An Extrapolated Iterative Algorithm for Multiple-Set Split Feasibility Problem

Table 1

The numerical results of Example 4.1.

Case	Algorithm (1.2)	Algorithm 3.1	Algorithm (1.2)	Algorithm 3.1	Algorithm (1.2)	Algorithm 3.1
	𝑠=1	𝑠=1	𝑠=0.6	𝑠=0.6	𝑠=1.6	𝑠=1.6
I	Iter.=85	Iter.=3	Iter.=143	Iter.=9	Iter.=52	Iter.=2
	Sec.=0.123	Sec.=0.002	Sec.=0.210	Sec.=0.006	Sec.=0.099	Sec.=0.001
	𝑥^∗=(0.0781	𝑥^∗=(0.1149	𝑥^∗=(0.0765	𝑥^∗=(0.0863	𝑥^∗=(0.0809	𝑥^∗=(−0.2996
	−0.6930	−0.7321	−0.6912	−0.7045	−0.6958	−0.6310
	0.4143	0.3215	0.4175	0.3868	0.4095	−0.0882
	−0.6005	−0.6893	−0.5997	−0.6248	−0.6051	−0.6830
	−0.3276)	−0.4082)	−0.3249)	−0.3483)	−0.3321)	−0.9525)
II	Iter.=658	Iter.=4	Iter.=1096	Iter.=8	Iter.=411	Iter.=2
	Sec.=0.890	Sec.=0.003	Sec.=0.996	Sec.=0.019	Sec.=0.633	Sec.=0.002
	𝑥^∗=(−0.0289	𝑥^∗=(−0.1147	𝑥^∗=(−0.0267	𝑥^∗=(−0.0607	𝑥^∗=(−0.0324	𝑥^∗=(−0.3398
	0.3333	0.3647	0.3314	0.3399	0.3367	0.3019
	−0.3736	−0.5197	−0.3715	−0.4232	−0.3771	−1.1325
	0.2065	0.2310	0.2059	0.2142	0.2077	0.0975
	0.0682)	0.0115)	0.0688)	0.0467)	0.0670)	−0.1164)
III	Iter.=774	Iter.=5	Iter.=1288	Iter.=11	Iter.=484	Iter.=1
	Sec.=0.910	Sec.=0.011	Sec.=1.231	Sec.=0.022	Sec.=0.810	Sec.=0.004
	𝑥^∗=(0.5447	𝑥^∗=(0.7013	𝑥^∗=(0.5376	𝑥^∗=(0.5206	𝑥^∗=(0.5572	𝑥^∗=(−1.2386
	−0.2349	−0.4513	−0.2277	−0.2120	−0.2474	0.0067
	−0.7627	−1.4225	−0.7437	−1.0221	−0.7953	−6.9419
	−0.9891	−1.4560	−0.9679	−1.1625	−1.0249	−3.1678
	−0.7520)	−1.3338)	−0.7343)	−0.8719)	−0.7822)	−6.8881)