Diagonal Block Method for Solving Two-Point Boundary Value Problems with Robin Boundary Conditions

Table 1

Comparison of the numerical result for solving Problem 1.

	Error at			Error at
	2PDD4	2PDAM4	DAM4	2PDD4	2PDAM4	DAM4	BP5
1.5708	4.64e-07	2.60e-07	1.49e-06	2.05e-10	2.05e-10	2.05e-10	0.00e+00
1.7279	6.76e-07	5.81e-07	2.37e-07	1.70e-10	1.71e-10	1.71e-10	2.74e-06
1.8850	8.47e-07	8.32e-07	7.10e-07	1.56e-10	1.63e-10	1.63e-10	8.52e-06
2.0420	6.32e-07	7.43e-07	1.11e-06	1.49e-10	1.66e-10	1.69e-10	6.63e-06
2.1991	5.36e-07	6.73e-07	1.39e-06	1.48e-10	1.78e-10	1.91e-10	4.21e-06
2.3562	3.68e-07	6.25e-07	1.56e-06	1.52e-10	2.00e-10	2.29e-10	1.10e-05
2.5133	3.43e-07	5.78e-07	1.62e-06	1.60e-10	2.31e-10	2.86e-10	5.35e-06
2.6704	1.94e-07	5.28e-07	1.59e-06	1.73e-10	2.72e-10	3.65e-10	6.10e-06
2.8274	2.06e-07	4.72e-07	1.45e-06	1.91e-10	3.25e-10	4.68e-10	9.42e-06
2.9845	6.27e-08	3.96e-07	1.18e-06	2.16e-10	3.92e-10	6.03e-10	2.45e-06
3.1416	9.16e-08	3.05e-07	7.81e-07	2.47e-10	4.76e-10	7.76e-10	0.00e+00
AVE	4.42e-07	5.99e-07	1.31e-06	1.75e-10	2.46e-10	3.16e-10	6.27e-06
TS	6	6	10	51	51	100	-
FCN	96	144	96	114	212	114	-
ITN	3	3	3	1	1	1	-
TIME	0.0030	0.0150	0.0310	0.0150	0.0470	0.0470	-