Abstract

Let 𝑓𝑛(𝑧)=𝑧+𝑛𝑘=2𝑎𝑘𝑧𝑘 be the sequence of partial sums of the analytic function 𝑓(𝑧)=𝑧+𝑘=2𝑎𝑘𝑧𝑘. In this paper, we determine sharp lower bounds for {𝑓(𝑧)/𝑓𝑛(𝑧)},{𝑓𝑛(𝑧)/𝑓(𝑧)},{𝑓(𝑧)/𝑓𝑛(𝑧)}, and {𝑓𝑛(𝑧)/𝑓(𝑧)}. The usefulness of the main result not only provides the unification of the results discussed in the literature but also generates certain new results.

1. Introduction and Preliminaries

Let 𝒜 denote the class of functions of the form𝑓(𝑧)=𝑧+𝑘=2𝑎𝑘𝑧𝑘(1.1) which are analytic and univalent in the open disc 𝑈={𝑧|𝑧|<1}. We also consider 𝑇 a subclass of 𝒜 introduced and studied by Silverman [1], consisting of functions of the form𝑓(𝑧)=𝑧𝑘=2𝑎𝑘𝑧𝑘,𝑧𝑈.(1.2)

For functions 𝑓𝒜 given by (1.1) and 𝑔𝒜 given by 𝑔(𝑧)=𝑧+𝑘=2𝑏𝑘𝑧𝑘, we define the Hadamard product (or convolution) of 𝑓 and 𝑔 by(𝑓𝑔)(𝑧)=𝑧+𝑘=2𝑎𝑘𝑏𝑘𝑧𝑘,𝑧𝑈.(1.3) We recall here a general Hurwitz-Lerch zeta function Φ(𝑧,𝑠,𝑎) defined in [2] byΦ(𝑧,𝑠,𝑎)=𝑘=0𝑧𝑘(𝑘+𝑎)𝑠(1.4) (𝑎0; 𝑠, when |𝑧|<1; (𝑠)>1, when |𝑧|=1), where, as usual, 0=, (={0,±1,±2,±3,}); ={1,2,3,}. Several interesting properties and characteristics of the Hurwitz-Lerch Zeta function Φ(𝑧,𝑠,𝑎) can be found in the recent investigations by Choi and Srivastava [3], Ferreira and López [4], Garg et al. [5], Lin and Srivastava [6], Lin et al. [7], and others. Srivastava and Attiya [8] (see also Răducanu and Srivastava [9] and Prajapat and Goyal [10]) introduced and investigated the linear operator 𝒥𝜇,𝑏𝒜𝒜 defined in terms of the Hadamard product by𝒥𝜇,𝑏𝑓(𝑧)=𝒢𝑏,𝜇𝑓(𝑧)𝑧𝑈;𝑏0,;𝜇;𝑓𝒜(1.5) where, for convenience,𝐺𝜇,𝑏(𝑧)=(1+𝑏)𝜇Φ(𝑧,𝜇,𝑏)𝑏𝜇(𝑧𝑈).(1.6) We recall here the following relationships (given earlier by [9, 10]) which follow easily by using (1.1), (1.5), and (1.6):𝒥𝜇𝑏𝑓(𝑧)=𝑧+𝑘=21+𝑏𝑘+𝑏𝜇𝑎𝑘𝑧𝑘.(1.7) Motivated essentially by the Srivastava-Attiya operator [8], we introduce the generalized integral operator𝒥𝑚,𝜂𝜇,𝑏𝑓(𝑧)=𝑧+𝑘=2𝐶𝑚𝑘(𝑏,𝜇)𝑎𝑘𝑧𝑘=𝐹(𝑧),(1.8) where𝐶𝑚𝑘||||(𝑏,𝜇)=1+𝑏𝑘+𝑏𝜇𝑚!(𝑘+𝜂2)!||||(𝜂2)!(𝑘+𝑚1)!,(1.9) and (throughout this paper unless otherwise mentioned) the parameters 𝜇, 𝑏 are constrained as 𝑏0; 𝜇, 𝜂2 and 𝑚>1. It is of interest to note that 𝐽1,2𝜇,𝑏 is the Srivastava-Attiya operator [8] and 𝐽𝑚,𝜂0,𝑏 is the well-known Choi-Saigo-Srivastava operator (see [11, 12]). Suitably specializing the parameters 𝑚, 𝜂, 𝜇, and 𝑏 in 𝒥𝑚,𝜂𝜇,𝑏𝑓(𝑧), we can get various integral operators introduced by Alexander [13] and Bernardi [14]. Further more, we get the Jung-Kim-Srivastava integral operator [15] closely related to some multiplier transformation studied by Flett [16].

Motivated by Murugusundaramoorthy [1719] and making use of the generalized Srivastava-Attiya operator 𝒥𝑚,𝜂𝜇,𝑏, we define the following new subclass of analytic functions with negative coefficients.

For 𝜆0, 1𝛾<1, and 𝛽0, let 𝑃𝜆𝜇(𝛾,𝛽) be the subclass of 𝒜 consisting of functions of the form (1.1) and satisfying the analytic criterion𝑧𝒥𝑚,𝜂𝜇,𝑏𝑓(𝑧)+𝜆𝑧2𝒥𝑚,𝜂𝜇,𝑏𝑓(𝑧)(1𝜆)𝒥𝑚,𝜂𝜇,𝑏𝑓𝒥(𝑧)+𝜆𝑧𝑚,𝜂𝜇,𝑏𝑓(𝑧)||||||𝑧𝒥𝛾>𝛽𝑚,𝜂𝜇,𝑏𝑓(𝑧)+𝜆𝑧2𝒥𝑚,𝜂𝜇,𝑏𝑓(𝑧)(1𝜆)𝒥𝑚,𝜂𝜇,𝑏𝑓𝒥(𝑧)+𝜆𝑧𝑚,𝜂𝜇,𝑏𝑓(𝑧)||||||1,(1.10) where 𝑧𝑈. Shortly we can state this condition by𝑧𝐺(𝑧)||||𝐺(𝑧)𝛾>𝛽𝑧𝐺(𝑧)||||,𝐺(𝑧)1(1.11) where𝐺(𝑧)=(1𝜆)𝐹(𝑧)+𝜆𝑧𝐹(𝑧)=𝑧+𝑘=2[]||𝐶1+𝜆(𝑘1)𝑚𝑘(||𝑎𝑏,𝜇)𝑘𝑧𝑘,(1.12) and 𝐹(𝑧)=𝒥𝑚,𝜂𝜇,𝑏𝑓(𝑧).

Recently, Silverman [20] determined sharp lower bounds on the real part of the quotients between the normalized starlike or convex functions and their sequences of partial sums. In the present paper and by following the earlier work by Silverman [20] (see [2125]) on partial sums of analytic functions, we study the ratio of a function of the form (1.1) to its sequence of partial sums of the form𝑓𝑛(𝑧)=𝑧+𝑛𝑘=2𝑎𝑘𝑧𝑘,(1.13) when the coefficients of 𝑓(𝑧) satisfy the condition (1.14). Also, we will determine sharp lower bounds for {𝑓(𝑧)/𝑓𝑛(𝑧)}, {𝑓𝑛(𝑧)/𝑓(𝑧)}, {𝑓(𝑧)/𝑓𝑛(𝑧)}, and {𝑓𝑛(𝑧)/𝑓(𝑧)}. It is seen that this study not only gives as a particular case, the results of Silverman [20], but also gives rise to several new results.

Before stating and proving our main results, we derive a sufficient condition giving the coefficient estimates for functions 𝑓(𝑧) to belong to this generalized function class.

Lemma 1.1. A function 𝑓(𝑧) of the form (1.1) is in 𝑃𝜆𝜇(𝛾,𝛽) if 𝑘=2([]||𝑎1+𝜆(𝑘1))𝑘(1+𝛽)(𝛾+𝛽)𝑘||𝐶𝑚𝑘(𝑏,𝜇)1𝛾,(1.14) where, for convenience, 𝜌𝑘=𝜌𝑘([]𝐶𝜆,𝛾,𝜂)=(1+𝜆(𝑘1))𝑛(1+𝛽)(𝛾+𝛽)𝑚𝑘(𝑏,𝜇),(1.15)0𝜆1, 1𝛾<1, 𝛽0, and 𝐶𝑚𝑘(𝑏,𝜇), is given by (1.9).

Proof. The proof of Lemma 1.1 is much akin to the proof of Theorem 1 obtained by Murugusundaramoorthy [17], hence we omit the details.

2. Main Results

Theorem 2.1. If 𝑓 of the form (1.1) satisfies the condition (1.14), then 𝑓(𝑧)𝑓𝑛𝜌(𝑧)𝑛+1(𝜆,𝛾,𝜂)1+𝛾𝜌𝑛+1(𝜆,𝛾,𝜂)(𝑧𝑈),(2.1) where 𝜌𝑘=𝜌𝑘𝜌(𝜆,𝛾,𝜂)1𝛾if𝑘=2,3,,𝑛,𝑛+1if𝑘=𝑛+1,𝑛+2,.(2.2) The result (2.1) is sharp with the function given by 𝑓(𝑧)=𝑧+1𝛾𝜌𝑛+1𝑧𝑛+1.(2.3)

Proof. Define the function 𝑤(𝑧) by 1+𝑤(𝑧)=𝜌1𝑤(𝑧)𝑛+11𝛾𝑓(𝑧)𝑓𝑛𝜌(𝑧)𝑛+11+𝛾𝜌𝑛+1=1+𝑛𝑘=2𝑎𝑘𝑧𝑘1+𝜌𝑛+1/(1𝛾)𝑘=𝑛+1𝑎𝑘𝑧𝑘11+𝑛𝑘=2𝑎𝑘𝑧𝑘1.(2.4)
It suffices to show that |𝑤(𝑧)|1. Now, from (2.4) we can write 𝑤𝜌(𝑧)=𝑛+1/(1𝛾)𝑘=𝑛+1𝑎𝑘𝑧𝑘12+2𝑛𝑘=2𝑎𝑘𝑧𝑘1+𝜌𝑛+1/(1𝛾)𝑘=𝑛+1𝑎𝑘𝑧𝑘1.(2.5) Hence we obtain ||||𝜌𝑤(𝑧)𝑛+1/(1𝛾)𝑘=𝑛+1||𝑎𝑘||22𝑛𝑘=2||𝑎𝑘||𝜌𝑛+1/(1𝛾)𝑘=𝑛+1||𝑎𝑘||.(2.6) Now |𝑤(𝑧)|1 if and only if 2𝜌𝑛+11𝛾𝑘=𝑛+1||𝑎𝑘||22𝑛𝑘=2||𝑎𝑘||(2.7) or, equivalently, 𝑛𝑘=2||𝑎𝑘||+𝑘=𝑛+1𝜌𝑛+1||𝑎1𝛾𝑘||1.(2.8)
From the condition (1.14), it is sufficient to show that 𝑛𝑘=2||𝑎𝑘||+𝑘=𝑛+1𝜌𝑛+1||𝑎1𝛾𝑘||𝑘=2𝜌𝑘||𝑎1𝛾𝑘||(2.9) which is equivalent to 𝑛𝑘=2𝜌𝑘1+𝛾||𝑎1𝛾𝑘||+𝑘=𝑛+1𝜌𝑘𝜌𝑛+1||𝑎1𝛾𝑘||0.(2.10) To see that the function given by (2.3) gives the sharp result, we observe that for 𝑧=𝑟𝑒𝑖𝜋/𝑛, 𝑓(𝑧)𝑓𝑛(𝑧)=1+1𝛾𝜌𝑛+1𝑧𝑛11𝛾𝜌𝑛+1=𝜌𝑛+11+𝛾𝜌𝑛+1when𝑟1.(2.11)

We next determine bounds for 𝑓𝑛(𝑧)/𝑓(𝑧).

Theorem 2.2. If 𝑓 of the form (1.1) satisfies the condition (1.14), then 𝑓𝑛(𝑧)𝜌𝑓(𝑧)𝑛+1𝜌𝑛+1+1𝛾(𝑧𝑈),(2.12) where 𝜌𝑛+11𝛾 and 𝜌𝑘𝜌1𝛾if𝑘=2,3,,𝑛,𝑛+1if𝑘=𝑛+1,𝑛+2,.(2.13) The result (2.12) is sharp with the function given by (2.3).

Proof. We write 1+𝑤(𝑧)=𝜌1𝑤(𝑧)𝑛+1+1𝛾𝑓1𝛾𝑛(𝑧)𝜌𝑓(𝑧)𝑛+1𝜌𝑛+1=+1𝛾1+𝑛𝑘=2𝑎𝑘𝑧𝑘1𝜌𝑛+1/(1𝛾)𝑘=𝑛+1𝑎𝑘𝑧𝑘11+𝑘=2𝑎𝑘𝑧𝑘1,(2.14) where ||||𝜌𝑤(𝑧)𝑛+1/+1𝛾(1𝛾)𝑘=𝑛+1||𝑎𝑘||22𝑛𝑘=2||𝑎𝑘||𝜌𝑛+11+𝛾/(1𝛾)𝑘=𝑛+1||𝑎𝑘||1.(2.15) This last inequality is equivalent to 𝑛𝑘=2||𝑎𝑘||+𝑘=𝑛+1𝜌𝑛+1||𝑎1𝛾𝑘||1.(2.16) We are making use of (1.14) to get (2.10). Finally, equality holds in (2.12) for the extremal function 𝑓(𝑧) given by (2.3).

We next turns to ratios involving derivatives.

Theorem 2.3. If 𝑓 of the form (1.1) satisfies the condition (1.14), then 𝑓(𝑧)𝑓𝑛𝜌(𝑧)𝑛+1(𝑛+1)(1𝛾)𝜌𝑛+1𝑓(𝑧𝑈),(2.17)𝑛(𝑧)𝑓𝜌(𝑧)𝑛+1𝜌𝑛+1+(𝑛+1)(1𝛾)(𝑧𝑈),(2.18) where 𝜌𝑛+1(𝑛+1)(1𝛾) and 𝜌𝑘𝑘𝜌𝑘(1𝛾)if𝑘=2,3,,𝑛,𝑛+1𝑛+1if𝑘=𝑛+1,𝑛+2,.(2.19) The results are sharp with the function given by (2.3).

Proof. We write 1+𝑤(𝑧)=𝜌1𝑤(𝑧)𝑛+1𝑓(𝑛+1)(1𝛾)(𝑧)𝑓𝑛𝜌(𝑧)𝑛+1(𝑛+1)(1𝛾)𝜌𝑛+1,(2.20) where 𝑤𝜌(𝑧)=𝑛+1/((𝑛+1)(1𝛾))𝑘=𝑛+1𝑎𝑘𝑧𝑘12+2𝑛𝑘=2𝑘𝑎𝑘𝑧𝑘1+𝜌𝑛+1/((𝑛+1)(1𝛾))𝑘=𝑛+1𝑘𝑎𝑘𝑧𝑘1.(2.21) Now |𝑤(𝑧)|1 if and only if 𝑛𝑘=2𝑘||𝑎𝑘||+𝜌𝑛+1(𝑛+1)(1𝛾)𝑘=𝑛+1𝑘||𝑎𝑘||1.(2.22) From the condition (1.14), it is sufficient to show that 𝑛𝑘=2𝑘||𝑎𝑘||+𝜌𝑛+1(𝑛+1)(1𝛾)𝑘=𝑛+1𝑘||𝑎𝑘||𝑘=2𝜌𝑘||𝑎1𝛾𝑘||(2.23) which is equivalent to 𝑛𝑘=2𝜌𝑘(1𝛾)𝑘||𝑎1𝛾𝑘||+𝑘=𝑛+1(𝑛+1)𝜌𝑘𝑘𝜌𝑛+1||𝑎(𝑛+1)(1𝛾)𝑘||0.(2.24)
To prove the result (2.18), define the function 𝑤(𝑧) by 1+𝑤(𝑧)=1𝑤(𝑧)(𝑛+1)(1𝛾)+𝜌𝑛+1𝑓(1𝛾)(𝑛+1)𝑛(𝑧)𝑓𝜌(𝑧)𝑛+1(𝑛+1)(1𝛾)+𝜌𝑛+1,(2.25) where 𝑤(𝑧)=1+𝜌𝑛+1/((𝑛+1)(1𝛾))𝑘=𝑛+1𝑘𝑎𝑘𝑧𝑘12+2𝑛𝑘=2𝑘𝑎𝑘𝑧𝑘1+1𝜌𝑛+1/((𝑛+1)(1𝛾))𝑘=𝑛+1𝑘𝑎𝑘𝑧𝑘1.(2.26) Now |𝑤(𝑧)|1 if and only if 𝑛𝑘=2𝑘||𝑎𝑘||+𝜌𝑛+1(𝑛+1)(1𝛾)𝑘=𝑛+1𝑘||𝑎𝑘||1.(2.27) It suffices to show that the left hand side of (2.27) is bounded previously by the condition 𝑘=2𝜌𝑘||𝑎1𝛾𝑘||,(2.28) which is equivalent to 𝑛𝑘=2𝜌𝑘||𝑎1𝛾𝑘𝑘||+𝑘=𝑛+1𝜌𝑘𝜌1𝛾𝑛+1𝑘||𝑎(𝑛+1)(1𝛾)𝑘||0.(2.29)

Remark 2.4. As a special case of the previous theorems, we can determine new sharp lower bounds for{𝑓(𝑧)/𝑓𝑛(𝑧)}, {𝑓𝑛(𝑧)/𝑓(𝑧)}, {𝑓(𝑧)/𝑓𝑛(𝑧)}, and {𝑓𝑛(𝑧)/𝑓(𝑧)} for various function classes involving the Alexander integral operator [13] and Bernardi integral operators [14], Jung-Kim-Srivastava integral operator [15] and Choi-Saigo-Srivastava operator (see [11, 12]) on specializing the values of 𝜂, 𝑚, 𝜇, and 𝑏.

Some other work related to partial sums and also related to zeta function can be seen in ([2629]) for further views and ideas.

Acknowledgment

The third author is presently supported by MOHE: UKM-ST-06-FRGS0244-2010.