Abstract

Here we prove that if xk, k=1,2,,n+2 are the zeros of (1x2)Tn(x) where Tn(x) is the Tchebycheff polynomial of first kind of degree n, αj, βj, j=1,2,,n+2 and γj, j=1,2,,n+1 are any real numbers there does not exist a unique polynomial Q3n+3(x) of degree 3n+3 satisfying the conditions: Q3n+3(xj)=αj, Q3n+3(xj)=βj, j=1,2,,n+2 and Q3n+3(xj)=γj, j=2,3,,n+1. Similar result is also obtained by choosing the roots of (1x2)Pn(x) as the nodes of interpolation where Pn(x) is the Legendre polynomial of degree n.