Research Article

A Novel BBO Algorithm Based on Local Search and Nonuniform Variation for Iris Classification

Table 3

Unimodal function test results.

FunctionDimensionEvaluating indicatorReference [4]BBOReference [24]DEReference [25]EHOReference [26]DEBBOReference [27]BBOPSOThe proposed method

D = 10Best
Ave|
Std
3.40 E − 03
1.37 E − 02
9.80 E − 03
1.70 E − 03
4.10 E − 03
1.70 E − 03
2.10 E − 03
6.60 E − 033.70 E − 03
1.81 E − 04
9.45 E − 04
6.91 E − 04
7.92 E − 05
1.20 E − 03
8.62 E − 04
5.78 E054.51 E043.25 E04
D = 30Best
Ave
Std
7.58 E − 02
1.47 E − 01
4.41 E − 02
3.50 E − 02
5.46 E − 02
1.03 E − 02
8.44 E − 02
1.33 E − 01
4.13 E − 02
1.05 E − 02
1.46 E − 02
4.20 E − 03
6.20 E − 03
2.23 E − 02
9.10 E − 03
1.10 E032.70 E032.00 E03
D = 50Best
Ave
Std
2.51 E − 01
5.67 E − 01
2.08 E − 01
1.21 E − 01
2.29 E − 01
5.16 E − 02
1.98 E − 01
5.37 E − 01
1.38 E − 01
3.47 E − 02
5.61 E − 02
1.56 E − 02
4.63 E − 02
7.82 E − 02
2.22 E − 02
3.00 E038.50 E034.20 E03

D = 10Best
Ave
Std
1.94 E + 00
8.38 E + 00
6.12 E + 00
1.18 E − 20
3.52 E − 20
2.77 E − 20
2.35 E − 04
3.74 E − 04
6.88 E − 05
6.72 E − 32
1.69 E − 29
2.06 E − 29
2.02 E − 28
1.37 E − 27
1.49 E − 27
3.66 E455.79 E439.78 E43
D = 30Best
Ave
Std
7.13 E + 01
1.43 E + 02
4.64 E + 01
1.20 E − 03
2.60 E − 03
2.20 E − 03
3.00 E − 03
3.60 E − 03
0.31 E − 04
1.40 E − 10
5.83 E − 10
4.90 E − 10
6.73 E − 07
1.24 E − 05
3.35 E − 05
2.09 E241.43 E223.91 E22
D = 50Best
Ave
Std
5.93 E + 02
7.27 E + 02
1.34 E + 02
1.58 E + 01
2.30 E + 01
4.63 E + 00
7.90 E − 03
9.00 E − 03
1.20 E − 03
2.38 E − 05
1.62 E − 04
1.54 E − 04
4.11 E − 02
1.64 E − 01
9.32 E − 02
4.66 E186.83 E178.48 E17

D = 10Best
Ave
Std
2.47 E − 02
3.01 E − 01
2.54 E − 01
2.04 E − 05
1.52 E − 04
1.04 E − 04
4.64 E − 06
7.51 E − 06
2.22 E − 06
3.89 E − 04
2.40 E − 03
1.80 E − 03
2.63 E − 04
1.45 E − 03
1.24 E − 03
8.88 E135.16 E077.21 E07
D = 30Best
Ave
Std
2.47 E + 00
5.77 E + 00
3.75 E + 00
6.19 E + 01
1.36 E + 01
4.70 E + 01
2.36 E − 04
4.10 E − 04
1.50 E − 04
1.21 E − 01
3.92 E − 01
1.61 E − 01
5.35 E − 02
2.90 E − 01
1.25 E − 01
1.13 E101.26 E062.10 E06
D = 50Best
Ave
Std
1.73 E + 01
5.16 E + 01
2.44 E + 01
1.04 E + 03
1.87 E + 03
4.83 E + 02
2.20 E − 03
3.30 E − 03
6.48 E − 04
2.02 E + 00
4.55 E + 00
2.61 E + 00
1.63 E + 00
2.55 E + 00
9.34 E − 01
4.07 E094.69 E066.33 E09

D = 2Best
Ave
Std
−9.13 E − 01
–5.00 E − 01
4.45 E − 01
−1.00 E + 00−1.00 E + 000.00 E + 00−9.95 E − 01
–9.60 E − 01
3.55EE − 02
−1.00 E+00−1.00 E+000.00 E+00−1.00 E+00−1.00 E+000.00 E+00−1.00 E+00−1.00 E+000.00 E+00