Numerical Solution of Higher Order Boundary Value Problems

Table 1

Comparison of numerical results for Example 1.

𝑥	Exact solution	Approximate series solution	Absolute error present method	Absolute error Siddiqi and Iftikhar [3]
0.0	0.0000	0.0000	0.0000	0.0000
0.1	0.9946	0.9946	5.39291𝐸−14	8.55607𝐸−13
0.2	0.1954	0.1954	4.85167𝐸−14	9.94041𝐸−12
0.3	0.2835	0.2835	3.92464𝐸−14	3.52244𝐸−11
0.4	0.3580	0.3580	2.21489𝐸−14	7.3224𝐸−10
0.5	0.4122	0.4122	3.84137𝐸−14	1.08769𝐸−10
0.6	0.4373	0.4373	2.10831𝐸−13	1.29035𝐸−10
0.7	0.4229	0.4229	1.99785𝐸−13	1.51466𝐸−10
0.8	0.3561	0.3561	3.29736𝐸−13	2.717974𝐸−10
0.9	0.2214	0.2214	1.77622𝐸−12	7.48179𝐸−10
1.0	0.0000	−1.65159𝐸−12	1.65159𝐸−12	2.1729𝐸−09