Abstract

We demonstrate that the characterizations of topological extreme amenability. In particular, we prove that for every locally compact semigroup with a right identity, the condition , for , in , and , implies that , for some ( is a Dirac measure). We also obtain the conditions for which is topologically extremely left amenable.

1. Introduction

Let be a locally compact (Hausdorff) semigroup such that its multiplication is separately continuous. We denote by the Banach algebra under the supremum norm of all bounded real-valued functions on . For a topological semigroup , let and be the closed subalgebras of consisting of all Borel measurable functions and all continuous functions on , respectively. Let be the subalgebra of consisting of the functions which vanish at infinity. Let be the Banach space of all bounded regular Borel (signed) measures on with a total variation norm. Let be the set of all probability measures in .

It is known that via the correspondence , where for any in [1, Section 14]. Consider the continuous dual of . An element in is called a mean on , if and , whenever . An equivalent definition for a mean is thatfor any in . We also note that is a mean if and only if . Each probability measure in is a mean on if we put , for any in . An application of Hahn-Banach separation theorem shows that is weak dense in the set of all means on .

Under point-wise operations and the supremum norm, becomes a Banach algebra. Arens product can thus be defined in . In particular, we have the following defining formulas for any in , in , and in :

This product induces a multiplication in via the identification . Since is a set of measures beside being the continuous dual of , this multiplication in is richer in content than just a generic Arens product in the second dual of a Banach algebra, and it is different from the point-wise multiplication in .

For in , we denote the multiplication of and by . In [2], it is shown that is defined via the following three steps.(a) For any and , the measure is defined by(b) For any and , the measure is defined by(c) For any , the functional is defined by We can conclude that becomes a commutative Banach algebra with an identity [2].

For the topological semigroup , we definewhere , and . Hence, and are the operators defined on onto . A subset of is called a left (right) translation invariant, if for all . It is well known that both and are left and right translation invariants [1]. Let be a topological semigroup, which for each compact subset of and ,is compact. Then, is a left (right) translation invariant.

Let be a left (right) translation invariant subspace of containing the constant function . A mean on is called a left (right) invariant, iffor every and [1]. If has a left invariant mean, then is said to be left amenable [3]. If has a multiplicative left-invariant mean, then is said to be extremely left amenable (see [4, 5] for more details).

Suppose that is a locally compact semigroup, then for , the convolution is defined bywhere . Hence, with a convolution as multiplication is a Banach algebra.

Now, for and , the linear functional is defined byWe denote by . Similarly, the is defined by

A mean on is called left invariant (LIM) if for all and for all . Also, a mean on is called topological left invariant (TLIM) if for all and for all . A topological left invariant mean on is called a multiplicative topological left-invariant mean (MTLIM) if for all . If there is an MTLIM on , we say that is extremely topological left amenable (ETLA). For results concerning ETLA and ELA semigroups, see [1, 6].

In this paper, we demonstrate that the Arens product and multiplication on defined by (1.3), (1.4), and (1.5) are associative (see Lemma 2.4). In [7], it is proved thatis valid, for all and . This means that Arens product distributes over multiplication on from right, for all and . Note that the multiplication in is different from the point-wise multiplication in . We show that Arens product distributes over multiplication on from left, when , and is a Dirac measure (see Lemma 2.2(ii)). Also, it is shown that if is a locally compact semigroup with a right identity and Arens product distributes from left over multiplication , then must be a Dirac measure (see Theorem 3.1). In the rest of this paper, we give some characterizations on ETLA of locally compact semigroups.

2. Preliminaries

In this section, we offer some results which are useful in the sequel. For more details, refer to [1, 2, 8]. Let be the total variation of , where and are the quotient Banach algebra with a quotient norm ; is the closed ideal of consisting of all locally -null functions. Consider the product linear space

An element is called a generalized function on , if the following conditions are satisfied:(a),(b)for in with , we have -a.e. Let be the linear space of all generalized functions on . It is known that is a Banach space with the norm defined by the formula (a) and that via the isometric Banach space isomorphism, , where for any in and in (see [8, 9]). A function in can be treated as an element in with for all in . The space is thus a subspace of .

For , and , we define and in by

It is shown that [8]. If , then the above equalities hold everywhere, and and are in . Also, if and , thenHence, and belong to .

Lemma 2.1. The map defined by for any in and in satisfies the following statements.(i) For any and ,(ii) For any and ,

Proof. We have for any [8]. Hence,Thus, . Similarly, . This proves (i). From (i) and (2.4), part of (ii) is trivial.

Lemma 2.2. For each and , we have(i)(ii)

Proof. (i) For each , from (2.3), we haveBut, for , from (1.4) and (1.9), we have Hence, by the Riesz representation theorem, . Thus,Therefore, .
(ii) For each , equality (2.4) implies thatNow, for , from (1.4) and (1.9), we obtain Hence, by the Riesz representation theorem, . ThusTherefore, .

Remark 2.3. (a) In the proof of Lemma 2.2, we use the equalities and . For , we have Hence, by the Riesz representation theorem, . Similarly, .
(b) The statement (i) of Lemma 2.2 has a general form as replacing a Dirac measure by [7]. It is natural to ask for which in , the equality  is valid?
Now, we demonstrate that the multiplication on defined by (1.3), (1.4), and (1.5) is associative.

Lemma 2.4. The multiplication defined by (1.3), (1.4), and (1.5) on is associative.

Proof. We know that the Arens product is associative [3, Lemma 1, page 527]. Let be isometric order-preserving linear space isomorphism in [1, Theorem 14.10, page 170], namely, for any and ,Now, let , , and , then (1.3) implies thatThus, . Also, from (1.4), we haveHence, . Also, from (1.5), we haveTherefore, . Now, for any ,So, , and thus the multiplication of is associative.  

Remark 2.5. We note that one can go through a process analogous to Day's proof [3] and establish the associativity of via the demonstration of the following identities one by one.(i) For any and ,(ii) For any , and ,(iii) For any and ,(iv) For any ,

The proofs of (i), (ii), and (iii) use the Riesz representation theorem and the relations (1.3), (1.4), and (1.5). The proof of (iv) follows from (iii) using definition.

3. Main Results

Each probability measure in is a mean on , if we put for any in . We give a partial answer to the question: For which , is the equality  valid?

Let , from the isometric Banach space isomorphism , we have which is in , where , for any in . For and we haveTherefore, . In particular, and so . In view of (1.4), if and , thenHence, if and , thenAlso, since , we haveand hence, whenever .

Theorem 3.1. Let be a locally compact semigroup with a right identity and that . If for any , then is a Dirac measure.

Proof. For , we haveThus, for any , from (3.6), we haveNow, let be a right identity of , that is, for any , then for any , we haveHence, for each ,In (3.9), we put , then for any ,so for each ,and by Holder's inequality, there exist real numbers and , not being zero, such that
Now, if and are the disjoint compact subsets of with and , by the Urysohn's lemma, there exist and in such thatBut from (3.12) and , there is such thatSo, . Also, follows that there is , such thatand therefore . This contradicts the fact that and are not both zero. Hence, if is a compact subset of with and is another compact subset of disjointed from , then we must have . Therefore, , that is, . This proves that if is a compact subset , then either or .
Now, the regularity of follows that for each Borel subset of , or . Hence, either or the measure is a Dirac measure, say [2].
Now, put , we haveand so . Thus, .  

Remark 3.2. If is a discrete semigroup, then , and so [1]. In this case, the multiplication on is just the point-wise multiplication as in . Let be the right identity of , thensince both and are in . Hence, is multiplicative, if the condition of Theorem 3.1 is satisfied. Therefore, must be either or a Dirac measure. But, when is a topological semigroup, the multiplication in defined by (1.3), (1.4), and (1.5) is just a generic Arens product in the second dual of a Banach algebra, which is different from the point-wise multiplication.

It is known that is weak dense in the set of all means on . We give some characterizations theorems for the extreme amenability of locally compact semigroup.

Lemma 3.3. Let be TLA. The following statements are equivalent:(i) is ETLA,(ii) for every and , there exists a mean on such that ,(iii) for every and , there exists a mean on such that ,(iv) for every and , there exists a mean on such that .

Proof. are obvious.
Suppose that and . For by (iv), there exists a mean on such thatand to expand the right-hand side, we getSince is topological left invariant, hence, . Therefore, is ETLA.  

Theorem 3.4. Let be a topological left invariant mean on . The following statements are equivalent:(i) is a multiplicative,(ii) there exists a net in such that for any in and in ,

Proof. Let be a multiplicative topological left invariant mean on . By Lemma 3.3, for any and , Let , thenWe haveSo,Thus,
Note that we apply the commutativity of in . Since is a mean on and is weak dense in the set of all means on , hence, there exists a net in such that in . Now for ,Thus,that is,
Since is a topological left invariant mean on , there exists a net in such that in . If ,Therefore, , that is, is extremely topological left amenable (ETLA).

Lemma 3.5. If is a multiplicative topological left invariant mean on , then there is a net in such that for any in and in ,

Proof. We consider with the norm topology. Let with the product of the norm topologies, where is the set theoretic cartesian product. Then, is a locally convex topological vector space [10]. Now, by Theorem 3.4 corresponding to , there exists a net in such that for any in and in ,We define a linear map byfor all . Hence,that is, in the product of weak topologies [10]. Therefore, lies in the weak closure of the convex set , and so is in the closure of in the original topology of . So, there is a net in such that for all ,that is,and the proof is complete.

Theorem 3.6. Let be a locally compact semigroup. The following statements are equivalent:(i) is extremely topological left amenable,(ii) there exists a net in such that for any in and in ,(iii) there exists a net in such that for any in and in ,

Proof. Let be a multiplicative left invariant mean on . Theorem 3.4 implies that there exists a net in such that for any in and in ,By Lemma 3.5, there exists a net in such that for any in and in ,Without the loss of generality, we may assume that for some mean in . Therefore, for any in and in , we haveIn (3.41), we put , then Also, for and in ,and for and in ,Therefore, for any in , we haveNow, from (3.30) for , we getAlso, let in and be given. Sinceit follows from (3.30) that for any in ,Now fix an arbitrary . This together with (3.46) implies that there exists a such that Also, we may assume thatConsequently, Obviously, .
. Since is weak dense in the set of all means on , by passing to a subnet if necessary, we may assume that weakly in for some mean . Thus, the assertion of (3.37) implies that is a topological left invariant mean. Also, (3.38) implies that is multiplicative because for any in and in ,Therefore, , that is, is extremely left amenable.

Remark 3.7. The conclusions of Theorem 3.6 are different from the classical characterizations of extremely left amenable discrete semigroups [4, Theorem 2]. This difference in the two situations is that any multiplicative mean on is the weak limit of evaluation functionals, while taking weak limits of all convergent nets of Dirac measures in does not exhaust all multiplicative means on [2, Theorem 2.7].

Theorem 3.8. Let be a locally compact semigroup. Define a function byThen,(i) is bounded and linear,(ii)(iii) whenever (iv) for all and in (v) for all and  

Proof. , and are obvious.
For any , we haveIn the final equality, we use the fact that multiplication in is a point-wise multiplication, see Remark 3.2 of Theorem 3.1.
(v) Let and , thenSo, .  

Remark 3.9. From Theorem 3.8, it follows that the map carries means to means, multiplicative means to multiplicative means, left invariant means to left invariant means, and multiplicative left invariant means to multiplicative left invariant means. But does not carry a type of means in onto the same type of means in . Indeed, if is a multiplicative topological left invariant mean which is not weak limit of all convergent nets of Dirac measures in , then does not belong to , where is the set of all means on .