Predicting the Ultimate Bearing Capacity of Bolts with an Optimized Function Model

Table 7

Model parameters for example 2.

Bolt	AH	CH	IE	IEPF
B1	a = 22.49	a = 9.18	a = 6 × 10^−3	a = 0.20
B2	b = 5.03	b = −0.83	k = −0.98	b = 7.32
	a = 53.24	c = −3.02	a = 1.4 × 10^−3	c = −0.07
	b = 0.66	a = 14.22	k = −0.99	k = −3.38
		b = −5.40		a = 0.16
		c = −0.39		b = 24.76
				c = −0.11
				k = 6.99