International Journal of Mathematics and Mathematical Sciences

Volume 2010, Article ID 714534, 38 pages

http://dx.doi.org/10.1155/2010/714534

## Benjamin-Ono Equation on a Half-Line

^{1}Department of Mathematics, Graduate School of Science, Osaka University, Osaka, Toyonaka 560-0043, Japan^{2}Instituto de Matemáticas, UNAM, Campus Morelia, AP 61-3 (Xangari), Morelia, CP 58089 Michoacán, Mexico

Received 18 September 2009; Accepted 28 January 2010

Academic Editor: Michael Tom

Copyright © 2010 Nakao Hayashi and Elena I. Kaikina. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

#### Abstract

We consider the initial-boundary value problem for Benjamin-Ono equation on a half-line. We study traditionally important problems of the theory of nonlinear partial differential equations, such as global in time existence of solutions to the initial-boundary value problem and the asymptotic behavior of solutions for large time.

#### 1. Introduction

In this paper we study the large time asymptotic behavior of solutions to the initial-boundary value problem for the Benjamin-Ono equation on a half-line:

where is the Hilbert transformation, and means the principal value of the singular integral. We note that in the case of the whole line we have the relations since the operator can be written as follows: where is the usual Fourier transform, and denotes the inverse Fourier transform. This equation is of great interest in many areas of Physics (see [1, 2]). The Cauchy problem (1.1) was studied by many authors. The existence of solutions in the usual Sobolev spaces was proved in [3–9] and the smoothing properties of solutions were studied in [10–14]. In paper [15] it was proved that for small initial data in solutions decay as in norm at the same rate as for the case of the linear Benjamin-Ono equation, where

The initial-boundary value problem (1.1) plays an important role in the contemporary mathematical physics. For the general theory of nonlinear equations on a half-line we refer to the book [16], where it was developed systematically a general theory of the initial-boundary value problems for nonlinear evolution equations with pseudodifferential operators on a half-line, where pseudodifferential operator on a half-line was introduced by virtue of the inverse Laplace transformation of the product of the symbol which is analytic in the right complex half-plane, and the Laplace transform of the derivative . Thus, for example, in the case of we get the following definition of the fractional derivative

Here and below is the main branch of the complex analytic function in the complex half-plane , so that (we make a cut along the negative real axis Note that due to the analyticity of for all the inverse Laplace transform gives us the function which is equal to for all In spite of the importance and actuality there are few results about the initial-boundary value problem for pseudodifferential equations with nonanalytic symbols. For example, in paper [17] there was considered the case of rational symbol which have some poles in the right complex half-plane. There was proposed a new method for constructing the Green operator based on the introduction of some necessary condition at the singularity points of the symbol . In the paper [18] one of the authors considered the initial-boundary value problem for a pseudodifferential equation with symbol and nonlinearity

As far as we know the case of nonanalytic conservative symbols was not studied previously. In the present paper we fill this gap, considering as example the Benjamin-Ono equation (1.1) with a symbol . There are many natural open questions which we need to study. First we consider the following question: how many boundary data we should pose on problem (1.1) for its correct solvability? Also we study traditionally important problems of a theory of nonlinear partial differential equations, such as global in time existence of solutions to the initial-boundary value problem and the asymptotic behavior of solutions for large time. We adopt here the approach of book [16] based on the estimates of the Green function. The main difficulty for nonlocal equation (1.1) on a half-line is that the symbol is non analytic in the complex plane. Therefore we cannot apply the Laplace theory directly. To construct Green operator we proposed a new method based on the integral representation for sectionally analytic function and theory of singular integrodifferential equations with Hilbert kernel and the discontinues coefficients (see [18, 19]).

To state precisely the results of the present paper we give some notations. We denote . Direct Laplace transformation is

and the inverse Laplace transformation is defined by

Weighted Lebesgue space is where

for , and

Sobolev space is

We define a linear functional :

Now we state the main results.

Theorem 1.1. *Suppose that the initial data with are such that the norm
**
is sufficiently small. Then there exists a unique global solution
**
to the initial-boundary value problem (1.1). Moreover the following asymptotic is valid in **
for , where is defined below by the formula (2.191), and the constant
*

*Remark 1.2. *Note that the time decay rate of the solution is faster comparing with the case of the corresponding Cauchy problem. So the nonlinearity in (1.1) is not the super critical case for our problem.

*Remark 1.3. *In the case of the negative half line we expect that the solutions have an oscillation character, and the time decay rate of the solution is the same as the case of the corresponding Cauchy problem. so the nonlinearity in (1.1) will be the super critical case.

#### 2. Preliminaries

In subsequent consideration we will have frequently to use certain theorems of the theory of functions of complex variable, the statements of which we now quote. The proofs can be found in [19].

Theorem 2.1. *Let be a complex function, which obeys the Hölder condition for all finite and tends to a definite limit as such that for large the following inequality holds:
**
Then Cauchy type integral
**
constitutes a function analytic in the left and right semiplanes. Here and below these functions will be denoted and , respectively. These functions have the limiting values and at all points of imaginary axis , on approaching the contour from the left and from the right, respectively. These limiting values are expressed by Sokhotzki-Plemelj formula:
*

Subtracting and adding the formula (2.3) we obtain the following two equivalent formulas:

which will be frequently employed hereafter.

Theorem 2.2. *An arbitrary function given on the contour , satisfying the Hölder condition, can be uniquely represented in the form
**
where are the boundary values of the analytic functions and the condition holds. These functions are determined by formula
*

Theorem 2.3. *An arbitrary function given on the contour , satisfying the Hölder condition, and having zero index,
**
is uniquely representable as the ratio of the functions and , constituting the boundary values of functions, and analytic in the left and right complex semiplane and having in these domains no zero. These functions are determined to within an arbitrary constant factor and given by formula
*

We consider the following linear initial-boundary value problem on half-line

Setting

where for , we define

where the function is given by formula

for Here and below

and are a left and right limiting values of sectionally analytic function given by

where

All the integrals are understood in the sense of the principal values.

Proposition 2.4. *Let the initial data be . Then there exists a unique solution of the initial-boundary value problem (2.9), which has integral representation
*

*Proof. *To derive an integral representation for the solutions of the problem (2.9) we suppose that there exists a solution of problem (2.9), which is continued by zero outside of :

Let be a function of the complex variable which obeys the Hölder condition for all finite and tends to as We define the operator

Since the operator is defined by a Cauchy type integral, it is readily observed that constitutes a function analytic in the entire complex plane, except for points of the contour of integration . Also by Sokhotzki-Plemelj formula we have for
Here and are limits of as tends to from the left and right semi-plane, respectively.

We have for the Laplace transform
Since is analytic for all we have
Therefore applying the Laplace transform with respect to to problem (2.9) we obtain for
where
We rewrite (2.22) in the form
with some function such that for all
and for
Applying the Laplace transformation with respect to time variable to problem (2.24) we find for
Here the functions and are the Laplace transforms for and with respect to time, respectively. We will find the function using the analytic properties of function in the right-half complex planes Re and We have for
In view of Sokhotzki-Plemelj formula via (2.27) the condition (2.28) can be written as
where the sectionally analytic functions and are given by Cauchy type integrals:
To perform the condition (2.29) in the form of nonhomogeneous Riemann problem we introduce the sectionally analytic function:
where
Taking into account the assumed condition (2.25) and making use of Sokhotzki-Plemelj formula (2.3) we get for limiting values of the functions and
Also observe that from (2.30) and (2.32) by formula (2.4)
Substituting (2.29) and (2.34) into this equation we obtain nonhomogeneous Riemann problem

It is required to find two functions for some fixed point , : , analytic in and , analytic in , which satisfy on the contour the relation (2.36). Here, for some fixed point , , the functions
are called the coefficient and the free term of the Riemann problem, respectively.

Note that bearing in mind formula (2.33) we can find unknown function which involved in the formula (2.27) by the relation
The method for solving the Riemann problem is based on the Theorems 2.2 and 2.3.

In the formulations of Theorems 2.2 and 2.3 the coefficient and the free term of the Riemann problem are required to satisfy the Hölder condition on the contour . This restriction is essential. On the other hand, it is easy to observe that both functions and do not have limiting value as . The principal task now is to get an expression equivalent to the boundary value problem (2.36), such that the conditions of theorems are satisfied. First, let us introduce some notation and let us establish certain auxiliary relationships. Setting
we introduce the function
where for some fixed point ()
We make a cut in the plane from point to point through Owing to the manner of performing the cut the functions , are analytic for and the function is analytic for

We observe that the function given on the contour satisfies the Hölder condition and under the assumption does not vanish for any . Also we have
Therefore in accordance with Theorem 2.3 the function can be represented in the form of the ratio
where
Now we return to the nonhomogeneous Riemann problem (2.36). Multiplying and dividing the expression by and making use of the formula (2.43) we get
where
Replacing in (2.36) the coefficient of the Riemann problem by (2.45) we reduce the nonhomogeneous Riemann problem (2.36) to the form
Now we perform the function given by formula (2.31) as
where
Firstly we calculate the left limiting value Since there exists only one root of equation such that for all therefore, taking limit from the left-hand side of complex plane, by Cauchy theorem we get
The last relation implies that can be expressed by the function which is analytic in
where
By Sokhotzki-Plemelj formula (2.4) we express the left limiting value in the term of the right limiting value as
where
Bearing in mind the representation (2.48) and making use of (2.52), (2.55), and (2.45) after simple transformations we get
where
Replacing in (2.47) by (2.56), we reduce the nonhomogeneous Riemann problem (2.47) in the form
where
In subsequent consideration we will have to use the following property of the limiting values of a Cauchy type integral, the statement of which we now quote. The proofs may be found in [19].Lemma 2.5. *If is a smooth closed contour and a function that satisfies the Hölder condition on , then the limiting values of the Cauchy type integral
**
also satisfy this condition.*

Since satisfies on the Hölder condition, on basis of this Lemma the function also satisfies this condition. Therefore in accordance with Theorem 2.2 it can be uniquely represented in the form of the difference of the functions and , constituting the boundary values of the analytic function , given by formula
Therefore the problem (2.58) takes the form
The last relation indicates that the function analytic in and the function analytic in constitute the analytic continuation of each other through the contour Consequently, they are branches of unique analytic function in the entire plane. According to generalize Liouville theorem this function is some arbitrary constant . Thus, bearing in mind the representations (2.59) and (2.52) we get
Since there exists only one root of equation such that for all therefore, in the expression for the function the factor has a pole in the point . Also the function has a pole in the point Thus in general case the problem (2.36) is insolvable. It is soluble only when the functions and satisfy additional conditions. For analyticity of in points it is necessary that
We reduce (2.64) to the form
Multiplying the last relation by and taking limit we get that This implies that for solubility of the nonhomogeneous problem (2.36) it is necessary and sufficient that the following condition is satisfied:

Therefore, we need to put in the problem (2.9) one boundary data and the rest of boundary data can be found from (2.66). Thus, for example, if we put from (2.66) we obtain for the Laplace transform of
where
Now we prove that the coefficient of does not vanish for all . We represent the function in the form
where
Since, for
making use of analytic properties of the function by Cauchy Theorem we have
where is some fixed point, To calculate the function we will use the identity (2.43). Observe that the function is analytic for all . Therefore, setting the relation (2.43) into definition of and making use of Cauchy Theorem we find
Thus, from (2.72) and (2.73) we obtain the following relation for the function
Substituting this formula into (2.67) we get
Now we return to problem (2.36). From (2.63) under the conditions and (2.75) the limiting values of solution of (2.36) are given by
From (2.76) with the help of the integral representations (2.61) and (2.50), for sectionally analytic functions and , making use of Sokhotzki-Plemelj formula (2.3) and relation (2.45) we can express the difference limiting values of the function in the form
We now proceed to find the unknown function involved in the formula (2.27) for the solution of the problem (2.9). Replacing the difference in the relation (2.38) by formula (2.77) we get
It is easy to observe that is boundary value of the function analytic in the left complex semi-plane and therefore satisfies our basic assumption for all
Having determined the function bearing in mind formula (2.27) and conditions we determine required function
where the function is given by formula (2.55):
Now we prove that, in accordance with last relation, the function constitutes the limiting value of an analytic function in

With the help of the integral representations (2.61), (2.31), and (2.50) for sectionally analytic functions and , and making use of Sokhotzki-Plemelj formula (2.3) we have
Substituting these relations into (2.80) we express the function in the following form:
If it is taken into account that by virtue of the relation (2.45), the last expression agrees with formula
Expressing the function in the last equation in terms of
we arrive at the following relation:
where by virtue of (2.49) and (2.66),
Thus the function is the limiting value of an analytic function in Note the fundamental importance of the proven fact that the solution constitutes an analytic function in and, as a consequence, its inverse Laplace transform vanishes for all We now return to solution of the problem (2.9).

Under assumption the integral representation (2.61) takes form
where is defined by (2.75). Substituting this relation into (2.86) and taking inverse Laplace transform with respect to time and inverse Fourier transform with respect to space variables we obtain
where the function was defined by formula (2.12). Proposition 2.4 is proved.

Now we collect some preliminary estimates of the Green operator . Let the contours be defined as

where can be chosen such that all functions under integration are analytic and for

Lemma 2.6. *The function given by formula (2.12) has the following representation:
**
where
**
The functions were defined in formulas (2.13) and (2.10).*

*Proof. *We rewrite formula (2.12) in the form
where
Here
Firstly we consider the sectionally analytic function given by Cauchy type integral (2.98).

On basis of the definition (2.98) its limiting value can be represent in the form
where
Making use of analytic properties of the functions for and for by Cauchy theorem we have
where is some fixed point,

To calculate the function we will use the following identity:
Observe that the function is analytic for all Therefore, setting the relation (2.103) into definition of and making use of Cauchy theorem we find
Thus from (2.102) and (2.104) we obtain the following relation:
where
In the same way (see also proof of relation (2.74)) we can prove that
Also we observe that
Inserting into definition (2.96) the expression (2.105) for we obtain the function in the form
Replacing in formula (2.97) the functions and by (2.108) and (2.107), respectively, we reduce the function in the form
Therefore inserting into definition (2.95) expressions (2.109) and (2.110), for and , respectively, we obtain the function in the form
where
Also, note that since
we obtain
So,
where
Using relation
we rewrite last formula in the following form:
On the basis of definitions (2.116) and in accordance with the Sohkotzki-Plemelj formula (2.3) we have
So we get
Now we consider for
Note that is analytic in domain , and and So we get
where
Changing the contour of integration with respect to by Cauchy theorem we get
where