Approximation Algorithm for a System of Pantograph Equations

Table 1

Comparison of the absolute errors for Example 3.1.

𝑡	Exact solution	𝑢1
	𝑢1=𝑒^𝑡	𝑛=2	𝑛=4	𝑛=6
0.2	1.221403	3.240𝐸−3	1.210𝐸−5	1.254E−7
0.4	1.491825	5.401𝐸−2	4.238𝐸−4	3.170𝐸−6
0.6	1.822119	1.099𝐸−1	3.499𝐸−3	5.583E−5
0.8	2.225541	2.878𝐸−1	1.594𝐸−2	4.460E−4
1.0	2.718282	6.171𝐸−1	5.236𝐸−2	2.259E−3
	𝑢2=𝑒^−𝑡	𝑢2
		𝑛=2	𝑛=4	𝑛=6
0.2	8.187308𝐸−1	1.179𝐸−2	5.219𝐸−5	7.807𝐸−8
0.4	6.703201𝐸−1	9.414𝐸−2	1.668𝐸−3	1.310𝐸−5
0.6	5.488116𝐸−1	3.179𝐸−1	1.266𝐸−2	2.227𝐸−4
0.8	4.493290𝐸−1	7.558𝐸−1	5.338𝐸−2	1.668𝐸−3
1.0	3.678794𝐸−1	1.484𝐸+0	1.632𝐸−1	7.956𝐸−3