Research Article

On the Effectiveness of Nature-Inspired Metaheuristic Algorithms for Performing Phase Equilibrium Thermodynamic Calculations

Table 2

Details of the phase stability, phase equilibrium, and reactive phase equilibrium problems used in this study.

CodeSystemFeed conditionsThermodynamic modelsGlobal optimum

T7C1 + C2 + C3 + C4 + C5 + C6 + + = (0.7212, 0.09205, 0.04455, 0.03123, 0.01273, 0.01361, 0.07215, 0.01248) at 353 K and 38500 kPaPhase stability problem with SRK EoS with classical mixing rules −0.002688

T8C1 + C2 + C3 + C4 + C4 + C5 + C5 + C6 + = (0.614, 0.10259, 0.04985, 0.008989, 0.02116, 0.00722, 0.01187, 0.01435, 0.16998)
at 314 K and 2010.288 kPa
Phase stability problem with SRK EoS with classical mixing rules −1.486205

T9 + + + + + + + + + = (0.6436, 0.0752, 0.0474, 0.0412, 0.0297, 0.0138, 0.0303, 0.0371, 0.0415, 0.0402) 
at 435.35 K and 19150 kPa
Phase stability problem with SRK EoS with classical mixing rules −0.0000205

G4C1 + H2S = (0.9813, 0.0187)  
at 190 K and 4053 kPa
Phase equilibrium problem with SRK EoS with classical mixing rules −0.019892

G6C2 + C3 + C4 + C5 + C6 = (0.401, 0.293, 0.199, 0.0707, 0.0363)  
at 390 K and 5583 kPa
Phase equilibrium problem with SRK EoS with classical mixing rules −1.183653

G7C1 + C2 + C3 + C4 + C5 + C6 + + = (0.7212, 0.09205, 0.04455, 0.03123, 0.01273, 0.01361, 0.07215, 0.01248) at 353 K and 38500 kPaPhase equilibrium problem with SRK EoS with classical mixing rules −0.838783

G8C1 + C2 + C3 + C4 + C4 + C5 + C5 + C6 + = (0.614, 0.10259, 0.04985, 0.008989, 0.02116, 0.00722, 0.01187, 0.01435, 0.16998)
at 314 K and 2010.288 kPa
Phase equilibrium problem with SRK EoS with classical mixing rules −0.769772

R4A1 + A2 A3 + A4 
(1) Acetic acid
(2) n-Butanol
(3) Water
(4) n-Butyl acetate
= (0.3, 0.4, 0.3, 0.0) at 298.15 K and 101.325 kPaReactive phase equilibrium problem with UNIQUAC model and ideal gas: 
= + 0.8
−1.10630

R7A1 + A2 A3 = (0.52, 0.48, 0.0) at 323.15 K and 101.325 kPaReactive phase equilibrium problem with Margules solution model:  
= 3.5
−0.653756