Research Article

On the Order Statistics of Standard Normal-Based Power Method Distributions

Table 4

Expected values of order statistics for 𝑝 2 ( 𝑍 ) = ( 2 / 5 ) 𝑍 3 for 𝑛 = 4 , 5 .

𝐸 [ 𝑝 1 ( 𝑍 ) 3 4 3 ] = 2 5 𝜋 3 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 3 4 ] = 0 . 1 4 4 6 2 6 6 5
𝐸 [ 𝑝 2 ( 𝑍 ) 4 4 ] = 2 5 𝜋 3 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 4 4 ] = 1 . 0 8 0 1 7 0 2 8
𝐸 [ 𝑝 2 ( 𝑍 ) 3 5 ] = 0
𝐸 [ 𝑝 2 ( 𝑍 ) 4 5 ] = 2 𝜋 3 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 4 5 ] = 0 . 2 4 1 0 4 4 4 2
𝐸 [ 𝑝 2 ( 𝑍 ) 5 5 1 ] = 2 𝜋 3 / 2 + 𝐸 [ 𝑝 1 ( 𝑍 ) 5 5 ] = 1 . 2 8 9 9 5 1 7 4