Abstract
Using some techniques from vector integration, we prove the weak measurability of the adjoint of strongly continuous semigroups which factor through Banach spaces without isomorphic copy of ; we also prove the strong continuity away from zero of the adjoint if the semigroup factors through Grothendieck spaces. These results are used, in particular, to characterize the space of strong continuity of , which, in addition, is also characterized for abstract - and -spaces. As a corollary, it is proven that abstract -spaces with no copy of are finite-dimensional.
1. Introduction
The study of the adjoint of a strongly continuous semigroups was initiated by Phillips [1], who proved, among other things, that for the general case, the domain of continuity of the adjoint semigroup on a Banach space is different from A systematic study of the adjoint semigroup can be found in [2], where, among other things, the basic properties of and of the canonical spaces and associated with it are studied. Also, in [2], Neerven introduces the space and studies the relationship between and giving some conditions guaranteeing that must be equal to where is a natural embedding of into defined by the formula
Some of the principal tools used by van Neerven come from vector measures, like Gelfand and Pettis integrals, in order to provide the reader with some examples where the above-mentioned equality holds.
In this paper, we also employ certain techniques from vector measures to show that semigroups factoring through Banach spaces without isomorphic copy of have weakly measurable adjoint. On the other hand, we prove the strong continuity away from zero of the adjoint when the semigroup factors through Grothendieck spaces. These results have several applications; in particular, there is one related to our other main topic of interest: to find a characterization of the space of strong continuity of a given second dual semigroup . This can be done in the case of spaces satisfying the above-mentioned hypotheses. This is also done when is sun-reflexive and is isomorphic to a dual Banach space. Additionally, we give a characterization of the strong continuity of for abstract - and -spaces, and prove that abstract -spaces with no copy of are finite-dimensional.
2. Preliminaries
2.1. The Semigroup Dual
Let be a complex Banach space and let be a -semigroup of bounded linear operators on The adjoint semigroup fails in general to be strongly continuous. The semigroup dual of with respect to notation (pronounced -sun) is defined as the linear subspace of on which acts in a strongly continuous way From this definition, we have that is -invariant, that is, for all
It can also be shown (see, e.g., [2]) that is a closed, weakβ-dense linear subspace of .
2.2. The Space
Let denote the restriction of to the -invariant subspace Since is closed, is a Banach space. Also, it is clear from the definition of that is a strongly continuous semigroup on
We can also define to be the adjoint of and write for (read as -sun-sun or -bosom).
If is defined by then and Moreover, is an embedding and we can identify isomorphically with the closed subspace of . If , then is said to be sun-reflexive or -reflexive with respect to .
The following results can be found in [2].
Theorem 2.1. Let be a complex Banach space, a -semigroup on with infinitesimal generator satisfying , and let be the adjoint of
The formula defines a natural embedding Moreover, and If is the natural map, then we have
We also have the following characterization of .
Theorem 2.2. It holds that
The former theorem suggests to define the following.
Definition 2.3.
A natural question is: do the spaces and coincide? Trivially, this is true if since then we have the coincidence of both definitions. It is also shown in [2] that maps into , and so always holds, but this inclusion can be proper. More specifically, if is the rotation group on the unit circle, then (see [2, page 99]).
In the following, we will be interested in giving conditions guaranteeing that is equal to
2.3. The Gelfand and Pettis Integrals
Let be finite measure space and let be a Banach space. Suppose that is weaklyβ--measurable and suppose further that for each the function belongs to For each define a map , It can be easily shown that is bounded. This implies that the linear map defined by is bounded. The element is called the weakβ-integral or Gelfand integral of over with respect to notation
We have from the definition that the weakβ-integral satisfies for all and
Now, if is weakly -measurable and for each , the function belongs to then using the same argument as above, each defines an element such that for all If for all the element belongs to then is said to be Pettis integrable with respect to
For a detailed study of the Gelfand and Pettis integrals, see [3β5].
Theorem 2.4. An element belongs to if and only if for all and one has
For a proof of this, see [2].
Corollary 2.5. if and only if for all , , and one has
Hence, if is Pettis integrable, that is, for all and , the map is Pettis integrable on then In particular, this holds if is strongly continuous away from zero (notation: ).
Definition 2.6. Let be two weakly -measurable functions. One says that are weakly -equivalent if - almost everywhere, for each If are weaklyβ-measurable, one says that , are weaklyβ-equivalent if for each
Following [5], we will denote by the space of classes of weakly -equivalent Pettis -integrable -valued functions. It is a linear space with ordinary algebraic operations.
Definition 2.7. has the -weak Radon-Nikodym property (-WRNP) if for each -valued -continuous measure of -finite variation , there exists such that for each and
has the WRNP if it has the -WRNP for every
For more details about the WRNP, see [4, 5].
One of the principal tools used here is the following theorem.
Theorem 2.8. has the weak Radon-Nikodym property if and only if contains no isomorphic copy of
3. Strong Continuity of the Adjoint Semigroup
It is well known that a semigroup is strongly continuous if and only if it is weakly continuous (see [6]). In [7], BΓ‘rcenas and Diestel have proved that if a -semigroup is such that, for each factors through an Asplund space, then the adjoint semigroup is (A Banach space is an Asplund space if and only if has the Radon-Nikodym property.) Since weakly compact operators factor through reflexive Banach spaces (which are Asplund spaces), we see that the adjoint semigroup of a semigroup of weakly compact operators is strongly continuous away from (see [8]). BΓ‘rcenas and Diestel used those results to get some applications in optimal control theory.
In this section, we get the same conclusion of BΓ‘rcenas-Diestel if a -semigroup is such that, for each , factors through a Grothendieck space.
We recall that a Banach space is a Grothendieck space if every weaklyβ-convergent sequence in is also weakly convergent. Equivalently, is a Grothendieck space if every linear bounded operator from to any separable space, Banach space is weakly compact. Among Grothendieck spaces, we list all reflexive Banach spaces and , where is a positive measure space. A Banach space isomorphic to a complemented subspace of a Grothendieck space is also a Grothendieck space. Several characterizations of Grothendieck spaces are found in [9].
A Banach space is said to have the Dunford-Pettis property if every weakly compact operator in applies relatively weakly compact sets onto relatively norm compact sets. The most common examples of Banach spaces with the Dunford-Pettis property are and Complemented subspaces of a space with the Dunford-Pettis property have also the Dunford-Pettis property. For more details about this, see [10].
If is a Grothendieck space with the Dunford-Pettis property, Lotz (see [11]) has shown that every strongly continuous semigroup is uniformly continuous and so the adjoint semigroup is uniformly continuous.
We also recall that a bounded linear operator (where and are Banach spaces) factors through a Banach space if there are bounded linear operators and such that the following diagram: (3.1) commutes.
Theorem 3.1. Let be a Banach space and a -semigroup defined on Suppose that for every there exists a Grothendieck space such that factors through Then is
Proof. More generally,
we will prove that, given , the adjoint semigroup is strongly continuous for if the operator factors through
a Grothendieck space .
Let be a positive
number. There exist a Grothendieck space and bounded
linear operators and such that the
following diagram is commutative:(3.2) For every , the following diagram also commutes, due to
semigroup properties: (3.3) Hence is β-continuous. If and then But is a
Grothendieck space, and consequently From this, we
can deduce that is weakly
continuous for . Finally, is -continuous
for , which implies that is strongly
continuous.
Remark 3.2. Our proof that semigroups factorizing through Grothendieck spaces have adjoint semigroup can be adapted to prove that the adjoint of a -semigroup on a Grothendieck space is also a -semigroup. This result can also be obtained by combining the results of 2.3.2 and 2.3.3 from [12].
Remark 3.3. Since reflexive Banach spaces are Grothendieck spaces, this gives an alternative proof that -semigroups of weakly compact operators have adjoint semigroups which are thanks to the Davis, Figiel, Johnson, and Pelczynski factorization scheme (see [8]).
Remark 3.4. Theorem 3.1 also has applications in optimal control theory. See [7] for details.
The following theorem shows, in the spirit of Remark 3.3, new examples of semigroups satisfying the hypotheses of Theorem 3.1.
Theorem 3.5. Let be a strongly continuous semigroup on an -space. If, for does not contain any isomorphic copy of , then is a compact semigroup.
Proof. Let be an -space and a strongly continuous semigroup such that for does not contain any isomorphic copy of . Then applies bounded sets onto sets which contain a weakly Cauchy sequence. Since -spaces are weakly sequentially complete, applies bounded sets onto weakly compact sets, due to the Eberlein-Smulian theorem. Therefore is weakly compact. Since -spaces have the Dunford-Pettis property, the square of a weakly compact operator is compact; hence for we have with being weakly compact, is compact.
Corollary 3.6. Every infinite-dimensional -space contains a copy of .
Proof. If not, we consider the semigroup defined, for each by , the identity on , which is strongly continuous and hence compact, and, by the Riesz lemma, is finite-dimensional.
We finish this section with two results related to the aim of finding a characterization of the space of strong continuity of .
Theorem 3.7. If is -reflexive under and is isomorphic to a dual Banach space, then is
Proof. is -reflexive if
and only if is -reflexive (see
[2]). If is -reflexive,
then the resolvent is weakly
compact. Since we can conclude that each -reflexive
Banach space is necessarily weakly compactly generated.
Then is weakly
compactly generated and therefore has the
Radon-Nikodym property since weakly compactly generated dual Banach spaces have
that property (see [13]). Now [2, Corollary 6.2.4] is applied.
Theorem 3.8. If is an -space or an -space, and is a -semigroup on , then is strongly continuous if and only if has bounded generator.
Proof. If is an -space,
then is an -space
and therefore there exists such that is
isometrically isomorphic to (see [14, page 18] for details). So is
isometrically isomorphic to , which is a Grothendieck space with the
Dunford-Pettis property. Since is a -semigroup, it
has bounded generator, by the Lotz theorem. So has bounded
generator.
Now we suppose that is an -space
and is strongly
continuous. By [12, Lemma II.3.2], is strongly
continuous. Since is a
Grothendieck space with the Dunford-Pettis property, it has bounded generator.
Therefore has bounded
generator.
3.1. The Weak Measurability of the Adjoint Semigroup
Definition 3.9. Let be a compact Hausdorff space. A function is said to be universally measurable if it is -measurable for all finite positive regular Borel measures on A function with a Banach space, is universally weakly measurable if is universally measurable for all is called universally Pettis integrable if it is Pettis integrable with respect to every
The following theorem of Riddle-Saab and Uhl (see [15]) is useful in providing examples of -semigroups for which
Theorem 3.10. Let be a separable Banach space and suppose that is a bounded, universally weakly measurable function. Then is universally Pettis integrable.
Remark 3.11. If is weakly Borel measurable, that is, for all and the map is weakly Borel measurable on it follows from Theorem 3.10 that is Pettis integrable. Combining this with Corollary 2.5 and the notes immediately following it, we get.
Corollary 3.12. Suppose that is separable. If is weakly Borel measurable, then .
Remark 3.13. It should be pointed out that weak measurability does not imply strong measurability. For example, let JF be the James function space, defined as the completion of the linear span of the characteristic functions of subintervals of with respect to the norm where the supremum runs over all partitions of . Define on JF by It is shown [2, pages 159-160] that the adjoint semigroup is weakly Borel measurable (and hence Pettis integrable) but not . In particular, it cannot be strongly measurable.
As it has been noted by van Neerven, as a consequence of the theorem of Odell-Rosenthal (see [16]), if is separable and does not contain a closed subspace isomorphic to then each is the weakβ-limit of some sequence in
If is a -semigroup on such a space, then is the pointwise limit of the continuous functions which implies that it is Borel measurable. From this, we can deduce that
Now, using the WRNP of the dual space of any space with no copy of we will prove that if factors through a separable space without copy of then is weakly measurable, thus giving some generality to the former results.
We will begin with a weakβ version of the theorem of Riddle-Saab and Uhl.
Theorem 3.14. Let be a Banach space with no copy of and suppose that is a bounded, universally weakly measurable function. Then is weak*-equivalent to a Pettis integrable function.
Proof. Let be the weakβ-integral of that is, for each and . is weaklyβ-countably additive. does not
contain a subspace isomorphic to Then, by a
classic result of Bessaga and Pelczynski (see [17, pages 48-49]), does not
contain a copy of By [5, Theorem 4.2, pages 197-198] (see also [3, I.4.7]), is a measure in
the strong topology of
Now we use the WRNP of : there exists an -Pettis
integrable function such that By (3.8) and (3.9),
we conclude that ββ-almost
everywhere, for all
Theorem 3.15. Let be a Banach space and let be a -semigroup defined on If for every factors through a separable Banach space with no copy of then is weakly Borel measurable.
Proof. Let be any closed and
bounded interval contained in There exists a
Banach space with no copy of and bounded
linear operators and such that the
following diagram is commutative: (3.10) For every the following
diagram also commutes, due to semigroup property: (3.11) Then is weakβ-continuous and hence Gelfand
integrable with respect to the Lebesgue measure on
For each we define where is a countably
additive vector measure which is also a vector measure in the strong topology,
by the same argument used in the proof of Theorem 3.14. On the other hand, we
have that is absolutely
continuous with respect to the Lebesgue measure on
By the WRNP of there exists a
Pettis-integrable function such that Let be a dense
subset in From (3.12) and
(3.13), we have for each
Let denote the
Lebesgue measure on According to
(3.14), there exists , such that for every
Now, take then and for every and
Since is dense in , we have that for every and hence is weakly Borel
measurable. Finally is also weakly Borel measurable.
Theorem 3.16. Let and be as in Theorem 3.15. Then .
Proof. We are going
to prove that is Pettis
integrable.
As in Theorem 3.15, Let by any closed
bounded interval. We have the following factorization scheme: (3.19)we also have (3.20)Then, using the same argument, we conclude that there
exists a Pettis-integrable function such that but then and it is easy to see that is Pettis integrable.
Remark 3.17. A Banach space is said to have
the Lotz property if every strongly continuous semigroup on has bounded
generator. It is noticeable that Leung [18] has found a Lotz space without the
Dunford-Pettis property, and it is also noticeable that to be a Grothendieck
space is not enough to ensure the Lotz property, since in , , we can easily
define a -semigroup
which is not uniformly continuous by means of where is the standard
unit basis.
Reworking on van Neerven results, we can show the
relationship that exists among some of them (note that they were stated
separately), thus giving necessary and sufficient conditions to ensure the
uniform continuity of the adjoint of a strongly continuous semigroup defined on
a Banach space whose dual has the Lotz property. This can be done as follows.
Let be a complex
Banach space such that has the Lotz
property, and let be a -semigroup on
with
infinitesimal generator
The following statements are equivalent.(1) is uniformly
continuous. (2)
is strongly
continuous. (3) for all (4) for all where
is the Gelfand
integral of on
with respect to
the Lebesgue measure. (5)The quotient semigroup on
is strongly
continuous.
Acknowledgment
This work is partially supported by CDCH of ULA under Project C-1335-05-05-A and by Universidad SimΓ³n Bolivar, Caracas, Venezuela.