Abstract

The reduced Burau representation is a one-parameter representation of 𝐵𝑛, the braid group on 𝑛 strings. Specializing the parameter to nonzero complex number 𝑥 gives a representation 𝛽𝑛(𝑥): 𝐵𝑛𝐺𝐿(𝑛1), which is either irreducible or has an irreducible composition factor ̂𝛽𝑛(𝑥): 𝐵𝑛𝐺𝐿(𝑛2). In our paper, we let 𝑘2, and we determine a sufficient condition for the irreducibility of the tensor product of 𝑘 irreducible Burau representations. This is a generalization of our previous work concerning the cases 𝑘=2 and 𝑘=3.

1. Introduction

Let 𝐵𝑛 be the braid group on 𝑛 strings. We consider the linear representation of 𝐵𝑛 called the Burau representation [1], which has a composition factor, the reduced Burau representation𝛽𝑛(𝑡)𝐵𝑛GL𝑛1𝑡±1,(1.1) where 𝑡 is an indeterminate. Specializing 𝑡𝑥, where 𝑥, defines a representation 𝛽𝑛(𝑥)𝐵𝑛GL𝑛1() which is either irreducible or has an irreducible subrepresentation ̂𝛽𝑛(𝑥) of degree 𝑛2. For more details, see [2, page 286].

In our paper, we consider the following question: for which values of the parameters is the tensor product of 𝑘irreducible representations of the braid group, 𝐵𝑛, irreducible? The question was answered in the cases 𝑘=2and 𝑘=3. We prove that the tensor product of an irreducible 𝛽𝑛(𝑦) or ̂𝛽𝑛(𝑦) with an irreducible 𝛽𝑛(𝑧) or ̂𝛽𝑛(𝑧) is irreducible if and only if 𝑦𝑧±1. For more details, see [3]. We also consider the case 𝑘=3and find a sufficient condition that guarantees the irreducibility of three irreducible representations of 𝐵𝑛. In other words, we show that the tensor product of an irreducible 𝛽𝑛(𝑥) or ̂𝛽𝑛(𝑥) with an irreducible 𝛽𝑛(𝑦) or ̂𝛽𝑛(𝑦) with an irreducible 𝛽𝑛(𝑧) or ̂𝛽𝑛(𝑧) is irreducible if 𝑥𝑦±1,  𝑥𝑧±1,  𝑦𝑧±1, 𝑥+𝑦𝑧0,  𝑦+𝑥𝑧0,  𝑧+𝑥𝑦0,  and 𝑥𝑦𝑧1. We fall short of finding a necessary and sufficient condition in the case 𝑘=3(see [4]).

In our paper, we generalize the results obtained in [3, 4] and find a sufficient condition that guarantees the irreducibility of the tensor product of 𝑘irreducible representations of the braid group, where 𝑘2. Therefore, our paper is concerned with the tensor product of the following irreducible representations:𝛽𝑛𝑥1𝛽𝑛𝑥2𝛽𝑛𝑥𝑘𝐵𝑛GL𝑛1𝑛1𝑛1,𝛽𝑛𝑥1̂𝛽𝑛𝑥2𝛽𝑛𝑥𝑘𝐵𝑛GL𝑛1𝑛2𝑛1,̂𝛽𝑛𝑥1̂𝛽𝑛𝑥2̂𝛽𝑛𝑥𝑘𝐵𝑛GL𝑛2𝑛2𝑛2.(1.2)

Our main result is that, for 𝑛4, the above representations are irreducible if (1)𝑙𝑤𝑙(1)𝑡𝑤𝑡±1, for 𝑙,𝑡{1,,𝑘}, where 𝑤𝑙 and 𝑤𝑡 are positive words of lengths 𝑙 and 𝑡,respectively, and do not have any 𝑥𝑖in common.

2. Definitions

The braid group on 𝑛 strings, 𝐵𝑛, is defined as an abstract group with 𝑛1 generators 𝜎𝑖 (𝑖=1,2,,𝑛1) and relations:(i)𝜎𝑖𝜎𝑖+1𝜎𝑖=𝜎𝑖+1𝜎𝑖𝜎𝑖+1 for 𝑖=1,2,,𝑛2,(ii)𝜎𝑖𝜎𝑗=𝜎𝑗𝜎𝑖if|𝑖𝑗|2.

The generators 𝜎1,𝜎2,𝜎𝑛1 are called the standard generators. Let 𝑡 be an indeterminate, and let [𝑡±1] be a Laurent polynomial ring over the complex numbers. All modules are -vector spaces, so 𝐵𝑛 modules and [𝐵𝑛] modules will mean the same. We define the following representations of 𝐵𝑛 by matrices over [𝑡±1].

Definition 1. The reduced Burau representation 𝛽𝑛(𝑡)𝐵𝑛GL𝑛1([𝑡±1]) is given by 𝜎1(𝑡)=𝛽𝑛(𝑡)𝜎1=𝑡01100𝐼𝑛3,𝜎𝑖(𝑡)=𝛽𝑛(𝑡)𝜎𝑖=𝐼𝑖20001𝑡00𝑡0011000𝐼𝑛𝑖2,for𝑖=2,,𝑛2,𝜎𝑛1(𝑡)=𝛽𝑛(𝑡)𝜎𝑛1=𝐼𝑛3001𝑡0𝑡.(2.1)

Definition 2. 𝜏𝑛=𝜎1𝜎2𝜎𝑛1and 𝜏𝑛(𝑡)=𝜎1(𝑡)𝜎2(𝑡)𝜎𝑛1(𝑡).

Direct calculations show that𝜏𝑛(𝑡)=𝑡𝑡2𝑡3(𝑡)𝑛2(𝑡)𝑛110000010000010000010.(2.2)

We identify 𝑛1 with (𝑛1)×1 column vectors, we let 𝑒1,𝑒2,,𝑒𝑛1 denote the standard basis for 𝑛1, and we consider matrices to act by left multiplication on column vectors.

Definition 3. If 𝑟=𝑎1𝑒1+𝑎2𝑒2++𝑎𝑛1𝑒𝑛1𝑛1, the support of 𝑟, denoted by supp(𝑟), is the set {𝑒𝑖𝑎𝑖0}. If 𝑠=𝑎𝑖𝑗(𝑒𝑖𝑒𝑗)𝑛1𝑛1, the support of 𝑠, also denoted by supp(𝑠), is the set {𝑒𝑖𝑒𝑗𝑎𝑖𝑗0}, and 𝑎𝑖𝑗 is called the coefficient of𝑒𝑖𝑒𝑗 in 𝑠.

Definition 4. For 𝑖=1,2,,𝑛1,𝑣𝑖(𝑡)=𝑒𝑖𝜎𝑖(𝑡)(𝑒𝑖)=(𝐼𝜎𝑖(𝑡))(𝑒𝑖).

3. Preliminaries

Lemma 3.1. (a) 𝜎𝑖(𝑡)(𝑣𝑖1(𝑡))=𝑣𝑖1(𝑡)𝑣𝑖(𝑡) for 2𝑖𝑛1,
𝜎𝑖(𝑡)(𝑣𝑖(𝑡))=𝑡𝑣𝑖(𝑡) for 1𝑖𝑛1,
𝜎𝑖(𝑡)(𝑣𝑖+1(𝑡))=𝑡𝑣𝑖(𝑡)+𝑣𝑖+1(𝑡) for 1𝑖𝑛2,
𝜎𝑖(𝑡)(𝑣𝑗(𝑡))=𝑣𝑗(𝑡) for 1𝑖,  𝑗𝑛1,  |𝑖𝑗|2,
(b) 𝜏𝑛(𝑣𝑖(𝑡))=𝑣𝑖+1(𝑡) for 1𝑖𝑛2.

Note that the above lemma remains true for any specialization 𝑡𝑦, where 𝑦.

Notation 1. Fix nonzero complex numbers 𝑥1,,𝑥𝑘. Let 𝜎𝐵𝑛and 𝑢=𝑢1𝑢𝑘𝑛1𝑛1, then we write 𝜎(𝑢1𝑢𝑘)=𝜎(𝑥1)(𝑢1)𝜎(𝑥𝑘)(𝑢𝑘).

Notation 2. Given 𝑥1,,𝑥𝑘, by a positive word of length 𝑙, we mean a word that is written as a product of 𝑥1,,𝑥𝑘, where the number of 𝑥𝑖s involved is 𝑙, and their exponents are ones. Each 𝑥𝑖in 𝑤𝑙appears exactly once. We denote the word by 𝑤𝑙. As an example, we write 𝑤3=𝑥1𝑥3𝑥4to stand for a word of length 3.

Lemma 3.2. 𝜎𝑛𝑖𝑒𝑖𝑒𝑖𝑒𝑖𝑘-times=𝑒𝑖1+𝑥𝑛11+𝑥1𝑣𝑖𝑥1𝑒𝑖1+𝑥𝑛𝑘1+𝑥𝑘𝑣𝑖𝑥𝑖𝑘if𝑛isodd,𝑒𝑖1𝑥𝑛11+𝑥1𝑣𝑖𝑥1𝑒𝑖1𝑥𝑛𝑘1+𝑥𝑘𝑣𝑖𝑥𝑘if𝑛iseven.(3.1)

Lemma 3.3. Let 𝛽𝑛(𝑦)𝐵𝑛GL(𝑛1) be a specialization of the Burau representation making 𝑛1 into a 𝐵𝑛-module, where 𝑛3, then (a)let 𝐴 be the kernel of the homomorphism [𝐵𝑛] induced by 𝜎𝑖1 (the augmentation ideal), then 𝐴𝑛1 is equal to the -vector space spanned by 𝑣1(𝑦),,𝑣𝑛1(𝑦),(b)if 𝑀 is a nonzero 𝐵𝑛-submodule of 𝑛1, then 𝐴𝑛1𝑀. Hence, 𝐴𝑛1 is the unique minimal nonzero 𝐵𝑛-module of 𝑛1,(c)if 𝑦 is not a root of 𝑝(𝑡)=𝑡𝑛1+𝑡𝑛2++𝑡+1, then 𝐴𝑛1=𝑛1, and 𝛽𝑛(𝑦) is irreducible. If 𝑦 is a root of 𝑝(𝑡), then dim𝐶(𝐴𝑛1)=𝑛2.

Hence, 𝐴𝑛1 is its unique minimal nonzero 𝐵𝑛-submodule. Of course, 𝐴𝑛1=𝑛1 when 𝛽𝑛(𝑦) is irreducible, but when 𝛽𝑛(𝑦) is reducible, 𝐴𝑛1 is the subrepresentation ̂𝛽𝑛(𝑦).

The main technical result is Proposition 4.1, which says that if (1)𝑙𝑤𝑙(1)𝑡𝑤𝑡±1,for 𝑙,𝑡{1,,𝑘},where 𝑤𝑙and 𝑤𝑡are positive words that do not have any 𝑥𝑖in common, then 𝐴𝑛1𝐴𝑛1𝐴𝑛1𝑘-timesis the unique minimal nonzero 𝐵𝑛-module of 𝑛1𝑛1𝑛1𝑘-times. This implies the irreducibility of the tensor products under the above conditions. We will mainly follow the argument presented in [3, 4]. However, new techniques in the proof are needed to generalize our computations.

4. Tensor Product of 𝑘 Irreducible Representations (𝑘2)

We obtain a result concerning the irreducibility of the tensor product of 𝑘irreducible representations of the braid group, 𝐵𝑛, where 𝑘2. We state our proposition and give an outline of a proof that goes along the same lines as in the cases 𝑘=2and 𝑘=3. However, a more general adequate proof is required here, which could be easily verified in the cases 𝑘=2and 𝑘=3by simply returning back to our previous work in [3, 4]. Most of the formulas and equations in the proof can be verified using mathematical induction and possibly by performing direct computations as well.

Proposition 4.1. Let 𝑀 be a nonzero 𝐵𝑛 submodule of 𝑛1𝑛1𝑛1𝑘-times under the action of 𝛽𝑛(𝑥1)𝛽𝑛(𝑥2)𝛽𝑛(𝑥𝑘)𝐵𝑛GL(𝑛1𝑛1𝑛1), where 𝑛3. Suppose that for 𝑙,𝑡{1,,𝑘} one has (1)𝑙𝑤𝑙(1)𝑡𝑤𝑡±1𝑤𝑙and𝑤𝑡donothaveany𝑥𝑖incommon,(4.1) then, 𝑀 contains all 𝑣𝑡1(𝑥1)𝑣𝑡2(𝑥2)𝑣𝑡𝑘(𝑥𝑘) for 1𝑡1,𝑡2,,𝑡𝑘𝑛1, and 𝑀 contains 𝐴𝑛1𝐴𝑛1𝐴𝑛1𝑘-times, where the action of 𝐵𝑛 on the 𝑖th factor is induced by 𝛽𝑛(𝑥𝑖).

Proof. The steps of the proof are similar to those in [3, 4]. But still, we need to generalize our computations in the general case 𝑘2.

Claim 1. There exists 𝑚𝑀 such that 𝑒1𝑒1𝑒1𝑘-timesor 𝑒2𝑒2𝑒2𝑘-timessupp(𝑚).

Proof of Claim 1. When 𝑘=2, we set 𝐽=𝑝𝑒𝑝𝑒𝑞or𝑒𝑞𝑒𝑝supp(𝑚)forsome𝑚𝑀andsome𝑞.(4.2)
First, we show that 1𝐽. Second, we let 𝑝=𝜎3𝜎𝑘, where 𝑘=min{𝑝𝑒𝑝supp(𝑣)supp(𝑤)}. Using some recursive argument, we show that there is an element 𝑚or 𝑝(𝑚)of the form 𝑚=𝑎𝑒1𝑒2+𝑏𝑒2𝑒1+𝑊,(4.3) where 𝑒1𝑒1,𝑒1𝑒2,𝑒2𝑒1supp(𝑊), and at least one of 𝑎,𝑏 is nonzero. If 𝑒2𝑒2supp(𝑊), we are done. If 𝑒2𝑒2supp(𝑊), then 𝑎𝑧by=coecientof𝑒1𝑒1in𝜎2(𝑚),𝑎𝑧2𝑧+𝑏𝑦2𝑦=coecientof𝑒1𝑒1in𝜎22(𝑚).(4.4) The determinant det𝑧𝑦𝑧2𝑧𝑦2𝑦=𝑦𝑧(𝑧𝑦),(4.5) is nonzero, since 𝑦𝑧. Then one of 𝑎𝑧by,𝑎(𝑧2𝑧)+𝑏(𝑦2𝑦) is nonzero, and one of 𝜎2(𝑚), (𝜎2)2(𝑚) has 𝑒1𝑒1 in its support. For more details, see [3].

As for the general case 𝑘2, we follow the same argument as above. The 2×2above is generalized to a (2𝑘2)×(2𝑘2) matrix 𝐴𝑘 whose rows 𝑅1,𝑅2,,𝑅2𝑘2 are given by𝑅1=(1)𝑙𝑤𝑙,1𝑙𝑘1,𝑅𝑖=𝑓𝑖𝑤𝑙,1𝑙𝑘1,𝑤𝑙arethesamepositivewordsin𝑅1,(4.6) for 𝑖=2,,2𝑘2.

Here, 𝑓𝑖(𝑥𝑙)=𝛼𝑖(𝑥𝑙) for 𝑖=1,,2𝑘2,and 𝑤𝑙s are all positive words of length 𝑙. Using the hypothesis, the determinant of the matrix 𝐴𝑘 is nonzero, and this gives that one of the coefficients in 𝜎𝑖2(𝑚) has 𝑒1𝑒1𝑒1𝑘-timessupp(𝑚) for 𝑖=1,2,,2𝑘2.

Claim 2. Suppose that 𝑒𝑖𝑒𝑖𝑒𝑖𝑘-timessupp(𝑚) for some 𝑚𝑀, then 𝑣𝑖𝑣𝑖𝑣𝑖𝑘-times𝑀.

Proof of Claim 2. 𝜎𝑖1𝑘1𝑡=1𝜎𝑖(1)𝑡𝑤𝑡𝑒𝑖𝑒𝑖𝑒𝑖𝑘-times=𝑘𝑡=2𝑤𝑡(1)𝑡𝑤12𝑘11(𝑣𝑖𝑣𝑖)𝑘-times,𝜎𝑖1𝑘1𝑡=1𝜎𝑖(1)𝑡𝑤𝑡𝑒𝑖1𝑒𝑖2𝑒𝑖𝑘=0if𝑖1,,𝑖𝑘(𝑖,,𝑖).(4.7) Here, 𝑤𝑡represents all words of length 𝑡. By our hypothesis, the proof is done.

Claim 3. There exists at least one (𝑠1,𝑠2,,𝑠𝑘) such that 𝑣𝑠1𝑣𝑠2𝑣𝑠𝑘𝑀, where 𝑠1,𝑠2,,𝑠𝑘{1,2} and (𝑠1,𝑠2,,𝑠𝑘) is neither (1,1,,1) nor (2,2,,2).

Proof of Claim 3. Knowing that 𝑣1𝑣1𝑣1𝑘-times𝑀, then 𝜎2(𝑣1𝑣1𝑣1)𝑀. It follows that 𝑣1𝑣2𝑣1𝑣2𝑣1𝑣2𝑀.(4.8)
The proof is completed by applying 𝜎1 repeatedly to the expression above.

Claim 4. All the tensors 𝑣𝑠1𝑣𝑠2𝑣𝑠𝑘𝑀 for all 𝑠1,𝑠2,,𝑠𝑘{1,2}.

Proof of Claim 4. By applying 𝜎2 to the tensors obtained from Claim 3 and then applying 𝜎1 repeatedly, the proof is done.

Claim 5. For 3𝑖𝑛2, all tensors of the form 𝑣𝑖𝑣1𝑣1𝑘-1times and 𝑣𝑖𝑣2𝑣2𝑘-1times and those obtained by permuting the indices are in 𝑀.

Proof of Claim 5. Knowing that 𝜎𝑖+1𝑣𝑖𝑥1𝑣1𝑥2𝑣1𝑥𝑘=𝑣𝑖𝑥1𝑣𝑖+1𝑥1𝑣1𝑥2𝑣1𝑥𝑘,𝜎𝑖+1𝑣𝑖𝑥1𝑣2𝑥2𝑣2𝑥𝑘=𝑣𝑖(𝑥)𝑣𝑖+1(𝑥)𝑣2𝑥2𝑣2𝑥𝑘,(4.9) we apply induction on 𝑖, and the proof is finished.

Claim 6. All tensors 𝑣𝑖𝑣𝑗𝑣1𝑣1𝑘-2times and those obtained by permuting the indices are in 𝑀 for 𝑖,𝑗3.

Proof of Claim 6. This is done by induction on 𝑗 and using Claim 5.

Claim 7. All tensors of the form 𝑣𝑖𝑣𝑗𝑣𝑣1𝑣1𝑣1𝑘-3times and those obtained by permuting the indices are in 𝑀.

Proof of Claim 7. Applying induction on and using Claim 6, the proof is completed.

Claim 8. All tensors 𝑣1𝑣𝑠1𝑣𝑠2𝑣𝑠𝑘1 are in 𝑀 for all 1𝑠1,𝑠2,,𝑠𝑘1𝑛1.

Proof of Claim 8. This is done by induction on 𝑠𝑘1 and using the previous claims.

Claim 9. 𝑣𝑠1𝑣𝑠2𝑣𝑠𝑘𝑀 for all 1𝑠1,𝑠2,,𝑠𝑘1𝑛1.

Proof of Claim 9. By Claim 8, we have that all the tensors 𝑣1𝑣𝑠1𝑣𝑠2𝑣𝑠𝑘1are in 𝑀, Consider then 𝜏𝑛𝑣1𝑣𝑠1𝑣𝑠2𝑣𝑠𝑘1𝑀.(4.10) Knowing that 𝜏𝑛(𝑣𝑖(𝑡))=𝑣𝑖+1(𝑡), the proof is completed.

We now get our main theorem.

Theorem 4.2. Consider the tensor products of the irreducible representations 𝛽𝑛𝑥1𝛽𝑛𝑥2𝛽𝑛𝑥𝑘𝐵𝑛GL𝑛1𝑛1𝑛1,where𝑝𝑥10,𝑝𝑥20,,𝑝𝑥𝑘0,𝛽𝑛𝑥1̂𝛽𝑛𝑥2𝛽𝑛𝑥𝑘𝐵𝑛GL𝑛1𝑛2𝑛1,where𝑝𝑥10,𝑝𝑥2=0,,𝑝𝑥𝑘0,̂𝛽𝑛𝑥1̂𝛽𝑛𝑥2̂𝛽𝑛𝑥𝑘𝐵𝑛GL𝑛2𝑛2𝑛2,where𝑝𝑥1=0,𝑝𝑥2=0,,𝑝𝑥𝑘=0,(4.11) where 𝛽𝑛(𝑥)𝐵𝑛GL(𝑛1) and ̂𝛽𝑛(𝑥)𝐵𝑛GL(𝐴𝑛1)=GL(𝑛2) denote a specialization of the reduced Burau representation and the irreducible subrepresentation of Lemma 3.3(b), respectively. If, for 𝑙,𝑡{1,,𝑘}, one has that (1)𝑙𝑤𝑙(1)𝑡𝑤𝑡±1𝑤𝑙and𝑤𝑡donothaveany𝑥𝑖incommon,(4.12) then the above representations are irreducible.

Proof. The proof is along the same lines as in the special cases 𝑘=2 and 𝑘=3. All of the above representations are subrepresentations of 𝛽𝑛𝑥1𝛽𝑛𝑥2𝛽𝑛𝑥𝑘𝐵𝑛GL𝑛1𝑛1𝑛1.(4.13)
By Proposition 4.1, 𝐴𝑛1𝐴𝑛1𝐴𝑛1𝑘-times is the unique minimal nonzero 𝐵𝑛 module of 𝑛1𝑛1𝑛1𝑘-times. In particular, it is an irreducible 𝐵𝑛-module. By Lemma 3.3, the first factor 𝐴𝑛1 corresponds to one of the representations 𝛽𝑛(𝑥1) or ̂𝛽𝑛(𝑥1), the second factor 𝐴𝑛1 corresponds to one of the representations 𝛽𝑛(𝑥2) or ̂𝛽𝑛(𝑥2), and so on according to whether or not 𝑥1, 𝑥2,𝑥𝑘 are roots of 𝑝(𝑡). Hence, all the above representations can be identified with the 𝐵𝑛-module 𝐴𝑛1𝐴𝑛1𝐴𝑛1𝑘-times, so they are irreducible.