A Filled Function Method Dominated by Filter for Nonlinearly Global Optimization

Table 3

Problem 2 for = 10.

1	(6, 6, 6, 6, 6, 6, 6, 6, 6, 6)	(5.9490, 5.9979, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980)	78.4316	(5.2490, 5.9979, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980)
2	(5.2490, 5.9979, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980, 5.9980)	(4.9657, 6.9821, 1.0005, 1.3301, 1.0272, 1.8293, 2.0042, 4.9996, 4.9850, 6.0038)	34.9446	(2.2217, 6.9786, 2.0157, 1.3101, 1.0113, 1.7940, 1.9541, 4.8329, 4.9992, 5.9946)
3	(2.2217, 6.9786, 2.0157, 1.3101, 1.0113, 1.7940, 1.9541, 4.8329, 4.9992, 5.9946)	(2.1040, 6.8602, 2.0072, 0.9162, −0.3235, 1.0357, 1.0372, 0.8575, 3.6559, 5.9685)	23.6598	(1.3172, 4.5326, −2.0782, 0.9559, −0.0656, 0.9771, 1.0218, 1.0527, 3.1821, 5.9918)
4	(1.3172, 4.5326, −2.0782, 0.9559, −0.0656, 0.9771, 1.0218, 1.0527, 3.1821, 5.9918)	(1.0258, 1.7654, 1.9963, 1.0103, −0.5615, 0.9857, 0.6612, 0.0176, 1.0171, 5.4008)	7.7379	(1.1328, 1.3377, 2.0368, 1.0522, −2.0462, 3.0318, 1.0211, 0.2395, 1.1045, 3.0591)
5	(1.1328, 1.3377, 2.0368, 1.0522, −2.0462, 3.0318, 1.0211, 0.2395, 1.1045, 3.0591)	(1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000)		(1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000, 1.0000)