Abstract
We consider the generalized shift operator, associated with the Dunkl operator , . We study the boundedness of the Dunkl-type fractional maximal operator in the Dunkl-type Morrey space , . We obtain necessary and sufficient conditions on the parameters for the boundedness , from the spaces to the spaces , , and from the spaces to the weak spaces , . As an application of this result, we get the boundedness of from the Dunkl-type Besov-Morrey spaces to the spaces , , , , , and .
1. Introduction
On the real line, the Dunkl operators are differential-difference operators introduced in 1989 by Dunkl [1]. For a real parameter , we consider the Dunkl operator, associated with the reflection group on :
In the theory of partial differential equations, together with weighted spaces, Morrey spaces play an important role. Morrey spaces were introduced by Morrey in 1938 in connection with certain problems in elliptic partial differential equations and calculus of variations (see [2]).
The Hardy-Littlewood maximal function, fractional maximal function, and fractional integrals are important technical tools in harmonic analysis, theory of functions, and partial differential equations. In the works [3–5], the maximal operator and in [6, 7] the fractional maximal operator associated with the Dunkl operator on were studied. In this work, we study the boundedness of the fractional maximal operator (Dunkl-type fractional maximal operator) in Morrey spaces (Dunkl-type Morrey spaces) associated with the Dunkl operator on . We obtain the necessary and sufficient conditions for the boundedness of the operator from the spaces to , , and from the spaces to the weak spaces , .
The paper is organized as follows. In Section 2, we present some definitions and auxiliary results. In Section 3, we give our main result on the boundedness of the operator in . We obtain necessary and sufficient conditions on the parameters for the boundedness of the operator from the spaces to the spaces , , and from the spaces to the weak spaces , . As an application of this result, in Section 4 we prove the boundedness of the operator from the Dunkl-type Besov-Morrey spaces to the spaces , , , , , and .
Finally, we mention that, will be always used to denote a suitable positive constant that is not necessarily the same in each occurrence.
2. Preliminaries
Let be a fixed number and be the weighted Lebesgue measure on , given by
For every , we denote by the spaces of complex-valued functions , measurable on such that
For we denote by , the weak spaces defined as the set of locally integrable functions , with the finite norm
Note that
For all , we put where and is the Bessel kernel given by where and .
In the sequel we consider the signed measure , on , given by
For and being a continuous function on , the Dunkl translation operator is given by
Using the change of variable , we have also (see [8]) where and .
Proposition 2.1 (see Soltani [9]). For all the operator extends to , and we have for ,
Let , ,, and . Then and .
Now we define the Dunkl-type fractional maximal function (see [3–5]) by If , then is the Dunkl-type maximal operator.
In [3–5] was proved the following theorem (see also [10]).
Theorem 2.2. If , then for every
where is independent of .
If , then and
where is independent of .
Definition 2.3. Let , . We denote by Morrey space ( Dunkl-type Morrey space), associated with the Dunkl operator as the set of locally integrable functions , , with the finite norm
Note that , and if or , then , where is the set of all functions equivalent to on (see also [7]).
Definition 2.4. Let and . We denote by a weak Dunkl-type Morrey space as the set of locally integrable functions , with finite norm
We note that
3. Main Results
The following theorem is our main result in which we obtain the necessary and sufficient conditions for the Dunkl-type fractional maximal operator to be bounded from the spaces to , and from the spaces to the weak spaces , .
Theorem 3.1. Let , , and . If , then the condition is necessary and sufficient for the boundedness of from to .If , then the condition is necessary and sufficient for the boundedness of from to .If , then is bounded from to .
For , , and , the Dunkl-type Besov-Morrey consists of all functions in so that
Besov spaces in the setting of the Dunkl operators were studied by Abdelkefi and Sifi [11], Bouguila et al. [12], Guliyev and Mammadov [10], and Kamoun [13]. In the following theorem, we prove the boundedness of the Dunkl-type fractional maximal operator in the Dunkl-type Besov-Morrey spaces.
Theorem 3.2. For ,, , , and , the Dunkl-type fractional maximal operator is bounded from to . More precisely, there is a constant such that hold for all .
Remark 3.3. Note that Theorem 3.2 in the case was proved in [10].
4. Boundedness of the Dunkl-Type Fractional Maximal Operator in the Dunkl-Type Morrey Spaces
In the following theorem, we obtain the boundedness of the Dunkl-type fractional maximal operator in the Dunkl-type Morrey spaces .
Theorem 4.1. Let , , , and . If and , then and where is independent of .If and , then and where is independent of .If and , then and
Proof. The maximal function may be interpreted as a maximal function defined on a space of homogeneous type. By this we mean a topological space equipped with a continuous pseudometric and a positive measure satisfying
with a constant being independent of and Here . Let be a space of homogeneous type, where , , and . It is clear that this measure satisfies the doubling condition (4.4). Define
It is well known that the maximal operator is bounded from to and is bounded on for , (see [14, 15]).
The following inequality was proved in [6]
where is independent of .
Then from (4.6) we get the boundedness of the operator from to and on , . Thus in the case we complete the proof of () and ().
Let , , , and . Applying the Hölders inequality we have
Therefore, for all , we get
The minimum value of the right-hand side (4.8) is attained at
and hence
Then for from (4.10), we have
where is independent of .
Also for from (4.10) we have
where is independent of .
Therefore, the case complete the proof of () and ().
() Let , ; then applying Hölders inequality, we obtain
Thus the case completes the proof of ().
Theorem 4.1 has been proved.
Proof of Theorem 3.1. Sufficiency part of the proof follows from Theorem 4.1.Necessity. () Let and be bounded from to .
Define , . Then
and ,
By the boundedness of from to ,
where depends only on , , , and .
If , then for all we have as , which is impossible. Similarly, if then for all we obtain as , which is also impossible.
Therefore, we get .Necessity. Let be bounded from to . We have
By the boundedness of from to it follows that
where depends only on , , and .
If , then for all we have as . Similarly, if , then for all we obtain as .
Hence we get . Thus the proof of Theorem 3.1 is completed.
Proof of Theorem 3.2. For , let be the generalized translation by . By definition of the Besov spaces, it suffices to show that It is easy to see that commutes with , that is, . Hence we have Taking norm on both ends of the above inequality, by the boundedness of from to , we obtain the desired result. Theorem 3.2 is proved.
Acknowledgment
The authors express their thanks to the referee for careful reading, and helpful comments and suggestions on the manuscript of this paper.