Diagonal Block Method for Solving Two-Point Boundary Value Problems with Robin Boundary Conditions

Table 2

Comparison of the numerical result for solving Problem 2.

	Error at			Error at
	2PDD4	2PDAM4	DAM4	2PDD4	2PDAM4	DAM4
0.00	4.90e-07	3.05e-05	1.84e-07	0.00e+00	0.00e+00	0.00e+00
0.10	2.61e-07	3.04e-05	4.17e-07	5.32e-12	2.79e-11	8.54e-12
0.20	2.63e-08	3.06e-05	6.61e-07	5.87e-12	1.35e-10	2.23e-11
0.30	2.58e-08	3.13e-05	6.76e-07	6.69e-12	3.24e-10	4.57e-11
0.40	9.67e-09	3.21e-05	6.78e-07	7.76e-12	5.88e-10	7.80e-11
0.50	1.30e-08	3.19e-05	6.68e-07	9.08e-12	9.22e-10	1.19e-10
0.60	7.25e-11	3.15e-05	6.46e-07	1.06e-11	1.32e-09	1.68e-10
0.70	6.15e-09	2.99e-05	6.14e-07	1.24e-11	1.79e-09	2.24e-10
0.80	4.33e-09	2.81e-05	5.73e-07	1.44e-11	2.32e-09	2.88e-10
0.90	3.91e-09	2.47e-05	5.22e-07	1.66e-11	2.91e-09	3.59e-10
1.00	4.63e-09	2.11e-05	4.62e-07	1.90e-11	3.56e-09	4.38e-10
AVE	8.44e-08	3.22e-05	6.10e-07	1.01e-11	1.22e-09	1.55e-10
TS	6	6	10	51	51	100
FCN	120	212	88	228	424	228
ITN	4	4	3	2	2	2
TIME	0.015	0.031	0.015	0.031	0.047	0.046