Iterative Method for Solving the Second Boundary Value Problem for Biharmonic-Type Equation

<table>Solution in the case of <svg height="11.1" id="M671" style="vertical-align:-0.17555pt" version="1.1" viewbox="0 0 46.900002 11.1" width="46.900002" xmlns="http://www.w3.org/2000/svg">
<g transform="matrix(1.25,0,0,-1.25,0,11.1)">
<g transform="translate(72,-63.12)">
<text transform="matrix(1,0,0,-1,-71.95,63.35)">
<tspan style="font-size: 12.50px; " x="0" y="0">𝑎</tspan>
<tspan style="font-size: 12.50px; " x="9.7398367" y="0">=</tspan>
<tspan style="font-size: 12.50px; " x="21.780226" y="0">0</tspan>
<tspan style="font-size: 12.50px; " x="28.031727" y="0">.</tspan>
<tspan style="font-size: 12.50px; " x="31.157476" y="0">5</tspan>
</text>
</g>
</g>
</svg> and <svg height="10.8625" id="M672" style="vertical-align:-0.13794pt" version="1.1" viewbox="0 0 34.674999 10.8625" width="34.674999" xmlns="http://www.w3.org/2000/svg">
<g transform="matrix(1.25,0,0,-1.25,0,10.8625)">
<g transform="translate(72,-63.31)">
<text transform="matrix(1,0,0,-1,-71.95,63.5)">
<tspan style="font-size: 12.50px; " x="0" y="0">𝑏</tspan>
<tspan style="font-size: 12.50px; " x="9.3397408" y="0">=</tspan>
<tspan style="font-size: 12.50px; " x="21.380131" y="0">1</tspan>
</text>
</g>
</g>
</svg>.</table>

Journal of Applied Mathematics

fig2

Figure 2

Figure 2: Iterative Method for Solving the Second Boundary Value Problem for Biharmonic-Type Equation 