Research Article

Differential Quadrature Solution of Hyperbolic Telegraph Equation

Table 2

RMS errors for Problem 1 with Δ 𝑡 = 0 . 2 5 using PDQ with Neumann boundary conditions.

𝑡 𝑁 = 1 1 𝑁 = 1 3 𝑁 = 1 7

0.5 2 . 8 2 𝑒 0 5 7 . 7 4 𝑒 0 7 2 . 2 6 𝑒 1 0
1 1 . 5 2 𝑒 0 5 3 . 7 8 𝑒 0 7 1 . 4 5 𝑒 1 0
2 4 . 4 4 𝑒 0 6 1 . 4 1 𝑒 0 7 8 . 3 2 𝑒 1 1
3 3 . 0 9 𝑒 0 6 7 . 6 3 𝑒 0 8 5 . 7 2 𝑒 1 1