Determining Optimal Replacement Policy with an Availability Constraint via Genetic Algorithms

Table 2

Result of 10 times ().

	Value	Individual	Time (seconds)
1st stop	−2.4950	32	1.6250
2nd stop	−2.4950	32	1.6406
3rd stop	−2.4950	32	1.6406
4th stop	−2.4950	32	1.6406
5th stop	−2.4872	30	1.6563
6th stop	−2.4950	32	1.6719
7th stop	−2.4872	30	1.6875
8th stop	−2.4950	32	1.6719
9th stop	−2.4950	32	1.6875
10th stop	−2.4950	32	1.7031