Journal of Applied Mathematics

Research Article

Differential Quadrature Solution of Hyperbolic Telegraph Equation

Table 5

Relative errors of Problem 2 using 𝑁 = 𝑀 = 2 1 using FDQ.
𝑡 Δ 𝑡 = 0 . 2 5 Δ 𝑡 = 0 . 5
0.5 3 . 6 2 𝑒 − 0 9 8 . 9 3 𝑒 − 0 5
1 3 . 6 2 𝑒 − 0 9 6 . 0 3 𝑒 − 0 5
2 3 . 4 3 𝑒 − 0 9 9 . 3 1 𝑒 − 0 5
3 3 . 6 6 𝑒 − 0 9 1 . 1 0 𝑒 − 0 4