Optimization in Construction Management Using Adaptive Opposition Slime Mould Algorithm

Table 2

Data resources for case 1.

ID	Case	Time	Cost	SI K = 1		SI K = 2		SI K = 3		Act. Weight	Ql k = 1		Ql k = 2		Ql k = 3
(i)	(n)	Days	$	RL; LkmA	RS; SkmA	RL; LkmA	RS; SkmA	RL; LkmA	RS; SkmA	(%) ()
1	1	8	10039.42	1	1	1	1	1	1	0.16	0.45	97	0.3	99	0.25	93
	2	8	9849.86	1	2	1	2	1	2			70		73		71
2	1	6	1082.13	3	3	1	1	3	2	0.164	0.2	94	0.35	91	0.45	89
	2	6	891.05	3	4	2	1	4	3			83		88		84
3	1	12	15545.67	3	2	4	2	3	2	0.19	0.3	95	0.45	94	0.25	95
	2	10	17039.34	2	2	3	3	3	2			85		87		89
4	1	5	562.13	3	5	2	1	2	2	0.133	0.35	89	0.35	92	0.3	94
	2	4	590.32	2	4	3	2	3	4			83		83		87
5	1	26	158,34.49	3	3	2	2	1	2	0.07	0.3	85	0.35	92	0.35	95
	2	16	17274.94	2	4	3	3	1	1			78		95		89
6	1	32	74124.65	2	3	4	5	3	3	0.057	0.4	99	0.3	78	0.3	94
	2	29	76345.78	3	4	4	6	4	4			90		85		88
	3	23	84312.34	4	5	5	6	3	3			85		90		86
7	1	22	32646.05	4	5	3	3	3	4	0.059	0.5	94	0.4	93	0.1	87
	2	11	29759.59	4	6	4	4	4	4			80		85		96
8	1	18	65959.52	2	3	2	4	2	3	0.043	0.4	90	0.5	78	0.1	73
	2	29	105296.94	2	2	3	3	1	2			85		90		94
	3	11	157433.42	2	2	3	2	2	3			90		95		95
9	1	37	58570.35	2	3	2	4	2	1	0.025	0.4	97	0.5	98	0.1	97
	2	21	59999.39	2	2	3	3	1	2			89		96		67
	3	32	57668.29	2	2	3	2	2	2			81		85		63
	4	17	63321.11	2	2	3	3	2	3			95		84		90
10	1	34	38411.50	2	3	2	4	2	1	0.02	0.45	85	0.45	90	0.1	78
	2	17	65326.48	2	2	3	3	1	2			88		92		90
	3	12	50214.22	2	2	3	2	2	3			78		84		93
11	1	9	12216.23	2	5	2	2	2	3	0.024	0.4	70	0.5	85	0.1	90
	2	12	3846.23	3	6	3	3	3	3			95		88		85
12	1	41	90219.78	1	2	2	3	1	3	0.022	0.4	70	0.5	85	0.1	90
	2	31	233034.50	2	3	3	3	2	3			95		88		85
13	1	23	127641.84	2	3	3	4	2	4	0.025	0.3	98	0.4	95	0.3	99
	2	24	81323.17	3	4	4	5	3	5			87		86		83