Abstract

We consider the generalized shift operator, associated with the Dunkl operator Λ𝛼(𝑓)(𝑥)=(𝑑/𝑑𝑥)𝑓(𝑥)+((2𝛼+1)/𝑥)((𝑓(𝑥)𝑓(𝑥))/2), 𝛼>1/2. We study the boundedness of the Dunkl-type fractional maximal operator 𝑀𝛽 in the Dunkl-type Morrey space 𝐿𝑝,𝜆,𝛼(), 0𝜆<2𝛼+2. We obtain necessary and sufficient conditions on the parameters for the boundedness 𝑀𝛽, 0𝛽<2𝛼+2 from the spaces 𝐿𝑝,𝜆,𝛼() to the spaces 𝐿𝑞,𝜆,𝛼(), 1<𝑝𝑞<, and from the spaces 𝐿1,𝜆,𝛼() to the weak spaces 𝑊𝐿𝑞,𝜆,𝛼(), 1<𝑞<. As an application of this result, we get the boundedness of 𝑀𝛽 from the Dunkl-type Besov-Morrey spaces 𝐵𝑠𝑝𝜃,𝜆,𝛼() to the spaces 𝐵𝑠𝑞𝜃,𝜆,𝛼(), 1<𝑝𝑞<, 0𝜆<2𝛼+2, 1/𝑝1/𝑞=𝛽/(2𝛼+2𝜆), 1𝜃, and 0<𝑠<1.

1. Introduction

On the real line, the Dunkl operators Λ𝛼 are differential-difference operators introduced in 1989 by Dunkl [1]. For a real parameter 𝛼>1/2, we consider the Dunkl operator, associated with the reflection group 2 on : Λ𝛼𝑑(𝑓)(𝑥)=𝑑𝑥𝑓(𝑥)+2𝛼+1𝑥𝑓(𝑥)𝑓(𝑥)2.(1.1)

In the theory of partial differential equations, together with weighted 𝐿𝑝,𝑤(𝑛) spaces, Morrey spaces 𝐿𝑝,𝜆(𝑛) play an important role. Morrey spaces were introduced by Morrey in 1938 in connection with certain problems in elliptic partial differential equations and calculus of variations (see [2]).

The Hardy-Littlewood maximal function, fractional maximal function, and fractional integrals are important technical tools in harmonic analysis, theory of functions, and partial differential equations. In the works [35], the maximal operator and in [6, 7] the fractional maximal operator associated with the Dunkl operator on were studied. In this work, we study the boundedness of the fractional maximal operator 𝑀𝛽 (Dunkl-type fractional maximal operator) in Morrey spaces 𝐿𝑝,𝜆,𝛼() (Dunkl-type Morrey spaces) associated with the Dunkl operator on . We obtain the necessary and sufficient conditions for the boundedness of the operator 𝑀𝛽 from the spaces 𝐿𝑝,𝜆,𝛼() to 𝐿𝑞,𝜆,𝛼(), 1<𝑝𝑞<, and from the spaces 𝐿1,𝜆,𝛼() to the weak spaces 𝑊𝐿𝑞,𝜆,𝛼(), 1<𝑞<.

The paper is organized as follows. In Section 2, we present some definitions and auxiliary results. In Section 3, we give our main result on the boundedness of the operator 𝑀𝛽 in 𝐿𝑝,𝜆,𝛼(). We obtain necessary and sufficient conditions on the parameters for the boundedness of the operator 𝑀𝛽 from the spaces 𝐿𝑝,𝜆,𝛼() to the spaces 𝐿𝑞,𝜆,𝛼(), 1<𝑝𝑞<, and from the spaces 𝐿1,𝜆,𝛼() to the weak spaces 𝑊𝐿𝑞,𝜆,𝛼(), 1<𝑞<. As an application of this result, in Section 4 we prove the boundedness of the operator 𝑀𝛽 from the Dunkl-type Besov-Morrey spaces 𝐵𝑠𝑝𝜃,𝜆,𝛼() to the spaces 𝐵𝑠𝑞𝜃,𝜆,𝛼(), 1<𝑝𝑞<, 0𝜆<2𝛼+2, 1/𝑝1/𝑞=𝛽/(2𝛼+2𝜆), 1𝜃, and 0<𝑠<1.

Finally, we mention that, 𝐶 will be always used to denote a suitable positive constant that is not necessarily the same in each occurrence.

2. Preliminaries

Let 𝛼>1/2 be a fixed number and 𝜇𝛼 be the weighted Lebesgue measure on , given by 𝑑𝜇𝛼(2𝑥)=𝛼+1Γ(𝛼+1)1|𝑥|2𝛼+1𝑑𝑥.(2.1)

For every 1𝑝, we denote by 𝐿𝑝,𝛼()=𝐿𝑝(𝑑𝜇𝛼)() the spaces of complex-valued functions 𝑓, measurable on such that 𝑓𝑝,𝛼=||||𝑓(𝑥)𝑝𝑑𝜇𝛼(𝑥)1/𝑝[<if𝑝1,),𝑓,𝛼=esssup𝑥||||𝑓(𝑥)if𝑝=.(2.2)

For 1𝑝< we denote by 𝑊𝐿𝑝,𝛼(), the weak 𝐿𝑝,𝛼() spaces defined as the set of locally integrable functions 𝑓(𝑥), 𝑥 with the finite norm 𝑓𝑊𝐿𝑝,𝛼=sup𝑟>0𝑟𝜇𝛼||||𝑥𝑓(𝑥)>𝑟1/𝑝.(2.3)

Note that 𝐿𝑝,𝛼𝑊𝐿𝑝,𝛼,𝑓𝑊𝐿𝑝,𝛼𝑓𝑝,𝛼𝑓𝐿𝑝,𝛼().(2.4)

For all 𝑥,𝑦,𝑧, we put 𝑊𝛼(𝑥,𝑦,𝑧)=1𝜎𝑥,𝑦,𝑧+𝜎𝑧,𝑥,𝑦+𝜎𝑧,𝑦,𝑥Δ𝛼(𝑥,𝑦,𝑧),(2.5) where 𝜎𝑥,𝑦,𝑧𝑥=2+𝑦2𝑧22𝑥𝑦if𝑥,𝑦0,0otherwise(2.6) and Δ𝛼 is the Bessel kernel given by Δ𝛼𝑑(𝑥,𝑦,𝑧)=𝛼||𝑦|||𝑥|+2𝑧2𝑧2||𝑦|||𝑥|2𝛼1/2||||𝑥𝑦𝑧2𝛼if|𝑧|𝐴𝑥,𝑦,0otherwise,(2.7) where 𝑑𝛼=(Γ(𝛼+1))2/(2𝛼1𝜋Γ(𝛼+1/2)) and 𝐴𝑥,𝑦=[||𝑥||𝑦||,|𝑥|+|𝑦|].

In the sequel we consider the signed measure 𝜈𝑥,𝑦, on , given by 𝜈𝑥,𝑦𝑊=𝛼(𝑥,𝑦,𝑧)𝑑𝜇𝛼(𝑧)if𝑥,𝑦0,𝑑𝛿𝑥(𝑧)if𝑦=0,𝑑𝛿𝑦(𝑧)if𝑥=0.(2.8)

For 𝑥,𝑦 and 𝑓 being a continuous function on , the Dunkl translation operator 𝜏𝑥 is given by 𝜏𝑥𝑓(𝑦)=𝑓(𝑧)𝑑𝜈𝑥,𝑦(𝑧).(2.9)

Using the change of variable 𝑧=Ψ(𝑥,𝑦,𝜃)=𝑥2+𝑦22𝑥𝑦cos𝜃, we have also (see [8]) 𝜏𝑥𝑓(𝑦)=𝐶𝛼𝜋0𝑓(Ψ)+𝑓(Ψ)+𝑥+𝑦Ψ(𝑓(Ψ)𝑓(Ψ))𝑑𝜈𝛼(𝜃),(2.10) where 𝑑𝜈𝛼(𝜃)=(1cos𝜃)sin2𝛼𝜃𝑑𝜃 and 𝐶𝛼=Γ(𝛼+1)/2𝜋Γ(𝛼+1/2).

Proposition 2.1 (see Soltani [9]). For all 𝑥 the operator 𝜏𝑥 extends to 𝐿𝑝,𝛼(), 𝑝1 and we have for 𝑓𝐿𝑝,𝛼(), 𝜏𝑥𝑓𝐿𝑝,𝛼4𝑓𝐿𝑝,𝛼.(2.11)

Let 𝐵(𝑥,𝑟)={𝑦|𝑦|]max{0,|𝑥|𝑟}, |𝑥|+𝑟[},𝑟>0, and 𝑏𝛼=[2𝛼+1(𝛼+1)Γ(𝛼+1)]1. Then 𝐵(0,𝑟)=]𝑟,𝑟[ and 𝜇𝛼𝐵(0,𝑟)=𝑏𝛼𝑟2𝛼+2.

Now we define the Dunkl-type fractional maximal function (see [35]) by 𝑀𝛽𝑓(𝑥)=sup𝑟>0𝜇𝛼𝐵(0,𝑟)1+𝛽/(2𝛼+2)𝐵(0,𝑟)𝜏𝑥||𝑓||(𝑦)𝑑𝜇𝛼(𝑦),0𝛽<2𝛼+2.(2.12) If 𝛽=0, then 𝑀=𝑀0 is the Dunkl-type maximal operator.

In [35] was proved the following theorem (see also [10]).

Theorem 2.2. (1) If 𝑓𝐿1,𝛼(), then for every 𝛽>0𝜇𝛼{𝐶𝑥𝑀𝑓(𝑥)>𝛽}𝛽𝑓𝐿1,𝛼,(2.13) where 𝐶>0 is independent of 𝑓.
(2) If 𝑓𝐿𝑝,𝛼(),1<𝑝, then 𝑀𝑓𝐿𝑝,𝛼() and 𝑀𝑓𝐿𝑝,𝛼𝐶𝑝𝑓𝐿𝑝,𝛼,(2.14) where 𝐶𝑝>0 is independent of 𝑓.

Definition 2.3. Let 1𝑝<, 0𝜆2𝛼+2. We denote by 𝐿𝑝,𝜆,𝛼() Morrey space ( Dunkl-type Morrey space), associated with the Dunkl operator as the set of locally integrable functions 𝑓(𝑥), 𝑥, with the finite norm 𝑓𝑝,𝜆,𝛼=sup𝑥,𝑟>0𝑟𝜆𝐵(0,𝑟)𝜏𝑥||||𝑓(𝑦)𝑝𝑑𝜇𝛼(𝑦)1/𝑝.(2.15)

Note that 𝐿𝑝,0,𝛼()=𝐿𝑝,𝛼(), and if 𝜆<0 or 𝜆>2𝛼+2, then 𝐿𝑝,𝜆,𝛼()=Θ, where Θ is the set of all functions equivalent to 0 on (see also [7]).

Definition 2.4. Let 1𝑝<and 0𝜆2𝛼+2. We denote by 𝑊𝐿𝑝,𝜆,𝛼() a weak Dunkl-type Morrey space as the set of locally integrable functions 𝑓(𝑥), 𝑥 with finite norm 𝑓𝑊𝐿𝑝,𝜆,𝛼=sup𝑡>0𝑡sup𝑥,𝑟>0𝑟𝜆{𝑦𝐵(0,𝑟)𝜏𝑥|𝑓(𝑦)|>𝑡}𝑑𝜇𝛼(𝑦)1/𝑝.(2.16)

We note that 𝐿𝑝,𝜆,𝛼()𝑊𝐿𝑝,𝜆,𝛼(),𝑓𝑊𝐿𝑝,𝜆,𝛼𝑓𝑝,𝜆,𝛼.(2.17)

3. Main Results

The following theorem is our main result in which we obtain the necessary and sufficient conditions for the Dunkl-type fractional maximal operator 𝑀𝛽 to be bounded from the spaces 𝐿𝑝,𝜆,𝛼() to 𝐿𝑞,𝜆,𝛼(), 1<𝑝<𝑞< and from the spaces 𝐿1,𝜆,𝛼() to the weak spaces 𝑊𝐿𝑞,𝜆,𝛼(), 1<𝑞<.

Theorem 3.1. Let 0𝛽<2𝛼+2, 0𝜆<2𝛼+2, and 1𝑝(2𝛼+2𝜆)/𝛽. (1)If 𝑝=1, then the condition 11/𝑞=𝛽/(2𝛼+2𝜆) is necessary and sufficient for the boundedness of 𝑀𝛽 from 𝐿1,𝜆,𝛼() to 𝑊𝐿𝑞,𝜆,𝛼().(2)If 1<𝑝<(2𝛼+2𝜆)/𝛽, then the condition (1/𝑝)(1/𝑞)=𝛽/(2𝛼+2𝜆) is necessary and sufficient for the boundedness of 𝑀𝛽 from 𝐿𝑝,𝜆,𝛼() to 𝐿𝑞,𝜆,𝛼().(3)If 𝑝=(2𝛼+2𝜆)/𝛽, then 𝑀𝛽 is bounded from 𝐿𝑝,𝜆,𝛼() to 𝐿().

For 1𝑝,𝜃, 0𝜆<2𝛼+2, and 0<𝑠<2, the Dunkl-type Besov-Morrey 𝐵𝑠𝑝𝜃,𝜆,𝛼() consists of all functions 𝑓 in 𝐿𝑝,𝜆,𝛼() so that 𝑓𝐵𝑠𝑝𝜃,𝜆,𝛼=𝑓𝐿𝑝,𝜆,𝛼+𝜏𝑥𝑓()𝑓()𝜃𝐿𝑝,𝜆,𝛼|𝑥|2𝛼+2+𝑠𝜃𝑑𝜇𝛼(𝑥)1/𝜃<.(3.1)

Besov spaces in the setting of the Dunkl operators were studied by Abdelkefi and Sifi [11], Bouguila et al. [12], Guliyev and Mammadov [10], and Kamoun [13]. In the following theorem, we prove the boundedness of the Dunkl-type fractional maximal operator in the Dunkl-type Besov-Morrey spaces.

Theorem 3.2. For 1<𝑝𝑞<,0𝜆<2𝛼+2, (1/𝑝)(1/𝑞)=𝛽/(2𝛼+2𝜆), 1𝜃, and 0<𝑠<1, the Dunkl-type fractional maximal operator 𝑀𝛽 is bounded from 𝐵𝑠𝑝𝜃,𝜆,𝛼() to 𝐵𝑠𝑞𝜃,𝜆,𝛼(). More precisely, there is a constant 𝐶>0 such that 𝑀𝛽𝑓𝐵𝑠𝑞𝜃,𝜆,𝛼𝐶𝑓𝐵𝑠𝑝𝜃,𝜆,𝛼(3.2) hold for all 𝑓𝐵𝑠𝑝𝜃,𝜆,𝛼().

Remark 3.3. Note that Theorem 3.2 in the case 𝜆=0 was proved in [10].

4. Boundedness of the Dunkl-Type Fractional Maximal Operator in the Dunkl-Type Morrey Spaces

In the following theorem, we obtain the boundedness of the Dunkl-type fractional maximal operator 𝑀𝛽 in the Dunkl-type Morrey spaces 𝐿𝑝,𝜆,𝛼().

Theorem 4.1. Let 0𝛽<2𝛼+2, 0𝜆<2𝛼+2, 𝑓𝐿𝑝,𝜆,𝛼(), and 1𝑝(2𝛼+2𝜆)/𝛽. (1)If 𝑝=1 and 11/𝑞=𝛽/(2𝛼+2𝜆), then 𝑀𝛽𝑓𝑊𝐿𝑞,𝜆,𝛼() and 𝑀𝛽𝑓𝑊𝐿𝑞,𝜆,𝛼𝐶𝑓1,𝜆,𝛼,(4.1) where 𝐶>0 is independent of 𝑓.(2)If 1<𝑝<(2𝛼+2𝜆)/𝛽 and (1/𝑝)(1/𝑞)=𝛽/(2𝛼+2𝜆), then 𝑀𝛽𝑓𝐿𝑞,𝜆,𝛼() and 𝑀𝛽𝑓𝑞,𝜆,𝛼𝐶𝑓𝑝,𝜆,𝛼,(4.2) where 𝐶>0 is independent of 𝑓.(3)If 𝑝=(2𝛼+2𝜆)/𝛽 and 𝑞=, then 𝑀𝛽𝑓𝐿() and 𝑀𝛽𝑓𝑏𝛼1/𝑝(2𝛼+2)𝑓𝑝,𝜆,𝛼.(4.3)

Proof. The maximal function 𝑀𝑓(𝑥) may be interpreted as a maximal function defined on a space of homogeneous type. By this we mean a topological space 𝑋 equipped with a continuous pseudometric 𝜌 and a positive measure 𝜇 satisfying 𝜇𝐸(𝑥,2𝑟)𝐶0𝜇𝐸(𝑥,𝑟)(4.4) with a constant 𝐶0 being independent of 𝑥 and 𝑟>0. Here 𝐸(𝑥,𝑟)={𝑦𝑋𝜌(𝑥,𝑦)<𝑟},𝜌(𝑥,𝑦)=|𝑥𝑦|. Let (𝑋,𝜌,𝜇) be a space of homogeneous type, where 𝑋=, 𝜌(𝑥,𝑦)=|𝑥𝑦|, and 𝑑𝜇(𝑥)=𝑑𝜇𝛼(𝑥). It is clear that this measure satisfies the doubling condition (4.4). Define 𝑀𝜇𝑓(𝑥)=sup𝑟>0(𝜇𝐸(𝑥,𝑟))1𝐸(𝑥,𝑟)||||𝑓(𝑦)𝑑𝜇(𝑦).(4.5)
It is well known that the maximal operator 𝑀𝜇 is bounded from 𝐿1,𝜆(𝑋,𝜇) to 𝑊𝐿1,𝜆(𝑋,𝜇) and is bounded on 𝐿𝑝,𝜆(𝑋,𝜇) for 1<𝑝<, 0𝜆<2𝛼+2 (see [14, 15]).
The following inequality was proved in [6]𝑀𝑓(𝑥)𝐶𝑀𝜇𝑓(𝑥),(4.6) where 𝐶>0 is independent of 𝑓.
Then from (4.6) we get the boundedness of the operator 𝑀 from 𝐿1,𝜆,𝛼() to 𝑊𝐿1,𝜆,𝛼() and on 𝐿𝑝,𝜆,𝛼(), 1<𝑝<. Thus in the case 𝛽=0 we complete the proof of (1) and (2).
Let 𝑡>0, 0<𝛽<2𝛼+2, 𝑓𝐿𝑝,𝜆,𝛼(), 1𝑝(2𝛼+2𝜆)/𝛽 and (1/𝑝)(1/𝑞)=𝛽/(2𝛼+2𝜆). Applying the Hölders inequality we have𝑀𝛽𝑓(𝑥)=maxsup𝑟𝑡𝜇𝛼𝐵(0,𝑟)𝛽/(2𝛼+2)1𝐵(0,𝑟)𝜏𝑥||||𝑓(𝑦)𝑑𝜇𝛼(𝑦),sup𝑟<𝑡𝜇𝛼𝐵(0,𝑟)𝛽/(2𝛼+2)1𝐵(0,𝑟)𝜏𝑥||||𝑓(𝑦)𝑑𝜇𝛼(𝑦)𝑏𝛼𝛽/(2𝛼+2)𝑏max𝛼1/𝑝𝑡𝛽(2𝛼+2𝜆)/𝑝𝑓𝑝,𝜆,𝛼,𝑡𝛽.𝑀𝑓(𝑥)(4.7)
Therefore, for all 𝑡>0, we get𝑀𝛽𝑓(𝑥)𝑏𝛼𝛽/(2𝛼+2)𝑏𝛼1/𝑝𝑡𝛽(2𝛼+2𝜆)/𝑝+𝑓𝑝,𝜆,𝛼,𝑡𝛽𝑀𝑓(𝑥).(4.8) The minimum value of the right-hand side (4.8) is attained at 𝑡=2𝛼+2𝜆𝑝𝑏𝛼1/𝑝𝑓𝑝,𝜆,𝛼𝑀𝑓(𝑥)𝑝/(2𝛼+2𝜆)(4.9) and hence 𝑀𝛽𝑓(𝑥)𝑏𝛼𝛽/(2𝛼+2)𝛽/(2𝛼+2𝜆)𝑓1𝑝/𝑞𝑝,𝜆,𝛼(𝑀𝑓(𝑥))𝑝/𝑞.(4.10)
Then for 1<𝑝(2𝛼+2𝜆)/𝛽 from (4.10), we have𝑀𝛽𝑓𝑞,𝜆,𝛼=sup𝑟>0𝑟𝜆𝐵(0,𝑟)𝜏𝑥𝑀𝛽𝑓(𝑦)𝑞𝑑𝜇𝛼(𝑦)1/𝑞𝑏𝛼𝛽/(2𝛼+2)𝛽/(2𝛼+2𝜆)𝑓1𝑝/𝑞𝑝,𝜆,𝛼𝑟𝜆𝐵(0,𝑟)𝜏𝑥(𝑀𝑓(𝑦))𝑝𝑑𝜇𝛼(𝑦)1/𝑞𝑏𝛼𝛽/(2𝛼+2)𝛽/(2𝛼+2𝜆)𝑓1𝑝/𝑞𝑝,𝜆,𝛼𝑀𝑓𝑝/𝑞𝑝,𝜆,𝛼𝐶𝑓𝑝,𝜆,𝛼,(4.11) where 𝐶>0 is independent of 𝑓.
Also for 𝑝=1 from (4.10) we have𝑀𝛽𝑓𝑊𝐿𝑞,𝜆,𝛼=sup𝑡>0𝑡sup𝑥,𝑟>0𝑟𝜆{𝑦𝐵(0,𝑟)𝜏𝑥𝑀𝛽𝑓(𝑦)>𝑡}𝑑𝜇𝛼(𝑦)1/𝑞sup𝑡>0𝑡sup𝑥,𝑟>0𝑟𝜆𝑦𝐵(0,𝑟)𝜏𝑥𝑀𝑓(𝑦)>𝑏𝛼𝛽𝑞/(2𝛼+2𝜆)+𝛽𝑞/(2𝛼+2)𝑓1𝑞1,𝜆,𝛼𝑡𝑞𝑑𝜇𝛼(𝑦)1/𝑞𝑏𝛼𝛽/(2𝛼+2𝜆)𝛽/(2𝛼+2)𝑓11/𝑞1,𝜆,𝛼𝑀𝑓1/𝑞𝑊𝐿1,𝜆,𝛼𝐶𝑓1,𝜆,𝛼,(4.12) where 𝐶>0 is independent of 𝑓.
Therefore, the case 𝛽>0 complete the proof of (1) and (2).
(3) Let 𝑝=(2𝛼+2𝜆)/𝛽, 𝑓𝐿𝑝,𝜆,𝛼(); then applying Hölders inequality, we obtain𝜇𝛼𝐵(0,𝑟)1+𝛽/(2𝛼+2)𝐵(0,𝑟)𝜏𝑥||𝑓||(𝑦)𝑑𝜇𝛼(𝜇𝑦)𝛼𝐵(0,𝑟)1+𝛽/(2𝛼+2)+1/𝑝𝐵(0,𝑟)𝜏𝑥||||𝑓(𝑦)𝑝𝑑𝜇𝛼(𝑦)1/𝑝=𝑏𝛼𝜆/𝑝(2𝛼+2)𝑟𝜆𝐵(0,𝑟)𝜏𝑥||||𝑓(𝑦)𝑝𝑑𝜇𝛼(𝑦)1/𝑝𝑏𝛼𝜆/𝑝(2𝛼+2)𝑓𝑝,𝜆,𝛼.(4.13)
Thus the case 𝛽>0 completes the proof of (3).
Theorem 4.1 has been proved.

Proof of Theorem 3.1. Sufficiency part of the proof follows from Theorem 4.1.Necessity. (1) Let 1<𝑝(2𝛼+2𝜆)/𝛼 and 𝑀𝛽 be bounded from 𝐿𝑝,𝜆,𝛼() to 𝐿𝑞,𝜆,𝛼().
Define 𝑓𝑡(𝑥)=𝑓(𝑡𝑥), 𝑡>0. Then𝑓𝑡𝑝,𝜆,𝛼=𝑡(2𝛼+2)/𝑝sup𝑥,𝑟>0𝑟𝜆𝐵(0,𝑡𝑟)𝜏𝑡𝑥||||𝑓(𝑦)𝑝𝑑𝜇𝛼(𝑦)1/𝑝=𝑡(2𝛼+2𝜆)/𝑝𝑓𝑝,𝜆,𝛼(4.14) and 𝑀𝛽𝑓𝑡(𝑥)=𝑡𝛽𝑀𝛽𝑓(𝑡𝑥), 𝑀𝛽𝑓𝑡𝐿𝑞,𝜆,𝛼=𝑡𝛽sup𝑥,𝑟>0𝑟𝜆𝐵(0,𝑟)𝜏𝑡𝑥||𝑀𝛽||𝑓(𝑦)𝑞𝑑𝜇𝛼(𝑦)1/𝑞=𝑡𝛽(2𝛼+2)/𝑞sup𝑥,𝑟>0𝑟𝜆𝐵(0,𝑡𝑟)𝜏𝑥||𝑀𝛽||𝑓(𝑦)𝑞𝑑𝜇𝛼(𝑦)1/𝑞=𝑡𝛽(2𝛼+2𝜆)/𝑞𝑀𝛽𝑓𝐿𝑞,𝜆,𝛼.(4.15)
By the boundedness of 𝑀𝛽 from 𝐿𝑝,𝜆,𝛼() to 𝐿𝑞,𝜆,𝛼(),𝑀𝛽𝑓𝐿𝑞,𝜆,𝛼=𝑟𝛽+(2𝛼+2𝜆)/𝑞𝑀𝛽𝑓𝑟𝐿𝑞,𝜆,𝛼𝐶𝑟𝛽+(2𝛼+2𝜆)/𝑞𝑓𝑟𝑝,𝜆,𝛼=𝐶𝑟𝛽+(2𝛼+2𝜆)/𝑞(2𝛼+2𝜆)/𝑝𝑓𝑝,𝜆,𝛼,(4.16) where 𝐶 depends only on 𝑝, 𝛽, 𝜆, and 𝛼.
If 1/𝑝>1/𝑞+𝛽/(2𝛼+2𝜆), then for all 𝑓𝐿𝑝,𝜆,𝛼() we have 𝑀𝛽𝑓𝑞,𝜆,𝛼=0 as 𝑟0, which is impossible. Similarly, if 1/𝑝<1/𝑞+𝛽/(2𝛼+2𝜆), then for all 𝑓𝐿𝑝,𝜆,𝛼() we obtain 𝑀𝛽𝑓𝑞,𝜆,𝛼=0 as 𝑟, which is also impossible.
Therefore, we get 1/𝑝=1/𝑞+𝛽/(2𝛼+2𝜆).
Necessity. Let 𝑀𝛽 be bounded from 𝐿1,𝜆,𝛼() to 𝑊𝐿𝑞,𝜆,𝛼(). We have 𝑀𝛽𝑓𝑟𝑊𝐿𝑞,𝜆,𝛼=𝑟𝛽(2𝛼+2𝜆)/𝑞𝑀𝛽𝑓𝑊𝐿𝑞,𝜆,𝛼.(4.17)
By the boundedness of 𝑀𝛽 from 𝐿1,𝜆,𝛼() to 𝑊𝐿𝑞,𝜆,𝛼() it follows that𝑀𝛽𝑓𝑊𝐿𝑞,𝜆,𝛼=𝑟𝛽+(2𝛼+2𝜆)/𝑞𝑀𝛽𝑓𝑟𝑊𝐿𝑞,𝜆,𝛼𝐶𝑟𝛽+(2𝛼+2𝜆)/𝑞𝑓𝑟1,𝜆,𝛼=𝐶𝑟𝛽+(2𝛼+2𝜆)/𝑞(2𝛼+2)𝑓1,𝜆,𝛼,(4.18) where 𝐶 depends only on 𝛽, 𝜆, and 𝛼.
If 1<1/𝑞+𝛽/(2𝛼+2𝜆), then for all 𝑓𝐿1,𝜆,𝛼() we have 𝑀𝛽𝑓𝑊𝐿𝑞,𝜆,𝛼=0 as 𝑟0. Similarly, if 1>1/𝑞+𝛽/(2𝛼+2𝜆), then for all 𝑓𝐿1,𝜆,𝛼() we obtain 𝑀𝛽𝑓𝑊𝐿𝑞,𝜆,𝛼=0 as 𝑟.
Hence we get 1=1/𝑞+𝛽/(2𝛼+2𝜆). Thus the proof of Theorem 3.1 is completed.

Proof of Theorem 3.2. For 𝑥, let 𝜏𝑥 be the generalized translation by 𝑥. By definition of the Besov spaces, it suffices to show that 𝜏𝑥𝑀𝛽𝑓𝑀𝛽𝑓𝐿𝑞,𝜆,𝛼𝐶2𝜏𝑥𝑓𝑓𝐿𝑝,𝜆,𝛼.(4.19) It is easy to see that 𝜏𝑥 commutes with 𝑀𝛽, that is, 𝜏𝑥𝑀𝛽𝑓=𝑀𝛽(𝜏𝑥𝑓). Hence we have ||𝜏𝑥𝑀𝛽𝑓𝑀𝛽𝑓||=||𝑀𝛽𝜏𝑥𝑓𝑀𝛽𝑓||𝑀𝛽||𝜏𝑥||.𝑓𝑓(4.20) Taking 𝐿𝑝,𝜆,𝛼() norm on both ends of the above inequality, by the boundedness of 𝑀𝛽 from 𝐿𝑝,𝜆,𝛼() to 𝐿𝑞,𝜆,𝛼(), we obtain the desired result. Theorem 3.2 is proved.

Acknowledgment

The authors express their thanks to the referee for careful reading, and helpful comments and suggestions on the manuscript of this paper.