Abstract

The purpose of the present paper is to investigate some subordination- and superordination-preserving properties of certain integral operators defined on the space of meromorphic functions in the punctured open unit disk. The sandwich-type theorem for these integral operators is also considered.

1. Introduction

Let denote the class of analytic functions in the open unit disk . For , let

Let and be members of . The function is said to be subordinate to , or is said to be superordinate to , if there exists a function analytic in , with and , and such that In such a case, we write or If the function is univalent in , then we have if and only if and (cf. [1]).

Definition 1.1 (see [1]). Let and let be univalent in . If is analytic in and satisfies the differential subordination
then is called a solution of the differential subordination. The univalent function is called a dominant of the solutions of the differential subordination, or more simply a dominant if for all satisfying (1.2). A dominant that satisfies for all dominants of (1.2) is said to be the best dominant.

Definition 1.2 (see [2]). Let and let be analytic in . If and are univalent in and satisfy the differential superordination
then is called a solution of the differential superordination. An analytic function is called a subordinant of the solutions of the differential superordination, or more simply a subordinant if for all satisfying (1.3). A univalent subordinant that satisfies for all subordinants of (1.3) is said to be the best subordinant.

Definition 1.3 (see [2]). One denotes by the class of functions that are analytic and injective on , where
and are such that for .

Let denote the class of functions of the form

which are analytic in the punctured open unit disk . Let and be the subclasses of consisting of all functions which are, respectively, meromorphic starlike and meromorphic convex in (see, for details, [35]).

For a function , we introduce the following integral operators defined by

The integral operator defined by (1.6) has been extensively studied by many authors [610] with suitable restrictions on the parameters and , and for belonging to some favored classes of meromorphic functions. In particular, Bajpai [6] showed that the integral operator belongs to the classes and , whenever belongs to the classes and , respectively. Moreover, the operator for the case is related to the generalized Libera transform introduced by Stević (see, e.g., [1113]).

Making use of the principle of subordination between analytic functions, Miller et al. [14] obtained some subordination-preserving properties for certain integral operators (see also [15]). Moreover, Miller and Mocanu [2] considered differential superordinations as the dual concept of differential subordinations (see also [16]). In the present paper, we obtain the subordination- and superordination-preserving properties of the integral operator defined by (1.6) with the sandwich-type theorem.

Throughout this paper, we denote the class by

where is the integral operator defined by (1.6). For various interesting developments involving functions in the class , the reader may be referred, for example, to the work of Dwivedi et al. [9].

2. A Set of Lemmas

The following lemmas will be required in our present investigation.

Lemma 2.1 (see [17]). Suppose that the function satisfies the following condition:
for all real and , where is a positive integer. If the function is analytic in and
then

Lemma 2.2 (see [5]). Let with and let with . If , then the solution of the differential equation
is analytic in and satisfies

Lemma 2.3 (see [1]). Let with and let be analytic in with and . If is not subordinate to , then there exist points and , for which

A function defined on is the subordination chain (or Löwner chain) if is analytic and univalent in for all , is continuously differentiable on for all and for .

Lemma 2.4 (see [2]). Let , set and let . If is a subordination chain and , then
implies that
Furthermore, if has a univalent solution , then is the best subordinant.

Lemma 2.5 (see [18]). The function with and is a subordination chain if and only if

3. Main Results

Subordination theorem involving the integral operator defined by (1.6) is contained in Theorem 3.1 below.

Theorem 3.1. Let . Suppose that
where
Then, the subordination
implies that
where is the integral operator defined by (1.6). Moreover, the function is the best dominant.

Proof. Let us define the functions and by
respectively. Without loss of generality, we can assume that is analytic and univalent on and that

We first show that if the function is defined by
then
In terms of the function involved in (3.1), the definition (1.6) readily yields
We also have
By a simple calculation with (3.9) and (3.10), we obtain the relationship
From (3.1), we note that
and by using Lemma 2.2, we conclude that the differential equation (3.11) has a solution with
Let us put
where is given by (3.2). From (3.1), (3.11), and (3.14), we obtain
Now, we proceed to show that for all real and . From (3.14), we have where For given by (3.2), we note that the coefficient of in the quadratic expression given by (3.17) is positive or equal to zero. Moreover, for the assumed value of given by (3.2), the quadratic expression by in (3.17) is a perfect square. Hence, from (3.16), we see that for all real and . Thus, by using Lemma 2.1, we conclude that
that is, is convex in .
Next, we prove that the subordination condition (3.3) implies that
for the functions and defined by (3.5). For this purpose, we consider the function given by
Since is convex in and , we obtain that
Therefore, by virtue of Lemma 2.5, is a subordination chain. We observe from the definition of a subordination chain that
This implies that

Now suppose that is not subordinate to , then by Lemma 2.3, there exist points and such that
Hence, we have by virtue of the subordination condition (3.3). This contradicts the above observation that . Therefore, the subordination condition (3.3) must imply the subordination given by (3.19). Considering , we see that the function is the best dominant. This evidently completes the proof of Theorem 3.1.

Remark 3.2. We note that given by (3.2) in Theorem 3.1 satisfies the inequality .

We next prove a dual problem of Theorem 3.1 in the sense that the subordinations are replaced by superordinations.

Theorem 3.3. Let . Suppose that
where is given by (3.2), is univalent in and , where is the integral operator defined by (1.6). Then, the superordination
implies that
Moreover, the function is the best subordinant.

Proof. The first part of the proof is similar to that of Theorem 3.1 and so we will use the same notation as in the proof of Theorem 3.1. Now let us define the functions and , respectively, by (3.5). We first note that by using (3.9) and (3.10), we obtain After a simple calculation, (3.29) yields the relationship where the function is defined by (3.7). Then, by using the same method as in the proof of Theorem 3.1, we can prove that
that is, defined by (3.5) is convex(univalent) in .
Next, we prove that the superordination condition (3.27) implies that
Now, consider the function defined by
Since is convex and , we can prove easily that is a subordination chain as in the proof of Theorem 3.1. Therefore, according to Lemma 2.4, we conclude that the superordination condition (3.27) must imply the superordination given by (3.32). Furthermore, since the differential equation (3.29) has the univalent solution , it is the best subordinant of the given differential superordination. Therefore, we complete the proof of Theorem 3.3.

If we combine Theorems 3.1 and 3.3, then we obtain the following sandwich-type theorem.

Theorem 3.4. Let . Suppose that
where is given by (3.2), is univalent in , and , where is the integral operator defined by (1.6). Then, the subordination
implies that
Moreover, the functions and are the best subordinant and the best dominant, respectively.

The assumption of Theorem 3.4, that the functions and need to be univalent in , may be replaced by another condition in the following result.

Corollary 3.5. Let . Suppose that the condition (3.34) is satisfied and
where is given by (3.2). Then, the subordination
implies that
where is the integral operator defined by (1.6). Moreover, the functions and are the best subordinant and the best dominant, respectively.

Proof. In order to prove Corollary 3.5, we have to show that the condition (3.37) implies the univalence of and
Since from Remark 3.2, the condition (3.37) means that is a close-to-convex function in (see [19]) and hence is univalent in . Furthermore, by using the same techniques as in the proof of Theorem 3.4, we can prove the convexity (univalence) of and so the details may be omitted. Therefore, by applying Theorem 3.4, we obtain Corollary 3.5.

By setting in Theorem 3.4, so that , we deduce the following consequence of Theorem 3.4.

Corollary 3.6. Let . Suppose that
is univalent in , and , where is the integral operator defined by (1.6) with . Then, the subordination
implies that
Moreover, the functions and are the best subordinant and the best dominant, respectively.

If we take in Theorem 3.4, then we are easily led to the following result.

Corollary 3.7. Let . Suppose that
is univalent in , and , where is the integral operator defined by (1.6) with . Then, the subordination:
implies that
Moreover, the functions and are the best subordinant and the best dominant, respectively.

Acknowledgments

The authors would like to express their gratitude to Professor S. Stević for his valuable suggestions. This research was supported by Kyungsung University Grants in 2008.