Generalized Newton Method for a Kind of Complementarity Problem

Table 4

𝑥0=(1,1)^𝑇
Step (𝑑𝑘 was computed by (12))	Ψ(𝑥)
14	9.696887098398221𝑒−005
𝑥0=(1,1)^𝑇
Step (𝑑𝑘 was computed by (35))	Ψ(𝑥)
21	9.401294082644895𝑒−005
𝑥0=(1,1)^𝑇
Step (𝑑𝑘 was computed by (36))	Ψ(𝑥)
22	9.162651686955847𝑒−005