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Abstract and Applied Analysis

Volume 2014 (2014), Article ID 710746, 9 pages

http://dx.doi.org/10.1155/2014/710746

## Krasnosel’skii Type Hybrid Fixed Point Theorems and Their Applications to Fractional Integral Equations

^{1}Department of Mathematics and Statistics, University of Victoria, Victoria, BC, Canada V8W 3R4^{2}Department of Mathematics, Mahatma Gandhi Mahavidyalaya, Ahmedpur, District Latur, Maharashtra 413515, India^{3}Research Scholar, Department of Mathematics, North Maharashtra University, Jalgaon, Maharashtra 415001, India^{4}Department of Engineering Sciences, MIT Academy of Engineering, Alandi, Pune, Maharashtra 412105, India^{5}Department of Mathematics, University of Mumbai, Mumbai, Maharashtra 400032, India

Received 23 June 2014; Accepted 5 July 2014; Published 27 August 2014

Academic Editor: Xiao-Jun Yang

Copyright © 2014 H. M. Srivastava et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

#### Abstract

Some hybrid fixed point theorems of Krasnosel’skii type, which involve product of two operators, are proved in partially ordered normed linear spaces. These hybrid fixed point theorems are then applied to fractional integral equations for proving the existence of solutions under certain monotonicity conditions blending with the existence of the upper or lower solution.

#### 1. Introduction

Recently, Nieto and Rodríguez-López [1] proved the following hybrid fixed point theorem for the monotone mappings in partially ordered metric spaces using the mixed arguments from algebra and geometry.

Theorem 1 (Nieto and Rodríguez-López [1]). *Let be a partially ordered set and suppose that there is a metric in such that is a complete metric space. Let be a monotone non-decreasing mapping such that there exists a constant such that
**
for all comparable elements . Assume that either is continuous or is such that if is a non-decreasing sequence with in , then
**
Further, if there is an element satisfying , then has a fixed point which is unique if “every pair of elements in has a lower and an upper bound.”*

Another fixed point theorem in the above direction can be stated as follows.

Theorem 2 (Nieto and Rodríguez-López [1]). *Let be a partially ordered set and suppose that there is a metric in such that is a complete metric space. Let be a monotone non-decreasing mapping such that there exists a constant such that (1) satisfies for all comparable elements . Assume that either is continuous or is such that if is a non-decreasing sequence with in , then
**
Further, if there is an element satisfying , then has a fixed point which is unique if “every pair of elements in has a lower and an upper bound.”*

*Remark 3. *If we suppose that and is a sequence in whose consecutive terms are comparable, then there exists a subsequence of such that every term comparable to the limit implies the conditions (2) and (3), since (in the monotone case) the existence of a subsequence whose terms are comparable with the limit is equivalent to saying that all the terms in the sequence are also comparable with the limit.

Taking Remark 3 into account, the results discussed by Nieto and Rodríguez-López and the fact that, in conditions , there is a sequence in whose consecutive terms are comparable, there exists a subsequence of such that every term comparable to the limit implies the validity of the conditions (2) and (3). Here the key is that the terms in the sequence (starting at a certain term) are comparable to the limit. Nieto and Rodríguez-López [2] obtained the following results, which improve Theorems 1 and 2.

Theorem 4 (Nieto and Rodríguez-López [2]). *Let be a partially ordered set and suppose that there exists a metric in such that is a complete metric space. Let be a monotone function (non-decreasing or non-increasing) such that there exists with
**
Suppose that either is continuous or is such that if is a sequence in X whose consecutive terms are comparable, then there exists a subsequence of such that every term comparable to the limit . If there exists with or , then has a fixed point which is unique if “every pair of elements in has a lower and an upper bound.”*

After the publication of the above fixed point theorems, there is a huge upsurge in the development of the metric fixed point theory in partially ordered metric spaces. A good number of fixed and common fixed point theorems have been proved in the literature for two, three, and four mappings in metric spaces by suitably modifying the contraction condition (1) as per the requirement of the results. We claim that almost all the results proved so far along this line, though not mentioned here, have their origin in a paper due to Heikkilä and Lakshmikantham [3]. The main difference is the convergence criteria of the sequence of iterations of the monotone mappings under consideration. The convergence of the sequence in Heikkilä and Lakshmikantham [3] is straightforward, whereas the convergence of the sequence in Nieto and Rodríguez-López [1, 2] is due mainly to the metric condition of contraction. The hybrid fixed point theorem of Heikkilä and Lakshmikantham [3] for the monotone mappings in ordered metric spaces is as follows.

Theorem 5 (Heikkillä and Lakshmikantham [3]). *Let be an order interval in a subset of the ordered metric space and let be a non-decreasing mapping. If the sequence converges in whenever is a monotone sequence in , then the well-ordered chain of -iterations of has the maximum which is a fixed point of . Moreover,
*

*The above hybrid fixed point theorem is applicable in the study of discontinuous nonlinear equations and has been used throughout the research monograph of Heikkillä and Lakshmikantham [3]. We also claim that the convergence of the monotone sequence in Theorem 5 is replaced in Theorem 4 by the Cauchy sequence and completeness of . Further, the Cauchy non-decreasing sequence is replaced by the equivalent contraction condition for comparable elements in . Theorem 4 is the best hybrid fixed point theorem because it is derived for the mixed arguments from algebra and geometry. The main advantage of Theorem 4 is that the uniqueness of the fixed point of the monotone mappings is obtained under certain additional conditions on the domain space such as lattice structure of the partially ordered space under consideration and these fixed point results are useful in establishing the uniqueness of the solution of nonlinear differential and integral equations. Again, some hybrid fixed point theorems of Krasnosel’skii type for monotone mappings are proved in Dhage [4, 5] along the lines of Heikkilä and Lakshmikantham [3].*

*The main object of this paper is first to establish some hybrid fixed point theorems of Krasnosel’skii type in partially ordered normed linear spaces, which involve product of two operators. We then apply these hybrid fixed point theorems to fractional integral equations for proving the existence of solutions under certain monotonicity conditions blending with the existence of the upper or lower solution.*

*2. Hybrid Fixed Point Theorems*

*Let be a linear space or vector space. We introduce a partial order in as follows. A relation in is said to be a partial order if it satisfies the following properties:(1)reflexivity: for all ;(2)antisymmetry: and implies ;(3)transitivity: and implies ;(4)order linearity: and ; and for .*

*The linear space together with a partial order becomes a partially ordered linear or vector space. Two elements and in a partially ordered linear space are called comparable if the relation either or holds true. We introduce a norm in partially ordered linear space so that becomes now a partially ordered normed linear space. If is complete with respect to the metric defined through the above norm, then it is called a partially ordered complete normed linear space.*

*The following definitions are frequently used in our present investigation.*

*Definition 6. *A mapping is called monotone non-decreasing if implies for all .

*Definition 7. *A mapping is called monotone non-increasing if implies for all .

*Definition 8. *A mapping is called monotone if it is either monotone non-increasing or monotone non-decreasing.

*Definition 9 (see [6, 7]). *A mapping is called a monotone dominating function or, in short, an -function if it is an upper or lower semicontinuous and monotonic non-decreasing or non-increasing function satisfying the condition: .

*Definition 10 (see [6, 7]). *Given a partially ordered normed linear space , a mapping is called partially -Lipschitz or partially nonlinear -Lipschitz if there is an -function satisfying
for all comparable elements . The function is called an -function of on . If , then is called partially -Lipschitz with the Lipschitz constant . In particular, if , then is called a partially -contraction on with the contraction constant . Further, if , for , then is called a partially nonlinear -contraction with an -function of on .

*There do exist -functions and the commonly used -functions are and , et cetera. These -functions can be used in the theory of nonlinear differential and integral equations for proving the existence results via fixed point methods.*

*Definition 11 (see [8]). *An operator on a normed linear space into itself is called compact if is a relatively compact subset of . is called totally bounded if, for any bounded subset of , is a relatively compact subset of . If is continuous and totally bounded, then it is called completely continuous on .

*Definition 12 (see [8]). *An operator on a normed linear space into itself is called partially compact if is a relatively compact subset of for all totally ordered set or chain in . The operator is called partially totally bounded if, for any totally ordered and bounded subset of , is a relatively compact subset of . If the operator is continuous and partially totally bounded, then it is called partially completely continuous on .

*Remark 13. *We note that every compact mapping in a partially metric space is partially compact and every partially compact mapping is partially totally bounded. However, the reverse implication does not hold true. Again, every completely continuous mapping is partially completely continuous and every partially completely continuous mapping is continuous and partially totally bounded, but the converse may not be true.

*We now state and prove the basic hybrid fixed point results of this paper by using the argument from algebra, analysis, and geometry. The slight generalization of Theorem 4 and Dhage [8] using -contraction is stated as follows.*

*Theorem 14. Let be a partially ordered set and suppose that there exists a metric in such that is a complete metric space. Let be a monotone function (non-decreasing or non-increasing) such that there exists an -function such that
for all comparable elements and satisfying . Suppose that either is continuous or is such that if is a sequence in whose consecutive terms are comparable, then there exists a subsequence of such that every term comparable to the limit . If there exists with or , then has a fixed point which is unique if “every pair of elements in has a lower and an upper bound.”*

*Proof. *The proof is standard. Nevertheless, for the sake of completeness, we give the details involved. Define a sequence of successive iterations of by
By the monotonicity property of , we obtain
or
If , for some , then is a fixed point of . Therefore, we assume that for some . If and , then, by the condition (6), we obtain
for each .

Let us write . Since is an -function, is a monotonic sequence of real numbers which is bounded. Hence is convergent and there exists a real number such that
We show that . If , then
which is a contradiction. Hence .

We now show that is a Cauchy sequence in . If not, then, for , there exists a positive integer such that
for all positive integers .

If we write , then
so that we have
Again, we have

Taking the limit as , we obtain
which is a contradiction. Therefore, is a Cauchy sequence in . By the metric space being complete, there is a point such that . The rest of the proof is similar to above fixed point Theorem 4 given in Nieto and Rodríguez-López [2]. Hence we omit the details involved.

*Corollary 15. Let be a partially ordered set and suppose that there exists a metric in such that is a complete metric space. Let be a monotone function (non-decreasing or non-increasing) such that there exists an -function and a positive integer such that
for all comparable elements and satisfying . Suppose that either is continuous or is such that if is a sequence in whose consecutive terms are comparable, then there exists a subsequence of such that every term comparable to the limit . If there exists with or , then has a fixed point which is unique if “every pair of elements in X has a lower and an upper bound.”*

*Proof. *Let us first set . Then is a continuous monotonic mapping. Also there exists the element such that . Now, an application of Theorem 14 yields that has an unique fixed point; that is, it is a point such that . Now , showing that is again a fixed point of . By the uniqueness of , we get . The proof is complete.

*Fixed point Theorem 14 and Corollary 15 have some nice applications to various nonlinear problems modelled on nonlinear equations for proving existence as well as uniqueness of the solutions under generalized Lipschitz condition. The following fixed point theorem is presumably new in the literature. The basic principle in formulating this theorem is the same as that of Dhage [5, 8] and Nieto and Rodríguez-López [2]. Before stating these results, we give an useful definition.*

*Definition 16. *The order relation and the norm in a nonempty set are said to be compatible if is a monotone sequence in and if a subsequence of converges to impling that the whole sequence converges to . Similaraly, given a partially ordered normed linear space , the ordered relation and the norm are said to be compatible if and the metric defined through the norm are compatible.

Clearly, the set with the usual order relation and the norm defined by absolute value function has this property. Similarly, the space with usual order relation defined by if and only if for all or if and only if for all and the usual standard supremum norm are compatible.

*We now state a more basic hybrid fixed point theorem. Since the proof is straightforword, we omit the details involved.*

*Theorem 17. Let be a partially ordered linear space and suppose that there is a norm in such that is a normed linear space. Let be a monotonic (non-decreasing or non-increasing), partially compact and continuous mapping. Further, if the order relation or and the norm in X are compatible and if there is an element satisfying or , then has a fixed point.*

*In this paper, we combine Theorems 14 and 17 and Corollary 15 to derive some Krasnosel’skii type fixed point theorems in partially ordered complete normed linear spaces and discuss some of their applications to fractional integral equations of mixed type. We freely use the conventions and notations for fractional integrals as in (for example) [9–11].*

*3. Krasnosel’skii Type Fixed Point Theorems*

*We first state the following result.*

*Theorem 18 (see Krasnosel’skii [12]). Let be a closed convex and bounded subset of a Banach space and let and be two operators satisfying the following conditions:(a) is nonlinear contraction;(b) is completely continuous;(c) for all implies .Then the following operator equation
has a solution.*

*Theorem 18 is very much useful and applied to linear perturbations of differential and integral equations by several authors in the literature for proving the existence of the solutions. The theory of Krasnosel’skii type fixed point theorem is initiated by Dhage [5]. The following Krasosel’skii type fixed point theorem is proved in Dhage [5].*

*Theorem 19 (see Dhage [5]). Let be a nonempty, closed, convex, and bounded subset of the Banach algebra . Also let and be two operators such that(a) is -Lipschitz with the -function ;(b) is completely continuous;(c) for all ;, where
Then the operator equation has a solution in .*

*Remark 20. * is monotone (non-decreasing or non-increasing) if and are monotone (non-decreasing or non-increasing), but the converse may not be true.

*We now obtain another version of Krasnosel’skii type fixed point theorems in partially ordered complete normed linear spaces under weaker conditions, which improve Theorem 19, and discuss some of their applications to fractional integral equations of mixed type.*

*Theorem 21. Let be a partially ordered complete normed linear space such that the order relation and the norm in are compatible. Let be two monotone operators (non-decreasing or non-increasing) such that(a) is continuous and partially nonlinear -contraction;(b) is continuous and partially compact;(c)there exists an element such that or for all ;(d)every pair of elements has a lower and an upper bound in ;(e), where
Then the operator equation has a solution.*

*Proof. *Define an operator by
Clearly, the operator is well defined. To see this, let be fixed and define a mapping by
Now, for any two comparable elements , we have
where is an -function of on . Hence, by an application of fixed point Theorem 14, has an unique fixed point; say . Therefore, we have an unique element such that
which implies that
or, equivalently, that
Thus the mapping is well defined.

We now define a sequence of iterates of ; that is, for . It follows from the hypothesis (c) that or . Again, by Remark 20, we find that the mapping is monotonic (non-decreasing or non-increasing) on . So we have
or
Since is partially compact and is continuous, the composition mapping is partially compact and continuous on into . Therefore, the sequence has a convergent subsequence and, from the compatibility of the order relation and the norm, it follows that the whole sequence converges to a point in . Hence, an application of Theorem 17 implies that has a fixed point. This further implies that
which evidently completes the proof of Theorem 21.

*Theorem 22. Let be a partially ordered complete normed linear space such that the order relation and the norm in are compatible. Let be two monotone mappings (non-decreasing or non-increasing) satisfying the following conditions:(a) is linear and bounded and is partially nonlinear -contraction for some positive integer ;(b) is continuous and partially compact;(c)there exists an element such that or for all ;(d)every pair of elements has a lower and an upper bound in ;(e), where
Then the operator equation has a solution.*

*Proof. *Define an operator on by
Now the mapping exists in view of the relation
where is bounded and exists in view of Corollary 15. Hence, exists and is continuous on . Next, the operator is well defined. To see this, let be fixed and define a mapping by
Then, for any two comparable elements , we have
Hence, by Corollary 15 again, there exists an unique element such that
This further implies that and is an unique fixed point of . Thus we have
Consequently, and so is well defined. The rest of the proof is similar to that of Theorem 21 and we omit the details. The proof is complete.

*Remark 23. *The hypothesis (d) of Theorems 21 and 22 holds true if the partially ordered set is a lattice. Furthermore, the space of continuous real-valued functions on the closed and bounded interval is a lattice, where the order relation is defined as follows. For any if and only if for all . The real-variable operations show that and are, respectively, the lower and upper bounds for the pair of elements and in .

*4. Fractional Integral Equations of Mixed Type*

*In this section we apply the hybrid fixed point theorems proved in the preceding sections to some nonlinear fractional integral equations of mixed type.*

*Given a closed and bounded interval in , being the set of real numbers or some real numbers and with and given a real number , consider the following nonlinear hybrid fractional integral equation (in short HFIE):
where is continuous and is locally Hölder continuous.*

*We seek the solutions of HFIE (38) in the space of continuous real-valued functions defined on . We consider the following set of hypotheses in what follows. is bounded on with bound . is non-decreasing in for each . There exist constants and such that
for all with . Moreover, . There exists an element such that
for all and or
for all and .*

*Remark 24. *The condition given in the hypothesis is a little more restrictive than that of a lower solution of the HFIE (38). It is clear that is a lower solution of the HFIE (38); however, the converse is not true.

*Theorem 25. Assume that the hypotheses through hold true. Then the HFIE (38) admits a solution.*

*Proof. *Define two operators and on , the Banach space of continuous real-valued functions on with the usual supremum norm given by
We define an order relation in with help of a cone defined by
Clearly, the Banach space together with this order relation becomes an ordered Banach space. Furthermore, the order relation and the norm in are compatible. Define two operators by
Then the given Hybrid fractional integral equation (38) is transformed into an equivalent operator equation as follows:
We show that the operators and satisfy all the conditions of Theorem 21 on . First of all, we show that is a nonlinear -contraction on . Let . Then, by the hypothesis , we obtain
Taking the supremum over , we get
where
Clearly, is an -function for the operator on and so is a partially nonlinear -contraction on .

Next, we show that is a compact continuous operator on . To this end, we show that is a uniformly bounded and equicontinuous set in . Now, for any , we have
which shows that is a uniformly bounded set in . We now let . Then
uniformly for all . Hence is an equicontinuous set in . Now we apply the Arzela-Ascoli theorem to show that is a compact set in . The continuity of follows from the continuity of the function on .

Finally, since and are non-decreasing in for each , the operators and are non-decreasing on . Also the hypothesis yields . Thus, all of the conditions of Theorem 22 are satisfied and we conclude that the fractional integral equation (38) admits a solution. This completes the proof.

*We now consider the following fractional integral equation of mixed type:
for all and , where the functions and are continuous.*

*We consider the following set of hypotheses in what follows. The function is continuous. Moreover, . is linear in for each . is bounded on and there exists a constant such that for all and . There exists an element such that
or
for all and , where the functions and are continuous.*

*Remark 26. *The condition given in hypothesis is a little more restrictive than that of a lower solution for the HFIE (51) defined on .

*Theorem 27. Assume that the hypotheses , , and through hold true. Then the HFIE (51) admits a solution.*

*Proof. *Set and define an order relation with the help of the cone defined by (43). Clearly, is a lattice with respect to the above order relation in it. Define two operators and on by
Clearly, the operator is linear and bounded in view of the hypotheses , , and . We only show that the operator is partially -contraction on for every positive integer . Let be such that . Then, by and , we have
where is the supremum of over . Thus, by taking the supremum over , we obtain
Similarly, it can be proved that
In general, proceeding in the same way, for any positive integer , we have
Therefore, for large , is partially a nonlinear -contraction mapping on . The rest of the proof is similar to that of Theorem 25. The desired result now follows by an application of Theorem 22. This completes the proof.

*5. An Illustrative Example*

*Example 1*. Consider a distributed-order fractional hybrid differential equation (DOFHDES) involving the Reimann-Liouville derivative operator of order with respect to the negative density function as follows:

*Moreover, the function is continuous for each , where is bounded in for some . Also and . It is well known that the DOFHDES (59) is equivalent to the following integral equation:
such that and
The integral equation (60) is valid for all . Hence, if Theorem 25 holds true then we further have
then the above-mentioned DOFHDES (59) has a solution.*

*Conflict of Interests*

*The authors declare that there is no conflict of interests regarding the publication of this paper.*

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