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Journal of Applied Mathematics
/
2012
/
Article
/
Tab 2
/
Research Article
Differential Quadrature Solution of Hyperbolic Telegraph Equation
Table 2
RMS errors for Problem 1 with
Δ
𝑡
=
0
.
2
5
using PDQ with Neumann boundary conditions.
𝑡
𝑁
=
1
1
𝑁
=
1
3
𝑁
=
1
7
0.5
2
.
8
2
𝑒
−
0
5
7
.
7
4
𝑒
−
0
7
2
.
2
6
𝑒
−
1
0
1
1
.
5
2
𝑒
−
0
5
3
.
7
8
𝑒
−
0
7
1
.
4
5
𝑒
−
1
0
2
4
.
4
4
𝑒
−
0
6
1
.
4
1
𝑒
−
0
7
8
.
3
2
𝑒
−
1
1
3
3
.
0
9
𝑒
−
0
6
7
.
6
3
𝑒
−
0
8
5
.
7
2
𝑒
−
1
1