore, has two limits, namely, and .

*Lemma 13. Let be a partial rectangular metric space and let be a sequence in . Then, the sequence converges in and converges to ; that is, , if and only if .*

*Proof. *Note that
which proves the result.

*Lemma 14. Let be a partial rectangular metric space and let be a sequence in . Then, the sequence is a Cauchy sequence in if and only if it is a Cauchy sequence in .*

*Proof. *Let be a Cauchy sequence in ; that is,
Note that , for all ; therefore, the sequence is a Cauchy sequence in and so we have . Therefore, it follows from (13) that .

Conversely, if is a Cauchy sequence in , that is, , then again and by definition .

*The proof of the following lemma follows from Lemmas 13 and 14.*

*Lemma 15. A partial rectangular metric space is complete, if and only if its induced rectangular metric space is complete.*

*3. Fixed Point Theorems*

*3. Fixed Point Theorems*

*In this section, some fixed point theorems in partial rectangular metric spaces are proved.*

*Let be a partial rectangular metric space and let be a mapping. For , we denote the diameter of by and
Note that, apart from rectangular metric space, if , then need not be zero, but .*

*For each , we define the orbit of by
*

*Definition 16. *Let be a complete partial rectangular metric space and let be a mapping. Then, is called a quasicontraction on with constant , if it satisfies the following property:
for all , where .

*Lemma 17. Let be a partial rectangular metric space, let be a quasicontraction on with constant , and let be a positive integer. Then, for each and all , one has . Furthermore there exists a positive integer such that and .*

*Proof. *Suppose then and so, by (16), we have
As , we have and so, by the definition of orbit of and the diameter of a set, we must have , where .

*The next lemma shows that the orbit of a quasicontraction is necessarily bounded.*

*Lemma 18. Suppose that all the conditions of Lemma 17 are satisfied; then
holds, for all .*

*Proof. *Let be arbitrary. Note that is a nondecreasing sequence of real numbers, so
Therefore, it is sufficient to show that
Now, (20) holds trivially, if . If , then from () and (16), we have
Since , we must have . Also, since , for all , therefore (20) holds for .

Suppose , then, by Lemma 17, we have , where . If or , we have finished. Suppose . If or or , then we have and (20) holds. Similarly, if , then (20) holds. Therefore, we can assume that , , , all are distinct elements of . As , therefore, from (), (16), (21), and Lemma 17, we obtain
Again, by Lemma 17, for some , we have ; therefore, it follows from the above inequality that
that is,
and the result follows.

*In the next theorem, existence and uniqueness of fixed point of quasicontraction in complete partial rectangular metric spaces are proved.*

*Theorem 19. Let be a complete partial rectangular metric space and let be a quasicontraction on with constant . Then, has a unique fixed point and .*

*Proof. *Let us first show that, if fixed point of exists, then it is unique. Let be two distinct fixed points of ; that is, , and . Then, from (16), we have
This contradiction shows that ; that is, . Thus, if fixed point of exists, then it is unique. Further, if is a fixed point of and , then, from (16), we have
Again, this contradiction shows that . So, if is a fixed point of , then .

Now, we prove existence of fixed point of . For arbitrary , we will show that the iterative sequence is a Cauchy sequence. Let with . Then, using Lemma 17, we have
Again, by Lemma 17, there exists such that ; therefore, using Lemma 17, it follows from the above inequality that
By repetition of this process, we obtain
which together with Lemma 18 yields
As , it follows from (30) that
Therefore, is a Cauchy sequence. By completeness of space , there exists such that
We will show that is the fixed point of . Suppose . Without loss of generality, we can assume that , for all , also, there exists such that , for all . Therefore, it follows from () that
Using (16), we have
For sufficiently large , from (32) and the above inequality, we have
If , then, from (32), (33), and (35), we obtain . If , then, for sufficiently large , we have
Again from (32), (33), (35), and (36), we obtain . Therefore, we must have . Thus, is the unique fixed point of .

*We illustrate the above result by the following example, which additionally shows that a quasicontraction in a partial rectangular metric space may not be a quasicontraction in the induced rectangular metric space and, therefore, it shows that our generalization is proper.*

*Example 20. *Let and define by
Then, is a complete partial rectangular metric space. Since, for all , , therefore is not a rectangular metric space. Also, is not a partial metric space because it lacks the property (P5). Indeed,
Define a mapping by
Then, by a careful calculation, one can see that is a quasicontraction with constant . All the conditions of Theorem 19 are satisfied and has a unique fixed point . Note that the rectangular metric induced by is given by
Now, it is easy to see that is not a quasicontraction with respect to . Indeed, for , , we have and , , , , and . Therefore, there exists no such that
for all . Thus, is not a quasicontraction in the induced rectangular metric space.

*Remark 21. *Note that, in the above example, the mapping is a Banach contraction in the partial rectangular metric space ; that is, , for all with , while it is not even a quasicontraction in the induced rectangular metric space . Also is not a partial metric space; therefore, the results of Branciari [2] and Matthews [3] are not applicable. Thus, this example also shows that the class of Banach contractions in a partial rectangular metric space is more wider than that in rectangular metric spaces.

*The following corollaries generalize the Banach, Kannan, Reich, Chatterjea, and Hardy-Rogers fixed point results (for details, see [5]) in partial rectangular metric spaces.*

*Corollary 22 (Banach type). Let be a complete partial rectangular metric space and let be a mapping. Suppose that the following condition is satisfied:
where . Then, has a unique fixed point and .*

*Corollary 23 (Kannan type). Let be a complete partial rectangular metric space and let be a mapping. Suppose that the following condition is satisfied:
for all , where . Then, has a unique fixed point and .*

*Corollary 24 (Reich type). Let be a complete partial rectangular metric space and let be a mapping. Suppose that the following condition is satisfied:
for all , where , and are nonnegative constants such that . Then, has a unique fixed point and .*

*Corollary 25 (Chatterjea type). Let be a complete partial rectangular metric space and let be a mapping. Suppose that the following condition is satisfied:
for all , where . Then, has a unique fixed point and .*

*Corollary 26 (Hardy-Rogers type). Let be a complete partial rectangular metric space and let be a mapping. Suppose that the following condition is satisfied:
for all , where , , , , and are nonnegative constants such that . Then, has a unique fixed point and .*

*Corollary 27. Let be a complete partial rectangular metric space and let be a mapping. Suppose that for some positive integer , the following condition is satisfied:
for all , where . Then, has a unique fixed point and .*

*Proof. *We note that satisfies the condition (16) of Theorem 19; therefore, has a unique fixed point and . Now, ; therefore, is another fixed point of and, by uniqueness, we have . Thus, is a fixed point of . Since every fixed point of is also a fixed point of , the fixed point of is unique.

*Conflict of Interests*

*Conflict of Interests*

*The author declares that there is no conflict of interests regarding the publication of this paper.*

*Acknowledgment*

*Acknowledgment*

*Author is thankful to Professor Stojan Radenović for his valuable suggestions on this paper.*

*References*

*References*

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