Interval Continuous Plant Identification from Value Sets

Table 2

Results of the algorithm for the value set at frequency 𝜔=1.0.

	𝑣1−𝑣2 arc		𝑣3	𝑣4	𝑣5	𝑣6	𝑣7
			0.8000 + 10.4000j	−4.8000 + 7.6000j	−3.5862 + 1.0345j	−2.5517 + 0.6207j	−1.3443 + 1.2131j	Kharitonov rectangles calculated
𝑣1	1.5676 + 2.5946j	Theorem; applied	Theorem 4.5	Theorem 4.5	Theorem 4.3	Theorem 4.5	Theorem 4.3	𝑘𝑛1𝑗𝜔=−0.6508−1.0847𝑗
𝑣2	2.0000 + 8.0000j	𝑣𝑥pred	2.0000 + 8.0000j	10.0000j	−4.8000 + 7.6000j	−3.5862 + 1.0345j	−2.5517 + 0.6207j	𝑘𝑛2𝑗𝜔=0.1085−1.0847𝑗
𝑣2succ	0.8000 + 10.4000j	𝑣𝑥succ	10.0000j	−3.5862 + 1.0345j	−2.5517 + 0.6207j	−1.3443 + 1.2131j	2.3336j	𝑘𝑛3𝑗𝜔=0.1085−0.7592𝑗
𝑣1pred	0 + 2.3336j	𝜑𝐴𝑥	210.97	174.29	174.29	261.87	261.87	𝑘𝑛4𝑗𝜔=−0.6508−0.7592𝑗
𝜑𝑛1	229.40	Condition; verified	Theorem 4.5(C1)	Theorem 4.5(C1)	Theorem 4.3(C3)	Theorem 4.5(C3)	Theorem 4.3(C4)	𝑘𝑑1𝑗𝜔=−0.3254+0.0542𝑗
𝑛1	−0.6508 − 0.7592j	𝑛𝑥	−0.6508 − 1.0846j	0.1084 − 1.0847j	0.1085 − 1.0846j	0.1085 − 0.7592j	0.1085 − 0.7592j	𝑘𝑑2𝑗𝜔=−0.1085+0.0542𝑗
𝑑1	−0.3254 + 0.0542j	𝑑𝑥	−0.1085 + 0.0542j	−0.1085 + 0.0542j	−0.1085 + 0.2712j	−0.1085 + 0.2712j	−0.3254 + 0.2712j	𝑘𝑑3𝑗𝜔=−0.1085+0.2712𝑗
𝑑2	−0.1085 + 0.0542j	𝑣𝑥	𝑛2/𝑑2	𝑛3/𝑑2	𝑛3/𝑑3	𝑛4/𝑑3	𝑛4/𝑑4	𝑘𝑑4𝑗𝜔=−0.3254+0.2712𝑗
𝑛4𝜆	−0.1266 − 0.7594j
𝑛2𝜆	−0.6508 − 1.0846j