Research Article

On the Order Statistics of Standard Normal-Based Power Method Distributions

Table 7

Expected values of order statistics for 𝑝 2 ( 𝑍 ) = ( 2 / 5 ) 𝑍 3 for 𝑛 = 6 , 7 .

𝐸 [ 𝑝 2 ( 𝑍 ) 4 6 ] = 2 𝜋 3 / 2 1 0 2 t a n 1 ( 3 3 / 2 / 7 ) 𝜋 5 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 4 6 ] = 0 . 0 6 4 7 5 9 5 1
𝐸 [ 𝑝 2 ( 𝑍 ) 5 6 2 ] = 2 𝜋 3 / 2 + 5 2 t a n 1 ( 3 3 / 2 / 7 ) 𝜋 5 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 5 6 ] = 0 . 3 2 9 1 8 6 8 8
𝐸 [ 𝑝 2 ( 𝑍 ) 6 6 2 ] = 2 𝜋 3 / 2 2 t a n 1 ( 3 3 / 2 / 7 ) 𝜋 5 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 6 6 ] = 1 . 4 8 2 1 0 4 7 1
𝐸 [ 𝑝 2 ( 𝑍 ) 4 7 ] = 0
𝐸 [ 𝑝 2 ( 𝑍 ) 5 7 7 ] = 2 2 𝜋 3 / 2 3 5 t a n 1 ( 3 3 / 2 / 7 ) 2 𝜋 5 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 5 7 ] = 0 . 1 1 3 3 2 9 1 4
𝐸 [ 𝑝 2 ( 𝑍 ) 6 7 7 ] = 2 𝜋 3 / 2 + 1 4 2 t a n 1 ( 3 3 / 2 / 7 ) 𝜋 5 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 6 7 ] = 0 . 4 1 5 5 2 9 9 8
𝐸 [ 𝑝 2 ( 𝑍 ) 7 7 7 ] = 2 2 𝜋 3 / 2 7 t a n 1 ( 3 3 / 2 / 7 ) 2 𝜋 5 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 7 7 ] = 1 . 6 5 9 8 6 7 1 7