Research Article

Optimization of the Supply Chain in the Production of Ethanol from Agricultural Biomass Using Mixed-Integer Linear Programming (MILP): A Case Study

Table 2

Other input parameters.

SourceEntry parametersValue

[55]Cost of annual amortization of construction and operation of storage centers ($/year) = [281,250; 156,250; 406,250; 156,250; 156,250; 156,250; 156,250]
[55]Amount of annual amortization of construction and operation of the biorefinery ($/year)  = [2,437,500; 4,500,000; 2,437,500]
[56]Cost of annual amortization of the construction and operation of the mixing plant ($/year) = [2,191,304.34; 3,286,956.52; 2,191,304.34]
[54, 57]Cost of planting and cultivation of biomass ($/ha) = [238.42, 131.57] (for all ) and  = [288.94, 164.47] (for all ) and
[54, 57]Cost of harvested biomass ($/ha) = [63.15, 31.57] (for all ) and
 = [78.94, 41.05] (for all ) and
[19, 58]Cost of holding biomass units at harvest sites ($/t) = 6.3 (for all )
[19, 58]Cost of holding biomass units in storage centers ($/t) = 4.3 (for all)
[19, 58]Cost of holding biomass units in biorefineries ($/t) = 4.3 (for all )
AssumedCost of holding bioethanol units in the biorefinery ($/L) = 0.015 (for all )
AssumedCost of holding units of bioethanol in mixing plants ($/L) = 0.015 (for all )
[55]Cost of transporting a biomass unit from the harvest site to storage centers ($/t) = 3.85 + 0.085  (for all )
[55]Cost of transporting a biomass unit from the harvest site to biorefineries ($/t) = 3.85 + 0.085  (for all )
[55]Cost of transporting biomass unit storage centers to biorefineries ($/t) = 3.85 + 0.085  (for all )
[55]Cost of transporting a bioethanol unit from biorefineries to mixing plants ($/L × km) = 0.000028 (for all )
[55]Cost of transporting a bioethanol unit from mixing plants to customers ($/L × km) = 0.000028 (for all )
[2, 55]Storage capacity of storage centers (t) = [110000, 200000, 300600]
[55]Bioethanol production capacity of biorefineries (L) = [190, 380, 190] MLPY
AssumedCapacity to store biomass per year in biorefineries (t) = [0, 0, 0] (for all )
[56]Capacity of the mixing plants (L) = [370000000,555000000,370000000] (for all )
AssumedNumber of biorefineries that can be opened = 3, (for all )
AssumedNumber of mixing plants that can be opened = 3, (for all )
[59]Cost per unit of fuel in the period ($/L) = 1.00 (for all )
[2]The processing cost of a biomass unit ($/t) = 48.86 (for all )
AssumedThe proportion of land available at the harvest site = 1.00 (for all )
[58, 60]Reason for deterioration of stored biomass = 0.01 (/t)
[2, 55]Biomass conversion ratio (L/t) = [208.93, 274.9] for all
[55]Demand is the demand that follows a normal distribution with a standard deviation of 15% of the mean
AssumedPercentage destined to store biomass in a biorefinery = 0.26 (for all )