A Numerical Approach Based on Taylor Polynomials for Solving a Class of Nonlinear Differential Equations

Table 1

Absolute error of Example 1 for N = 2, 3, 4, 5 and h = 0.1.

	Absolute errors
	0	0	0	0	0
0.1	3.41836e-04	5.23638e-05	6.01615e-06	4.98080e-07
0.2	2.80552e-03	3.48083e-04	3.31963e-05	2.24337e-06
0.3	9.71762e-03	9.25784e-04	7.15951e-05	3.92686e-06
0.4	2.36494e-02	1.57940e-03	9.86752e-05	4.72833e-06
0.5	4.74425e-02	1.83245e-03	1.05041e-04	5.66754e-06
0.6	8.42376e-02	9.09599e-04	1.22880e-04	8.24884e-06
0.7	1.37505e-01	2.29481e-03	2.57394e-04	1.01147e-05
0.8	2.11082e-01	9.25145e-03	7.21536e-04	2.60625e-06
0.9	3.09206e-01	2.18344e-02	1.87440e-03	6.66051e-05
1	4.36564e-01	4.23636e-02	4.26365e-03	2.56735e-04