Abstract and Applied Analysis

Volume 2014 (2014), Article ID 512426, 18 pages

http://dx.doi.org/10.1155/2014/512426

## Existence and Multiple Positive Solutions for Boundary Value Problem of Fractional Differential Equation with -Laplacian Operator

School of Mathematics Science, University of Electronic Science and Technology of China, Chengdu 611731, China

Received 28 February 2014; Accepted 26 April 2014; Published 15 May 2014

Academic Editor: Bashir Ahmad

Copyright © 2014 Min Jiang and Shouming Zhong. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

#### Abstract

This paper investigates the existence, multiplicity, nonexistence, and uniqueness of positive solutions to a kind of two-point boundary value problem for nonlinear fractional differential equations with -Laplacian operator. By using fixed point techniques combining with partially ordered structure of Banach space, we establish some criteria for existence and uniqueness of positive solution of fractional differential equations with -Laplacian operator in terms of different value of parameter. In particular, the dependence of positive solution on the parameter was obtained. Finally, several illustrative examples are given to support the obtained new results. The study of illustrative examples shows that the obtained results are applicable.

#### 1. Introduction

In this paper, we consider boundary value problem for a fractional differential equation with -Laplacian operator where is a constant and is a parameter. , is the -Laplacian operator; that is, . denotes the Caputo fractional derivative.

Fractional differential equations have been of great interest recently. It is caused both by the intensive development of the theory of fractional calculus itself and by the applications of such constructions in various fields of sciences and engineering such as physics, chemistry, aerodynamics, electrodynamics of complex medium, electrical circuits, and biology (see [1–7] and their references). Differential equations with -Laplacian arise naturally in non-Newtonian mechanics, nonlinear elasticity, glaciology, population biology, combustion theory, and nonlinear flow laws. Since the -Laplacian operator and fractional calculus arise from so many applied fields, the fractional -Laplacian differential equations are worth studying. Recently, there have appeared a very large number of papers which are devoted to the existence of solutions of boundary value problems and initial value problems for the fractional differential equations (see [8–12]), and the existence of solutions of boundary value problems for the fractional -Laplacian differential equations has just begun in recent years (see [13–22]). On the other hand, there are few papers that consider the eigenvalue intervals of fractional boundary value problems (see [23, 24]). In [23], the author discussed the following system: By the use of appropriate conditions with respect to and , the author proved that the above problem has at least one or two positive solutions for some , where . But almost all the results which the author obtained depend on both and ; the case depends on one of and ; the author only discussed and ; the case or has not been discussed. On the other hand, there exist several results on the existence of one solution to fractional -Laplacian boundary value problems (BVPs); there are, to the best of our knowledge, relatively few results on the nonexistence and the uniqueness of positive solutions to fractional -Laplacian differential equation with parameter.

Motivated by the above questions, in this paper, we will establish several sufficient conditions for the existence of positive solutions of (1) by using fixed point theorem and fixed point index theory.

The work is organized in the following fashion. In Section 2, we provide some necessary background. In particular, we will introduce some lemmas and definitions associated with fixed point index theory. The main results will be stated and proved in Section 3. Two examples are given in Section 4.

#### 2. Preliminaries

In this section, we introduce definitions and preliminary facts which are used throughout this paper.

*Definition 1 (see [1]). *The Riemann-Liouville fractional integral of order of a function is given by
provided that the right side is point-wise defined on and is the Gamma function.

*Definition 2 (see [1]). *The Caputo fractional derivative of order of a continuous function is given by
where , provided that the right side is point-wise defined on .

Lemma 3 (see [1]). *Let , and assume that , and then the fractional differential equation has unique solutions:
*

*Lemma 4 (see [1]). Let . Then,
where .*

*Lemma 5 (see [25]). Let be a cone in a real Banach space , and let be a bounded open set of . Assume that operator is completely continuous. If there exists a such that
then .*

*Lemma 6 (see [26]). Let be a Banach space and a cone, and and are open set with , and let be completely continuous operator such that either(i), and or(ii), and holds. Then has a fixed point in .*

*3. Main Results*

*In this section, we present some new results on the existence, multiplicity, nonexistence, and the uniqueness of positive solution of problem (1) and dependence of the positive solution on the parameter .*

*Let ; then is a real Banach space with the norm defined by .*

*Lemma 7. Let and ; then the solution of the problem
is given by
where and .*

*Proof. *It is easy to see by integration of (8) that
By the boundary condition , we can easily get that , and we obtain that
that is
By Lemmas 3 and 4, we get that
Using the boundary condition , , we get and
Thus,
Direct differentiation of (9) implies
By differentiation of (17), we get

Thus the solution of problem (8) is nonincreasing and concave on , and
On the other hand, as we assume that , we see that
Therefore, and is concave for . So for every ,
Therefore,
Since , we have
that is,
The Lemma is proved.

*We construct a cone in by
where is defined in Lemma 7. It is easy to see is a closed convex cone of .*

*Define by
*

*It is clear that the fixed points of the operator are the solutions of the boundary value problems (1).*

*We make the following hypotheses:(H1) is continuous;(H2) is continuous and not identical zero on any closed subinterval of with ;(H3);
(H4), where uniformly for ;(H5), where uniformly for ;(H6) for any and .*

*Lemma 8. Assume that (H1)–(H3) hold. Then is completely continuous.*

*Proof. *First, we show that is continuous. It is easy to see . For and , as , by the continuous of , we get , as . This implies that
So we have
Denote ; then

Hence, is continuous.

Second, we show that is compact.

For , by condition (H1), . Denote .

Then
that is, maps bounded sets into bounded sets in .

For , ,
By mean value theorem, we obtain that
Thus
This shows that , as , so is equicontinuous. Therefore, the operator is completely continuous by the Arzela-Ascoli theorem.

*Now for convenience we introduce the following notations. Let
*

*Theorem 9. Assume that (H1)–(H5) hold.(i)If , then there exists such that, for every , problem (1) has a positive solution satisfying associated with
where and are two positive finite numbers.(ii)If , then there exists such that, for every , problem (1) has a positive solution satisfying for any
where and are two positive finite numbers.(iii)If , then there exists such that, for any , problem (1) has a positive solution satisfying for any
where is a positive finite number.(iv)If , then there exists such that, for every , problem (1) has a positive solution satisfying for any
where is a positive finite number.(v)If there exists such that , then problem (1) has positive solution satisfying for any
where is a positive finite number.*

*Proof. *(i) It follows from that there exists , such that

Let ; we show that is required. When , we have
we need ; this implies that , as , so .

Let . Then we may assume that
if not, then there exists such that , and then (35) already holds for .

Define ; then , and . We now show that
In fact, if there exists such that , then (42) implies that . On the other hand ; we may choose ; then . Therefore
Consequently, for any , (26) and (44) imply that
which implies that , which is a contradiction to the definition of . Thus, (42) holds and, by Lemma 5, the fixed point index
On the other hand, by the fact that the fixed point index of constants operator is 1, so
where is the zero operator. It follows therefore from (46) and (47) and the homotopy invariance property that there exist and such that , but , which implies that ; it follows that we get ; that is,
and then
From the proof above, for any , there exists a positive solution associated with .

Thus
with .

Next, we show that . In fact,
which implies that
that is,
it follows that we get
In conclusion, .

(ii) It follows from that there exist such that
Let , the following proof are similar to (i).

(iii) It follows from , there exists , such that
Let ; we show that is required. When , we have ; since , then we need , as , so holds.

Let ; we proceed in the same way as in the proof of (i): replacing (42) we may assume that , and replacing (43) we can prove . It follows from Lemma 5 that . Note that ; we can easily show that there exists and such that . Hence (37) holds for .

The proof of Theorem 9(iv) follows by the method similar to Theorem 9(iii); we omit it here.

(v) It follows that ; for any , we have and ; then
Let . The following proof is similar to that of (iv). This finished the proof of (v).

*Remark 10. *In Theorem 9, all the criteria obtained depend on one of and .

*Let ; the following theorems give out the multiply, nonexistence, and the dependence of parameter.*

*Theorem 11. Assume that (H1)–(H5) hold.(i)If and , uniformly for , then there exists such that the problem (1) has two solutions for any .(ii)If and , then there exists such that, for any , problem (1) has no solution.*

*Proof. *(i) It follows from that, for any , there exists , such that

Since , there exists such that
where satisfied .

For , we have
This implied
Let and ; then ; we have and
which implies

Next, for , there exist such that
where satisfied .

Similar to the above proof, we get

Applying Lemma 7 to (61), (65), and (63) yields that has two fixed points such that and .

(ii) It follows from and that there exists , such that
then for , by the continuous of , there exists such that
Let ; then
Assuming is a positive solution of problem (1), we will show that this leads to a contradiction for , where . It follows from (26) that
This implies that , which is a contradiction. This finishes the proof of (ii).

*Remark 12. *In (i), the condition uniformly for can be replaced with condition (H6). The same methods can be used to prove the results.

*Remark 13. *From the above proof, the condition is important to keep the problem (1) having at least two positive solutions, if this condition is not satisfied, then there exists small enough such that the problem (1) has no positive solutions for all .

*Theorem 14. Assume that (H1)–(H6) hold.(i)If and , then there exists such that problem (1) has at least two solutions for .(ii)If and , then there exists such that problem (1) has no solution for all .*

*Proof. *
(i) It follows from that there exists